Good work! It's the very best explanation I found on this matter. I was searching for, probably 20h overall, since I first saw that circuit. And only you explain the states, but also the transitions and all that in a mathematicaly coherent way by using Kirchhof and even repeating each step 3 times or so, firstly to just show it, and then to sum it up again more fluently, to help put the idea together that was in ones mind. Very nice. Just what I need.
I was surprised as well! When I was initially trying to understand how this circuit works myself, I kept thinking I had screwed it up and was wrong because I kept getting a negative voltage and that made no sense. But as it turns out, charging/discharging circuits do funny things like that, which is why it's important that the transistors can handle being reverse-biased and not conduct or break.
I didn’t find a video in my language that explains me that concept in a way I understand. Had to switch language, thanks sir for your patience and explanation !
I am late but I have to thank you so much for explaining it in so much detail. I never understood the negative Voltage at the Base of the Closed Transistor. Thank you so much!
Sir i don't know how many times I should thank you for clearing this concept I have been struggling with the visualization of this circuit so that I could register it into my mind Now,I saw your video and my vague understanding resonated with your explanation Thanks once again I am a hobbiest and currently pursuing electrical and electronic engineering in India 🇮🇳
Great explanation man. Exactly what I need. When I first saw this circuit, I thought I could easily figure it out but, I could not. It's operation turns out to be surprisingly complicated.
Incredible, super, Don't have more words to say you are awesome, I was looking for this for months now, you gave me relaxation to my mind. Super work :). Keep up the good work. Good Luck
the jump cuts were really difficult to follow, the use of the word "this" made it also difficult to follow (what is "this"??). However, your repetition of the ideas was really *really* helpful. I really appreciated the beginning of the video where you addressed how it gets into a deterministic state from a non-deterministic state. I'm definitely subscribing!
This circuit works fine as long as the operating voltage stays well below the avalanche breakdown voltage of the base emitter diode of the transistor, which is typically between -7 and -9 V.
I have to say man that it is difficult to follow. I am picking up bits and pieces, but some I’m not. Do you have any very basic videos that you can recommend that can get me started in this field?
This is silly, but....even something like a random gamma ray from God knows where could displace a single electron in one of your capacitors and cause the "initial" astable state. I just discovered your video today, and I really like it.
YOu made two good points: Be careful not to exceed Transistor's REVERSE Vbe; Electrolytic Capacitors can be used because the time of capacitor reverse polarity is so small.
Very useful video (much, much better than the usual hand wavey explanations). Do you know of a source that actually works through the Kirchhoff equations for this circuit in full detail? I’ve been trying to find one, but haven’t had any luck so far. Thanks again for the video!
Thanks a lot, I learned a few things. I'm trying to work out the cap voltages in the case of using PNP transistors in this circuit. Given a 9v power supply, I think C1's voltages when T1 is ON are 9v & 16.3v (left and right sides respectively) at the moment it just switched over. So what I mean is the surprise neg voltage in your NPN example 'inverts' to a much higher than Vcc amount...again surprising at first glance. Is this right?
It's a magnetic whiteboard, meaning it's metal underneath the white coating. I bought magnetic sheets which are just big, thin, paper-shaped soft magnets, printed out whatever I wanted and glued it to the sheets, then used scissors to cut them out.
I think it’s becUse of the resistance values of the resistors. Remember that the inner ones are higher ohms than the outer ones and based on that the voltage drop through them creates an appropriate inbalance on the respective side of the capacitor
Because its grounded through the collector and has to discharge first because of the polarity of the capacitor at that moment and after its voltage is zero it will charge in the opposite direction of the discharging something like that
Think about a simple closed loop with a Vcc (5V), a LED (we assume its voltage drop is 2V) and a resistor. You have 5V; 2V voltage drop on the LED, then resistor "takes over what’s left" : 3V.
I believe it’s Based on the resistance values of the resistors. Then inner ones are higher resistance than the outer ones, this causes a different voltage drop causing an imbalance across the capacitor. The outer resistor is connected to one side of the capacitor the inner resistor is connected to the other side of the capacitor. The difference in ohms causes the imbalance via voltage drop
Can you place the capacitor between the collector of one bjt and the base of the other bjt instead of its base like you have it. I am looking at this website and I swear that is how they have it. I was wonder something does not look right. So I don't know what results.
You started strong in the first minute. Then you got fixated on an irrelevance. Now I see why bus drivers should not teach (or try to teach) electronics to people who have a casual interest.
Good work!
It's the very best explanation I found on this matter.
I was searching for, probably 20h overall, since I first saw that circuit.
And only you explain the states, but also the transitions and all that in a mathematicaly coherent way by using Kirchhof and even repeating each step 3 times or so, firstly to just show it, and then to sum it up again more fluently, to help put the idea together that was in ones mind.
Very nice. Just what I need.
I never thought a simple circuit like this would have negative voltage at some point (11:00) ….. well explained, thank you.
I was surprised as well! When I was initially trying to understand how this circuit works myself, I kept thinking I had screwed it up and was wrong because I kept getting a negative voltage and that made no sense. But as it turns out, charging/discharging circuits do funny things like that, which is why it's important that the transistors can handle being reverse-biased and not conduct or break.
