From a confidence interval, find the number surveyed and margin of error (Statistics 5)

University students were surveyed and asked if they had over $30,00 in student loan debt. The 95% confidence interval was found to be 56.1% to 82.5%. Find the percent of students in this survey who had over $30,000 of college loan debt. Find the margin of error of the confidence interval. Bonus! How many students were surveyed in this study?

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The margin of error would be 13.2% divided by 2 because isn’t 95% CI stating that it’s 2 SD away from the mean??