7.3 Solving Pulley Systems
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- čas přidán 1. 06. 2017
- MIT 8.01 Classical Mechanics, Fall 2016
View the complete course: ocw.mit.edu/8-01F16
Instructor: Dr. Peter Dourmashkin
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu
This was a really helpful and enlightening video...
Amazing lecture
why we choose different coordinate system not the same and how we can equation that are written for diffenrent coordinate system
Why don't we show tension upwards on the rope as well....like as the rope is massless the tension is constant every Where along the rope....so these upward tension also don't cancel out?? Why don't we show it?
What about the force the pulley exerts on the rope? 🤔
But isn't that paradoxical when we assume the tension in the string to be uniform? The string shouldn't move at all according to the FBD of string or am I missing something?
Vedat Var watch the previous video in the playlist
@@DanLyndon Thanks, that helped.
How is he writing that? Shouldn't it all be in reverse for us, like a mirror image to us.😱😨😮
It is, they're writing on a big pice of glass, and then flip the image so that we can se it.
Notice most teachers appear to be left-handed where many people are actually right-handed, it's the mirror image :)
👍👍👍👍👍
We said earlier that T1=T2 when ma =0 but here T1+T2= F pulley which means T1 is not equal to T2
I think you're confused. T1 + T2 = F_pulley doesn't have anything to do with whether or not T1 = T2. Say, for example, T1+T2 = 4. If this is the case, then when ma = 0, T1 = T2, so that means T1 = T2 = 2. This checks out, 2 + 2 = 4. BUT, if (ma) is not equal to zero, then T1 does not equal T2. However, T1 + T2 still is equal to 4; it could be 2.1 and 1.9, or 1 and 3, or 0.5 and 3.5, etc.