Chapter 1- Exercise 1.2 (Q5, Q6, Q7, Q8) RELATIONS & FUNCTIONS|CBSE Class 12 Maths in Tamil|NCERT|GS

In this video I taught Chapter 1 Relations and Functions - Exercise 1.2 Question Numbers 5, 6, 7, 8 solved in detailed.
**** Exercise 1.2 Relations & Functions ****
Time Stamps:
Q5 - 00:53
Q6 - 06:48
Q7(i) - 08:37
Q7(ii) - 14:55
Q8 - 19:18
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[@shaliyashalu5221]

Anna 12 lesson continue pannunga na ungala nambi tha board exam prepare pandran ............... Don't leave us na 🥺. ........and I secure in my week test 93/100 na

[@shaliyashalu5221]

12 th standard lessons

[@GopinathShanmugam]

Super ma thangachi....sure definitely I will post don't worry ma...Now I am little busy from next week I will post videos continuously don't worry ma.....

[@shaliyashalu5221]

@@GopinathShanmugam tq anna 🤜🤛

[@PriyaDharshini-iv3kq]

Anyone in 2024😂

[@Shamsuthsameer]

😂

[@MouniappaneR]

🖐🏻😂

[@xollox3714]

us bro us

[@KavyaJ-oo3xt]

😅

[@sherins6013]

Sir your teachings are really awesome and I can understand very well

[@merlin6603]

Ultimate sir ninga...spr ah purinchuu...nalaiku exm enna pandrathu theriyama iruntha...paravalyee math um easy nuh ninga eduthu than puriyuthu❤...thanks sir...

[@GopinathShanmugam]

Thanks thambi, kindly do subscribe and share to your frds

[@merlin6603]

@@GopinathShanmugam sir .....thangachii😅

[@dharshini4181]

அண்ணா, Well teaching! Thank you ☺💙

[@kiruthikashashna9093]

Your teaching is wonderful.... go-ahead sir.. All the best...

[@mahathik575]

Sir great teaching sir plzzz don't stop sir 👍

[@saimanju1171]

I can understand only by Ur teaching sir .... Pls do miscellaneous exercise also

[@GopinathShanmugam]

Sure sure.. coming soon. Kindly do subscribe and share to all your class mates

[@rithikkannan2977]

Thank you sir 🤩

[@more-ee7ix]

Thala na ippa thaan 12th poren un video ennaku romba helpful la irruku thalaa

[@badmintonlover5078]

Thanks sir ☺️

[@s.p.ananthitha2812]

Sir ncert exemplar podunga please... Naaan undagaluku subscribers rise panni tharen😢

[@Nityasreeh]

😂

[@dhaneshmuthu9044]

God bless you sir

[@d.nrockff1102]

Sir in 7th sum in that 2 sub division,it comes onto when we prove like f(x)=y

[@jayasneha168]

Sir excellent teaching sir

[@sarukkeshsarukkesh2073]

Thanks anna you are great anna can yous say me how tp study speedly pls I am very lagging in that pls anna

[@MrKem-qm2yg]

Happy birthday to you 🎂🎉

[@renisha.gracelinn]

thank you

[@kaviyathequeen814]

Hi sir ..

[@imashikda]

5,6,7,8,9,11,12,14

[@abishekabishek2700]

Sir nenga entha view la vachu canera and board vaipinga

[@divyan.A.S]

Sir in the 7th sum second question we can say that it is onto function bcoz
f(x)=1+x²
F(x)=y, y=1+x² = x²=y-1 = x=√y-1
Substitute value of x as y in answer
Let f(x)=y for every y€R there exist x=√y-1
F(x)= 1+(√y-1)²
By cancelling sq. and root we will get
F(x) =1+y-1
Then, f(x)=y
Then it is onto function know sir 😢😢😢 pls explain it sir!!!!!

[@jayapriyathennavan2437]

x = (+or-) √y-1
x^2 la so value may be positive or negative

[@divyan.A.S]

@@jayapriyathennavan2437 thnx 🙇‍♂️

[@Kxxh883]

3:00 f(1) onuku povum.

[@divyarani8534]

Sir oru doubt
Signum function ellama one-one and onto kediyatha??

[@divyarani8534]

Sir reply sir

[@GopinathShanmugam]

Yes, from R to R, signum function is neither one to one nor onto.

[@divyarani8534]

@@GopinathShanmugam ok sir

[@abineshb2476]

Sir deleted portion oru video vaa poduga sir

[@rinzz99]

0.1 and 0.5, will it come under 0 or 1?

[@anandhansenthilkumar3950]

0

[@user-cm3zm1ez8k]

Gi

[@sivakamyvijay9248]

Can't understand

[@GopinathShanmugam]

Which problem thambi,...tell me

[@AdonisTheGod]

@@GopinathShanmugamsir doubt sir 7th la 2 sum la normal method la pota x1=x2nu varudhe sir enna panrathu sir ethuku eppidi podanu