The best explanation by far how an Astable Multi vibrator on CZcams! Very intuitive manner to explain how a circuit works!
Best explanation on the whole internet
I didn’t find a video in my language that explains me that concept in a way I understand. Had to switch language, thanks sir for your patience and explanation !
I am late but I have to thank you so much for explaining it in so much detail. I never understood the negative Voltage at the Base of the Closed Transistor. Thank you so much!
Sir i don't know how many times I should thank you for clearing this concept I have been struggling with the visualization of this circuit so that I could register it into my mind
Now,I saw your video and my vague understanding resonated with your explanation
Thanks once again I am a hobbiest and currently pursuing electrical and electronic engineering in India 🇮🇳
Beautifully put again.
Great explanation man. Exactly what I need. When I first saw this circuit, I thought I could easily figure it out but, I could not. It's operation turns out to be surprisingly complicated.
indeed you are taking enough time to explain each detail so it becomes easier to follow and REALLY understandable. Well done
Thank you so much for taking the time to explain this carefully! Amazing job
Incredible, super, Don't have more words to say you are awesome, I was looking for this for months now, you gave me relaxation to my mind. Super work :). Keep up the good work. Good Luck
Very well explained, thx a lot for this, was scratching my head before on this one.
the jump cuts were really difficult to follow, the use of the word "this" made it also difficult to follow (what is "this"??). However, your repetition of the ideas was really *really* helpful. I really appreciated the beginning of the video where you addressed how it gets into a deterministic state from a non-deterministic state. I'm definitely subscribing!
This circuit works fine as long as the operating voltage stays well below the avalanche breakdown voltage of the base emitter diode of the transistor, which is typically between -7 and -9 V.
I have to say man that it is difficult to follow. I am picking up bits and pieces, but some I’m not. Do you have any very basic videos that you can recommend that can get me started in this field?
great video!! Needed to learn this for school
Excellent explanation. You didactic its amazing!
Amazing!
Nice explanation thanks sir
Love this!
Very well done !
Thanks, subscribed
This is silly, but....even something like a random gamma ray from God knows where could displace a single electron in one of your capacitors and cause the "initial" astable state.
I just discovered your video today, and I really like it.
YOu made two good points: Be careful not to exceed Transistor's REVERSE Vbe; Electrolytic Capacitors can be used because the time of capacitor reverse polarity is so small.
For the electrolytic I think it's that the reverse voltage is so small, not the time.
My brain hurts!! 🤯
great suggestion from YT. new sub indeed. TY!!
Very useful video (much, much better than the usual hand wavey explanations). Do you know of a source that actually works through the Kirchhoff equations for this circuit in full detail? I’ve been trying to find one, but haven’t had any luck so far. Thanks again for the video!
I don't know of one, but I've been meaning to do some actual circuit analysis videos. I just have to get around to it.
Thanks
A brilliant man 👑
i appreciate if you have any documented material about this subject
Thanks a lot, I learned a few things. I'm trying to work out the cap voltages in the case of using PNP transistors in this circuit. Given a 9v power supply, I think C1's voltages when T1 is ON are 9v & 16.3v (left and right sides respectively) at the moment it just switched over. So what I mean is the surprise neg voltage in your NPN example 'inverts' to a much higher than Vcc amount...again surprising at first glance. Is this right?
Why assuming one capacitor charging and the other is discharging? I thought both are charging initially at time 0.
How you be able to stick paper to the board? Thanks
It's a magnetic whiteboard, meaning it's metal underneath the white coating. I bought magnetic sheets which are just big, thin, paper-shaped soft magnets, printed out whatever I wanted and glued it to the sheets, then used scissors to cut them out.
Just one question? How do you know that the capacitor C2 is discharging not charging (07:30)?
I think it’s becUse of the resistance values of the resistors. Remember that the inner ones are higher ohms than the outer ones and based on that the voltage drop through them creates an appropriate inbalance on the respective side of the capacitor
Because its grounded through the collector and has to discharge first because of the polarity of the capacitor at that moment and after its voltage is zero it will charge in the opposite direction of the discharging something like that
I don’t know what you mean by the resistors taking over what’s left.
Think about a simple closed loop with a Vcc (5V), a LED (we assume its voltage drop is 2V) and a resistor.
You have 5V; 2V voltage drop on the LED, then resistor "takes over what’s left" : 3V.
So the voltage goes negative because of the voltage drop across the resistor?
How do you know to assign the + and - signs on the two capacitors?
I believe it’s Based on the resistance values of the resistors. Then inner ones are higher resistance than the outer ones, this causes a different voltage drop causing an imbalance across the capacitor. The outer resistor is connected to one side of the capacitor the inner resistor is connected to the other side of the capacitor. The difference in ohms causes the imbalance via voltage drop
what are those headphones ?
Can you place the capacitor between the collector of one bjt and the base of the other bjt instead of its base like you have it.
I am looking at this website and I swear that is how they have it. I was wonder something does not look right. So I don't know what results.
Somehow this helped and made it worse. :/
Ok. Can you stop doing the annoying animation. I can't focus on what you're saying because of the annoying cutting footage.
You started strong in the first minute.
Then you got fixated on an irrelevance.
Now I see why bus drivers should not teach (or try to teach) electronics to people who have a casual interest.