Norton's Theorem with Dependent Source

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  • čas přidán 4. 09. 2024
  • Network Theory: Solved Question on Norton's Theorem
    Topics discussed:
    1) Calculating Norton's current when the network has a dependent source.
    2) Calculating Norton's resistance when the network has a dependent source.
    3) Norton's equivalent circuit of a network with a dependent source.
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Komentáře • 26

  • @oliversaviour3286
    @oliversaviour3286 Před 2 lety +5

    Thank you very much for your help. I had difficulties in understanding superposition, Thevenin's and Norton's theorem but gradually watching your videos via CZcams, I'm able to solve almost every question concerning these theorems. Thank you once again!

  • @racademy4192
    @racademy4192 Před 4 lety +2

    In the presence of independent source ,if dependent source is present then the procedure to find Rn or Rth is by finding Voc and Isc and then dividing former by latter.

  • @shivanshusharma7741
    @shivanshusharma7741 Před 4 lety +10

    In the last step for finding RTh, 5 ohm and 4ohm resistors r connected in series so RTh should be 9ohms?

    • @simranjitsingh4935
      @simranjitsingh4935 Před 4 lety +14

      there is a short circuit after 4 ohm resistance (where he replaced the independent voltage source with the short), hence it is not taken into account

    • @nahiyanalamgir7056
      @nahiyanalamgir7056 Před 3 lety +18

      Another way to think about it: across the 4 ohm resistor, the potential difference is 0 (the resistor is connected to the same node!), thus no current will flow through it (ohm's law). Thus it's as if the resistor doesn't even exist, since R = V / I (both V and I are 0) = 0.

  • @shahnawazgkp
    @shahnawazgkp Před 4 lety +4

    Thanks Sir.. Please Upload some more numerical problem related to Superposition, Thevenin, and Norton theorem ..(In this lock down period).

  • @ssbgogeta7514
    @ssbgogeta7514 Před 4 lety +2

    Zeher lecturer sir ji ❤️

  • @saimadhavchakrala4430
    @saimadhavchakrala4430 Před 9 měsíci

    Thank you sir

  • @saurabhsuthar9274
    @saurabhsuthar9274 Před 3 lety +5

    Suppose 2ix is not zero then after we have to open circuit the dependent source or not?

  • @none665
    @none665 Před 3 lety +3

    But I am unable to do it with thevenin s

  • @qemmm11
    @qemmm11 Před 9 měsíci

    Thanks Sir😊
    10=4ix,ix=2.5A
    E=5(I+2ix)+10=5(I+5)+10
    E=5I+25+10=5I+35
    So Rab=5,Eab=35v(one minute)

  • @saikrishnathota5972
    @saikrishnathota5972 Před 4 lety

    Thank u sir

  • @yasaswinikothamasu3473
    @yasaswinikothamasu3473 Před 4 lety +1

    Sir, please make videos on state space analysis.

  • @ahmedtawfeeq6511
    @ahmedtawfeeq6511 Před 4 lety

    Why the independent source has been open-circuited when it equals Zero?

    • @mumtaheenareza6484
      @mumtaheenareza6484 Před 4 lety +2

      Or,you can also find Rn by adding a 1V voltage in a-b terminal and short circuiting the 10V.
      Then the 4ohm will be ignored due to being short circuited.
      Then the voltage source,5ohm and dependent sources will all be in parallel and you can find i=1v/5 =0.2
      Rn=v/i =1/0.2

    • @hasnainashraf660
      @hasnainashraf660 Před 2 lety

      @@mumtaheenareza6484 why we applied kcl at the reference node b

  • @birensubba8986
    @birensubba8986 Před 3 lety +9

    Y CZcamsr only solve common problem..

  • @anjalisuniquechannel
    @anjalisuniquechannel Před 2 lety

    If there is only one dependent source then why the value of Inor is 0

  • @Akash_Balamurugan
    @Akash_Balamurugan Před 4 lety +1

    why 4ohm is not consider when find Rn ?

    • @jancydas5569
      @jancydas5569 Před 4 lety +5

      Becoz of short circuited voltage source

    • @SasawataDG
      @SasawataDG Před 4 lety +14

      As the voltage source is now short circuited, the 4 Ohms resistance comes in parallel with a short circuit. As you know when a s.c is parallel with any resistance, the overall resistance is 0 ohms. Hence, the 4 Ohms is not considered when Rn is being calculated.

  • @continnum_radhe-radhe
    @continnum_radhe-radhe Před 2 lety +1

    🔥🔥🔥

  • @amitkumar-ex7pg
    @amitkumar-ex7pg Před rokem

    Hi

  • @sakhavalley4382
    @sakhavalley4382 Před 4 lety +1

    👌👌👌👌 🌼🌹🌹🏵️