This is literally the best CZcams educational video I've ever watched. Brian, u probably saved my entire acid/base part of the organic chemistry exam ill have in few weeks, and for that I really want to thank you. I was struggling on simple exercises before watching your video, and with the examples u used and your explanation I can now solve them within seconds. This is such a good explanation im really happy I came across this video. Hats off for you. Regards from Switzerland !
I usually find most you tube videos on most of organic chemistry topics more confusing than the books I use. This truly is applicable and guiding. I've no words!!!
In 14:04 to 16:06 you say that O > N in terms of electronegativity, and then S > O in terms of size, and so put them as S > O > N (you said that S will be the best). But if you look up the electronegativity table, then O=3.44 > N=3.04 (as you said), but S=2.58, so sulfur is actually the _worst_ of these two in terms of electronegativity :q So in that case it should really be O > N > S. Is that correct? So which factor should we consider as more important when it comes to accommodating negative charges? Electronegativity, or size? Is it possible, for example, for resonance or induction to outweigh one of the other factors? I.e. are they ordered top to bottom in such a way that we can check them in top-to-bottom order safely? Or could it be that some combination of lower factors can outweigh one of the higher factors on your list? What if one molecule wins with another by resonance, but loses instead by induction, for example?
THIS! I was looking for the answer too in the comments, I was majorly confused by this but barely noone else in the comment section seems to have even noticed it??? wtf
Hey Brian, great video! Quick question - towards the end when you're ranking the organic molecules in order of decreasing basicity, you have the sp-hybridized carbon ranked as more basic than the sp3. Shouldn't it be the other way around where sp3 is more basic than sp2, followed by sp? Since the more S character, the more stable and, therefore, more acidic? Thanks!
For 28:51 , why wouldn't the last molecule with the Cl be 2nd instead of 3rd? I understand that Sulfur's atomic radius is bigger than Oxygen's, but in this case, Oxygen is more electronegative AND has good induction, vs the molecule with Sulfur only really has the atomic radius going for it since there's nothing else making it more stable. I know we said the order is partially important, but in my mind the last molecule has two things making it stable vs the sulfur one only has one thing. (I hope I'm making sense lol)
the charge is on the o, not the cl or f which means the size effect does not apply. the electronegativity being greater in f than cl has a larger inductive effect
This is literally the best CZcams educational video I've ever watched. Brian, u probably saved my entire acid/base part of the organic chemistry exam ill have in few weeks, and for that I really want to thank you. I was struggling on simple exercises before watching your video, and with the examples u used and your explanation I can now solve them within seconds. This is such a good explanation im really happy I came across this video. Hats off for you. Regards from Switzerland !
get a room
THANK YOU SO MUCH! My TAs has no idea how to explain this to us. This makes me so much more sense now.
I usually find most you tube videos on most of organic chemistry topics more confusing than the books I use. This truly is applicable and guiding. I've no words!!!
I have an exam on Tuesday and I needed this very badly. Thank you so much!
thank you! I like your way of doing it! I'll be using your approach on the exam!
Thanks for your explanation. I can finally understand the concept now
I am so glad that i opened this video. This literally saved my life!!!!
Omg thank you for making this I was so confused before!
such a good resource, this was seriously aweomse
This video is crazy usefull. Thanks from Italy man!
thank you the way of explaining was very helpful
well,Sir thanks a million for such a brilliant video, cleared all my doubts, looking forward to more videos like this. Regards from India
wow! It hadn't even occurred to me to make a table
Thank you, you saved my life
Thanks for the help with O chem :)
great video! you got my subscription
super helpful, thank you!
The answers don’t match the order you’re suggesting?
I feel like I'm out of 5th period and sitting in the hs auditorium for the mandatory assembly for Ranking Acidity in O-Chem and all for it!
Thank you so much this helped a lot 👍
Thank you!
In 14:04 to 16:06 you say that O > N in terms of electronegativity, and then S > O in terms of size, and so put them as S > O > N (you said that S will be the best).
But if you look up the electronegativity table, then O=3.44 > N=3.04 (as you said), but S=2.58, so sulfur is actually the _worst_ of these two in terms of electronegativity :q So in that case it should really be O > N > S. Is that correct?
So which factor should we consider as more important when it comes to accommodating negative charges? Electronegativity, or size?
Is it possible, for example, for resonance or induction to outweigh one of the other factors? I.e. are they ordered top to bottom in such a way that we can check them in top-to-bottom order safely? Or could it be that some combination of lower factors can outweigh one of the higher factors on your list?
What if one molecule wins with another by resonance, but loses instead by induction, for example?
THIS! I was looking for the answer too in the comments, I was majorly confused by this but barely noone else in the comment section seems to have even noticed it??? wtf
I think it is because it's a balance of the electronegativity and the size of the atom and sulfur is a larger atom so it was first. I hope this helps!
Around 5 minutes in he's talking about a balance between size and electronegativity. Does that help?
size trumps electronegativity usually when it comes to comparing stability of conjugate bases
it was superb!
Hey Brian, great video! Quick question - towards the end when you're ranking the organic molecules in order of decreasing basicity, you have the sp-hybridized carbon ranked as more basic than the sp3. Shouldn't it be the other way around where sp3 is more basic than sp2, followed by sp? Since the more S character, the more stable and, therefore, more acidic? Thanks!
sp3 is more basic that is why it's ranked first (3)
thank you sm!!!!!!
Can you explain how the induction effect can have "good", "bad" or nothing? what determines it? Thank you.
우와 한국인이다!!! 반가워요
Woah... it makes sense now XD
15:22 How's the hybridization of NH2 sp3. shouldn't it be sp2 because one lone pair and two bonding regions?
There are two lone pairs and 2 bonding regions. Note that the molecule is now NH2-, not NH2.
I'm new to this topic and this video confuses me :(((
For 28:51 , why wouldn't the last molecule with the Cl be 2nd instead of 3rd? I understand that Sulfur's atomic radius is bigger than Oxygen's, but in this case, Oxygen is more electronegative AND has good induction, vs the molecule with Sulfur only really has the atomic radius going for it since there's nothing else making it more stable. I know we said the order is partially important, but in my mind the last molecule has two things making it stable vs the sulfur one only has one thing. (I hope I'm making sense lol)
best!!!! thanks a lot
Can you make more ochem videos? Please....
did you record this in a cave?
lol
Grant Fisher lol chilll
LMAO 💀
🤣🤣🤣🤣🤣🤣🤣🤣🤣
How are you doing guys
the way you present answers at the end of a problem is confusing,
Hello ChE from UPV ik ur watching this rn, good luck as prob set
@@kaylenyvonjalandoni6705 talaga?? huhuhu
At 23:36 how are the two molecules sp2?
Is it because they have resonance and so there can be a pi bond there?
It’s because of the non bonding electrons
Nice
great video but it's hard to make out what you're saying.
Isn't Cl more electronegative than F? 20:04
no F is more electronegative. Charge goes up when you more to the right and move up the P.T.
Chlorine is more acidic . . . based on the periodic trend, acidity increases from left to right and from up to down . . .
But isn’t cl bigger than F at 21:56 so it should have been 45312?
the charge is on the o, not the cl or f which means the size effect does not apply. the electronegativity being greater in f than cl has a larger inductive effect
But he’s falling asleep while explaining so now I’m falling asleep lol
hahaha