Solving Ax=b

MIT 18.06SC Linear Algebra, Fall 2011
View the complete course: ocw.mit.edu/18-06SCF11
CZcams Playlist: • MIT 18.06SC Linear Alg...
Instructor: Martina Balagovic
A teaching assistant works through a problem on solving Ax=b.
License: Creative Commons BY-NC-SA
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[@AnupKumar-wk8ed]

Martina Balagovic! You are an awesome TA.

[@quirkyquester]

Thank you MIT, Thank you Martina! Amazing Example!

[@sanjaypaudel3296]

Love her accent

[@akistsili8574]

Love her at all! A very useful complementary lecture !

[@loucascubeddu]

Great exercise to make us think about the last course! Thanks ocw

[@snakelord8316]

The description should have the link to the whole playlist and that would be super helpful.

[@doruktopcu]

chalk is so tick and it is almost finished... that is how much we need to study too, thanks

[@yiyu9519]

love this lecture

[@roshankannouje4900]

Great presentation

[@Upgradezz]

Thank you :)

[@rachealgiftordu3522]

Thank you 😊💕

[@tanaypatel2266]

Thank you so much

[@surajitbosu8639]

Very nice

[@LoseTheFur]

import sys; A = [1, 2, 3, ...]; x= sys.argv[1]; b = lambda b: b*x; list(map(b, A))

[@edian1895]

Just to clarify: The "special solution" can also be seen as the Span when written in parametric vector form right? p (particular solution) + Span{v1,v2,...,vp}

[@Mathin3D]

Yum yum, gimme some!

[@franciscojavier7103]

Hello in the particular solution how can we get the value of b1 b2 and b3?

[@pz_bowmaking8861]

I just found out that one problem in my home work is exactly the same

[@stevenm3914]

How exactly does she get the x values for the special solution. It almost seems like it just appears.

[@MrJKostyal]

5:25