Uniformly Distributed Load (UDL): Shear Force and Bending Moment Diagram [SFD BMD Problem 4]

[@VadhelDharmesh]

Very useful and good understanding ❤

[@md.hasanuzzamanjihad4623]

Great and easiest explanation... Thanks bro. Pls upload more videos on SFD and BMD problem solving

[@FilmonAron-qx4gg]

Thank you so much for the clear explanation!

[@ifinfotech]

Glad it was helpful!

[@olivergrennan309]

your the goat

[@charukadilshan4599]

Great Teaching

[@AnanyaAugustine]

Thank you for the detailed explanation

[@ifinfotech]

You are welcome!

[@gabrielatem1121]

Much appreciated your explanation❤

[@user-eq1ih2oc9p]

Great video, have being trying to understand udl and your video helped me a lot, much love from Kenya 🇰🇪

[@user-sc2zw8tl6z]

Thank you so much

[@satazer5824]

Perfect method. Thank you.

[@ifinfotech]

You're welcome!

[@user-zw2qq8gx1r]

你超猛的,聽不懂你的語言我卻看得懂整個分布圖,

[@strdpra0z]

Sir when you find out moment of udl that time 8×4×(4÷2) +5×5=Rb×6 hona chahiye

[@prashanthakumar4573]

how did you get Rb value 5.86kn

[@mahendratripura800]

41/7

[@baiklahtu]

Sorry sir, SFdr for SF diagram should be - 4.14 or - 5.86?

[@gabrielatem1121]

Could you clarify how length x=3.57 become force at maximum point E?

[@aqsanazir4819]

Same question

[@zyler548]

Look back 10 Standard Maths Similarity of Triangles

[@kenken578]

Can you also do for moving loads, and triangular loads example? Thank you.

[@gluton07]

while taking moment at E its length is 3.57, doesnt the point load 8 kN will be counted as Moment at E = 7.14*3.57-2*3.57²/2-8*1.57 ??

[@Rahulterabhaisabsebhar.i]

Bro 8 KN is UDL and 3.57 is also udl but 3.57 is part of 8 hence we will neglect it because we Have created Individual Udl of that

[@patilgouda]

How Rb =5.86kn

[@swasthik.B]

41/7

[@kerinekylie]

There's something wrong here

[@richardrichard886]

💩