LEC 26 Uniqueness Theorem for charge free region | HC VERMA | GDS K S
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- čas přidán 29. 11. 2020
- #HcVerma #ClassicalElectromagnetism #Gdsks #PhysicsTutorials
HC VERMA
Coulomb's law and its limitation, Electrostatic charge distribution, Linear, surface, and volume charge distributions. Use of Dirac delta function to describe point charges, linear charges and surface charges, vector expressions for electric field due to different kinds of charge distributions.
Spherical and Cylindrical coordinates, line element, surface element, and volume element. Evaluation of electric field using such coordinate systems.
Gauss's law in differential form, Concept of divergence, Expressions in Cartesian, spherical and cylindrical coordinates, Evaluation of charge density from the electric field, Integral form of Gauss's law, calculation of electric field for planer, spherically and cylindrically symmetric charge distributions.
Electric potential energy and potential, Concepts of Curl and gradient, Relation between E and V, Potential due to a continuous charge distribution, Energy in an electric field, Boundary conditions on the electric field across a surface.
Multipole expansion of potential. Monopole, Electric dipole moment, Field due to a dipole, force, and torque due to E-field on a dipole, Quadrupole moment of a charge distribution.
Charge distribution on conductors, Cavities in a conductor, capacitors.
Laplace and Poisson's equations, Properties of solutions of Laplace equation, Uniqueness theorems.
Method of images, general theory, charge in front of conductors of different shapes.
Dielectrics, Polarization P in a dielectric, Bound and free charges, Relation with polarization, Electric
field due to a uniformly polarized sphere, Electrical susceptibility.
Displacement vector D, Gauss's law in terms of D, Boundary conditions on D.
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Easy explanation of Griffith's Classical ED. Much obliged to Prof. HC Verma.
agreed :D i mean my dumb mind needs someone to explain me the text of griffith's 😭😭
@@icant_thinkbetter lmfao +1 man
This is the only platform on youtube where I found the correct proof of uniqueness theorem. Hats off to the genius proff, our inspiration HCV.
I was not able to understand ' UNIQUENESS THEOREM ' in such depth before . HC VERMA SIR is the best . Please keep up the philanthropic work for the student community sir!!!!
You are superb sir! Kanpur is lucky to have u.
How easily he can explain everything is just unmatchable ❤️
Aag laga di Sir!!🔥🔥
Superb explanation.
Love u sir! Always
Sir thank you very much..... this video has helped me to clear my confution beautifully.
Thankyou so much sir 🙏🙏
You put a lot in my pot
Really awesome explanation sir.. really luved it veryyyyyyy much ❤️.. I really understood it in depth and enjoyed it a lot .. thanq vryyyyyyy much sir 🎊❤️💕😍
Amazing sir 👍👍🧡🧡
Your are inspiring to all of us ..
Thank you so much sir🙏
Awesome explanation sir....🙂
Such a great explanation sir 👌👌👌👌👌
THANK YOU SO MUCH SIR 💗🙏🤩
🙏🙏nice video
Thank you sir ji......❤️😊😊
You deserve 1 million sir
Thank u vry much sir
Thanks sir
Feel agaya ❤
Thank you so much sir lectures hindi me banane k liye
Sir make a vedio on liouvilles theorm msc physics
Sir, how can we prove the uniqueness theorem for anisotropic material??
thanku sir
flawless explanation.
As you have watched the lecture 3 months ago so can you help me with a doubt. As sir have said in the last lecture Take any range the average of value of the function at the boundaries is equal to the value of the function at the middle of the range. So, In case of a uniformly charged solid sphere if we take a range from 2R to 6R then why the average of potential at 2R and 6R is not equal to value of potential at 4R??? Plzz help.
@@ranbirbarman548 are you taking about harmonic function?
Well, If you are. Then these three must give the same results, actually it has no dependence on radius because if for a moment you think of a circle and you increase it's radius the circumference will also increase and if you take its radio it will give you a contact value i.e 2π, same logic can you take here for the potential.
@@hikmatullahpakhtoon3694 Then how can you say that in any range the average of the value of the solution laplace eqn at the boundaries give the same value at the middle of the range?
@@ranbirbarman548 vro when I solved it the answer came equal toh (q/(4(pi)€ *4r) *ln(3)) . And since value of ln3 is 1.098 so it's very close to actual average
11th and 12th mey, aapki book tho mey ney, pada nahi. But, lectures tho zarur dekhungaa
❤
14:33
Sir is this for jee advanced
Sir why to consider only this function V3=V1-V2. Instead can't we consider V3=αV1+βV2
It still satisfies Laplace equation.
And now it's value at surface is (α+β)Vs
But at surface it should be Vs so to take this into consideration we put condition that V3 is a possible function for which (α+β) =1
V3=α(V1-V2)+V2
Which satisfies both Laplace equation as well as potential Vs on surface
@@SidsrozxYtforCercube how?
Thanks sir
Thanks sir