How To Solve Any Resistors In Series and Parallel Combination Circuit Problems in Physics
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- čas přidán 11. 12. 2017
- This physics video tutorial explains how to solve any resistors in series and parallel combination circuit problems. The first thing you need to do is calculate the equivalent resistance of the circuit which you can use to calculate the current flowing from the battery based on ohm's law. Using the current and the voltage drops across each resistor, you can calculate the electric potential at every point in the circuit which will allow you to calculate the current flowing through any resistor. This technique is useful if there's not multiple batteries in different loops of the equation. Keep in mind, the current flowing in two resistors that are in series with each other is the same. The voltage is the same across resistors connected in parallel. This video contains plenty of examples and practice problems including a current division formula for resistors connected in parallel.
Schematic Diagrams & Symbols:
• Schematic Diagrams & S...
Resistors In Series:
• Resistors In Series - ...
Resistors In Parallel:
• Resistors In Parallel ...
Series and Parallel Circuits - Light Bulb Brightness:
• Series and Parallel Ci...
Equivalent Resistance of Complex Circuits:
• Equivalent Resistance ...
_________________________
Voltage Divider Circuit:
• Voltage Divider Circui...
Current Dividers:
• Current Dividers Expla...
Parallel Circuit Challenge Problem:
• Finding The Current In...
Kirchhoff's Current Law:
• Kirchhoff's Current La...
Kirchhoff's Voltage Law:
• Kirchhoff's Voltage La...
DC Circuits Review:
• Series and Parallel Ci...
____________________________
KCL and KVL Circuit Analysis:
• Kirchhoff's Law, Junct...
Thevenin's Theorem - Circuit Analysis:
• Thevenin's Theorem - C...
Norton's Theorem - Circuit Analysis:
• Norton's Theorem and T...
Superposition Theorem:
• Superposition Theorem
Maximum Power Transfer:
• Maximum Power Transfer...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
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I got finals too. Trying to figure this out cuz my instructor full of shit .
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Man you're whoever you think you are, no youtube tutor comes close not even an inch closer the gap is too wide. See how I understood this equivalent resistance effortlessly. I've never regretted subscribing to your youtube channel and I will make sure my course mates subscribe to your channel as a form of appreciation to the amount of work you put in just to make us understand seemingly complex topics easily. Because almost all my course mates did not understand this topic when the lecturer came to deliver to the class.You'll be the reason why i will graduate with First Class. thanks once again! Gracias
For some reason this has conceptually been one of the hardest topics for me to grasp at the beginning.. thanks for helping clear it up!
for some reason i was never taught to redraw the circuit at all. I just watched this video and another one where you both redraw the circuit and my mind is blown omfg. it makes everything so much easier to understand
Exactly, I'm like wtf. My prof just told us to simplify the circuit in our head instead of redraw it. I'm like wut?
Absolutely NO redraws are necessary!. Find total resistance from right to left, back to the source voltage. Then figure the total current by Ohms law. Now, going from left to right...figure your voltage drops across R1 and R6. Then subtract those voltages from the source voltage. Divide the 15 volts by R2 resistance to get 1.5 amps, which is half of the total current. The other 1.5 amps goes thru the rest of the circuit, or just divide the 15 volts by the total resistance of the three resistors in the far right part of the circuit. Bingo, problem solved people!
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You do such a great job explaining multiple ways to solve the same problem! In earlier lectures you showed how to do it by summing the resistors in series on right side and then solving the parallel resistors and now you explained the alternate way to solve to find the current through the middle resistor by using the potential difference between two voltage points on either side of the middle resistor and solving for the current through the middle resistor and then subtracting that current to find the remaining current flowing through the resistors in series on the right side of the circuit! Just what I needed explained clearly!
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In physics class, to combine parallel repressors, we have been using the formula 1/Rt =1/R1 +1/R2, but that doesn't seem to be in your video. I'm still kind of struggling to understand circuits as a whole, and it would be very helpful to me if you could explain that rule/ its relevancy to circuits. The right hand rule also has been confusing me as well.
I love your videos, they've helped me loads in AP Chem and in physics. I'm really glad that there are people out there who make videos to help others, rather than click-baited videos.
1/Rt = [1/R1 + 1/R2] and don't forget it's to the power of -1
You only combine them when u are trying to figure out the current encompassing the whole device (circuit).
Once you do that you can troubleshoot your device with a multimeter and see where its failing you.
didiroxforever that method still applies, in the first question he did he said the total resistance for the the two ten ohm resistors in parallel was 5. He got that by adding 1/10 + 1/10 then finding the inverse of that answer
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To compute 2 resistor in parallel with different value just multiply the Numerator then add the Denominator and Devide the value that you get in 15:31 minutes 12 * 4 = 48 (Numerator) then 12 + 4 = 16 therefore 48/16 = 3ohms
Great work! when calculating the currents at each resistor, i get lost due to the resistors not being labelled.
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