Video není dostupné.
Omlouváme se.

Deloitte Interview experience Java Developer 2+ years experience

Sdílet
Vložit
  • čas přidán 13. 09. 2023
  • Java Developer Interview Questions and Answers 2+ years of experience in Deloitte company
    Deloitte's first round question and answer
    How to give a first-round interview
    How to face the interview
    How to give proper questions and answer as a java developer
    java interview questions and answers
    java 8 features
    java interview questions
    java interview
    stream api in java 8
    java interview questions and answers for freshers
    Deloitte interview
    Deloitte interview 2023
    Deloitte interview questions and answers
    Deloitte interview questions and answers for freshers
    Deloitte interview question
    Deloitte interview expriencs
    Deloitte interview expriencs 2023
    Deloitte interview for fresher
    Deloitte interview process experienced
    Deloitte interview preparation
    Deloitte interview preparation 2022
    Deloitte interview process for freshers
    java interview
    java interview questions
    java interview questions and answers
    java developer interview questions
    java developer interview
    java developer interview questions and answers,
    This video is educational. I humbly request to you please don't give the wrong comment.
    #interview #deloitte #java #javaprogramming

Komentáře • 23

  • @abhijitkarmakar6328
    @abhijitkarmakar6328 Před 9 měsíci +3

    In the first coding question, he using array hashing and character ASCII value, since it was mentioned that we only have lowercase characters, so the person created a array of size 26 to denote the each character index values. He was substracting a because ASCII range for 65-90(a-z), so the hash array would look something like int [] hashArray = {0,0,0,......0} , 26 zeros on each index. Now when he gets the index of each char by substracting a. For example if we want index of b, it will be 66-65 = 1 and then incrementing the value at that index, after computation he would have an array in which index have count of the characters.
    Now he could easily iterate through the array for each character and find if count of the char is 1 then return the index else if not found return -1;

  • @HanilKumarMuchu
    @HanilKumarMuchu Před 5 měsíci +1

    public class Practise {
    public static int method1(String str) {
    String s1=str;
    int count=0;
    int num=0;
    for(int i=0;i

  • @raghavendrac1053
    @raghavendrac1053 Před 5 měsíci

    Can you please make vedio on Deloitte techno manegeral round for java developers

  • @user-gt6xk2pk4i
    @user-gt6xk2pk4i Před 9 měsíci +1

    Use Streams if you are using 1.8

  • @sanjaykumarray149
    @sanjaykumarray149 Před 3 měsíci

    How many rounds of interview you had buddy?

  • @ayushsahu3983
    @ayushsahu3983 Před 9 měsíci

    How much package you had got from deloitte after 2 years exp.

  • @ChandanKumar-xd1tg
    @ChandanKumar-xd1tg Před 10 měsíci

    Current interview Questions??

  • @funtube7444
    @funtube7444 Před 3 měsíci

    Bro is using chatgpt😂

  • @avaneetagrahari4502
    @avaneetagrahari4502 Před 9 měsíci

    He got selected or not?

  • @ronaldo76544
    @ronaldo76544 Před 10 měsíci +2

    This is real interview of Deloitte?

  • @ManishWorkspace
    @ManishWorkspace Před 9 měsíci +3

    this is first question of answer
    String sentence = "abcdcaf";
    for (int i = 0; i < sentence.length(); i++) {
    int count = 0;
    for (int j = 0; j < sentence.length(); j++) {
    if (sentence.charAt(i) == sentence.charAt(j)) {
    count = count + 1;
    }
    }
    if (count == 1) {
    System.out.println(sentence.charAt(i));
    break;
    }
    }

  • @divyanshkaushik6265
    @divyanshkaushik6265 Před měsícem

    public class FirstNonRepeatingCharacter {
    public static int firstNonRepeatingCharacter(String str) {
    Map frequencyMap = str.chars()
    .mapToObj(c -> (char) c)
    .collect(Collectors.groupingBy(c -> c, LinkedHashMap::new, Collectors.counting()));
    Optional firstNonRepeatingChar = frequencyMap.entrySet()
    .stream()
    .filter(entry -> entry.getValue() == 1)
    .map(Map.Entry::getKey)
    .findFirst();
    return firstNonRepeatingChar.map(c -> str.indexOf(c)).orElse(-1);
    }
    public static void main(String[] args) {
    String input = "abcdcafb";
    int result = firstNonRepeatingCharacter(input);
    System.out.println(result);
    }
    }