God I’ve looked all over the internet for something that will explain double integral bounds and not a thing helped until I FINALLY found your video. This is exactly what I needed, thank you 🙏🏻
@@akhilkumar3090 The volume is given by the integral of 1, the integral with respect to z goes from x^2 +1 to y+1 so he basically skips that step and alredy gives us that expression
Because U = y^5 + 1 So the integrals with respect to U are (1)^5+1 And (2)^5+1 Because before it was with respect to y now it it was with respect to U , and U equals the Y value to the power of 5 plus 1. So you just substitute the Y integrals you had and you will get the U definite integrals.
God I’ve looked all over the internet for something that will explain double integral bounds and not a thing helped until I FINALLY found your video. This is exactly what I needed, thank you 🙏🏻
James Hamblin you absolute legend
Thank You for such a great explanation ! keep doing more of these and you will help a whole lot of people. THANKS!
i don't usually leave comments on videos since most of the don't explain anything. but you help me a lot today thanks
finally someone with short video and great explaining
I've had trouble with this for ages, this video is no nonsense and really helped
Just a great explanation. Thank you J.H
you are really good at problem solving and fast ,thank you
Thank you so much!!! This helps a lot for my class. :) ✨
This was super helpful, thank you
U are simply awesome. I do not understand why they do not teach us like that.
because in class no one pays attention. A teacher speaking that fast would be unbearable.
thanks for such amazing and easy explanation
Perfect explication thanks you soo much 💞💞
Nice job. Deserves more likes
very good explanation. thank you so much
thanks, king🙏
step by step in your explanation..
great video💪
best channel thank you
hey thank you from uganda
wow , thank you 1 million time
Thanks alot ❤️
Finally got what i wanted
Thank you
Thanks alot
Nice😍
Thank u so much 😍😍 but I had question why in the last problem in 9.42 the function that u integral is y+1-(x²+1) ???
I have the same question, i think its bcoz we already have dx and dy terms, so we need some kind of dz
@@akhilkumar3090 The volume is given by the integral of 1, the integral with respect to z goes from x^2 +1 to y+1 so he basically skips that step and alredy gives us that expression
you must explain how you have drawn the surfaces z=y+1 and……
so this is not math
how did you get the limit 33 to 1 ? can someone explain to me?
Because U = y^5 + 1
So the integrals with respect to U are
(1)^5+1
And
(2)^5+1
Because before it was with respect to y now it it was with respect to U , and U equals the Y value to the power of 5 plus 1.
So you just substitute the Y integrals you had and you will get the U definite integrals.
hamblin hamblin mcgill
what is this chicanery
😊😊😊😊😊😊😊ppppppm
P
Thank you