Preparation of alcohols using NaBH4 | Alcohols, ethers, epoxides, sulfides | Khan Academy
Vložit
- čas přidán 18. 08. 2012
- How to prepare a primary or secondary alcohol from a ketone or aldehyde using sodium borohydride. Created by Jay.
Watch the next lesson: www.khanacademy.org/science/o...
Missed the previous lesson? www.khanacademy.org/science/o...
Organic Chemistry on Khan Academy: Carbon can form covalent bonds with itself and other elements to create a mind-boggling array of structures. In organic chemistry, we will learn about the reactions chemists use to synthesize crazy carbon based structures, as well as the analytical methods to characterize them. We will also think about how those reactions are occurring on a molecular level with reaction mechanisms. Simply put, organic chemistry is like building with molecular Legos. Let's make some beautiful organic molecules!
About Khan Academy: Khan Academy offers practice exercises, instructional videos, and a personalized learning dashboard that empower learners to study at their own pace in and outside of the classroom. We tackle math, science, computer programming, history, art history, economics, and more. Our math missions guide learners from kindergarten to calculus using state-of-the-art, adaptive technology that identifies strengths and learning gaps. We've also partnered with institutions like NASA, The Museum of Modern Art, The California Academy of Sciences, and MIT to offer specialized content.
For free. For everyone. Forever. #YouCanLearnAnything
Subscribe to Khan Academy’s Organic Chemistry channel: / channel
Subscribe to Khan Academy: czcams.com/users/subscription_...
u can't believe what u did 4 me....thanksssss alot !!!!!!!!!!!!1
Khan academy for life
sir in da abv rxn 'H' [BH4] has positive charge ,hw can it attach to the carbo cation .please clear my doubt,sir
7:58 why in this reaction do we use methanol unlike the first reactions when we used H+? like how did you know to just use methanol
I think,to reduce ketones alcohol should be used as a solvent
Is this a SN2 mechanism? I need fast answer :)
+Cartoonjoystick nah it's not SN2. If it was SN2 that would indicate that the BH4 would stay bonded and the oxygen would leave (which wouldn't happen since SN2 reactions normally have halides as leaving groups)
anyone stuck confused on how to do the LiAlH4 + Aldehyde? :(
Is this mechanism a consequence of the oxymercuration of an alkene?
Simply too fast....much better videos with good pacing and far more
sophisticated diagrams available on CZcams..............