Find the Equation of the Tangent Plane to z = sqrt(4 - x^2 - 2y^2) at (1, -1, 1)
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- čas přidán 17. 10. 2022
- Find the Equation of the Tangent Plane to z = sqrt(4 - x^2 - 2y^2) at (1, -1, 1). This is a Calculus 3 problem.
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Thank you:)
Thanks Sir useful problem.
You deserve more than 100 million subscribers 😌😌
Hey bro. How are you?
I have to agree that solving math problems is ALWAYS more comfortable/better with a pencil.. 👍 The cherry on the top would be if its an ORIOLE brand pencil.. ✏🤝🤣
Please I have a question
Find the equation tangent plane to the surface
Z=8/√(x^2+y^2+z^2-2) -4 at the point p=(2,1,1)
I like the paper format
Thank you! I like to do both the tablet and paper, it's fun to mix it up! I need to get another whiteboard:)
First 🥇🥇