Pyramid Frustum

[@johnescranda1804]

6:37 V1 should be 64 units cubed
V1 = 64 units cubed
V2 = 8 units cubed
Vf = V1 - V2
Vf = 56 units cubed

[@Twizzzzzy]

That’s what I thought,
Here’s what I did;
h/3 x (a^2 + ab + b^2) =
h/3 x ( 4 + 8 + 16) =
6/3 x (28) = 56
The answer is 56.

[@user-sj7vo2iw7u]

I'm amazed at you thank you so much pls continue

[@nandanarekal5631]

To get slant height we have to use---------- l^2 = (half of hypotenuse of base)^2 + height ^2

[@jeromejeyz8499]

Square roots are slunt height not peperndicular height

[@JCuddihee]

I believe the volume of the frustum is 56 u cubed not 40 u cubed.

[@tedhodgson4623]

Very true. For some reason, I thought that 4 x 16 = 48 on the day I created the video. Obviously, 4 x 16 = 64, so the volume is 64 - 8 = 56 units cubed.

[@HansTheCool]

what do you do if there is no side length of the top square is given?

[@amakaugo7657]

I think there's a mistake in 1:58

[@jordancrate602]

did you make a mistake at 7:20 min? shouldn’t the base of V2 be 2? so 1/3(2)(6)

[@johnescranda1804]

Jordan Crate He’s looking for the volume. Breaking down the formula 1/3Bh
B = Area of the base which is s^2
Volume = 1/3(s^2)h

[@benyamtewolde9242]

@ 16:04 subtract error4*sqrt(37)

[@ashutoshkumar6568]

v1 will be 64

[@jeromejeyz8499]

I think u made a mistake