Norton's Theorem with Dependent Source
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- čas přidán 4. 09. 2024
- Network Theory: Solved Question on Norton's Theorem
Topics discussed:
1) Calculating Norton's current when the network has a dependent source.
2) Calculating Norton's resistance when the network has a dependent source.
3) Norton's equivalent circuit of a network with a dependent source.
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Thank you very much for your help. I had difficulties in understanding superposition, Thevenin's and Norton's theorem but gradually watching your videos via CZcams, I'm able to solve almost every question concerning these theorems. Thank you once again!
In the presence of independent source ,if dependent source is present then the procedure to find Rn or Rth is by finding Voc and Isc and then dividing former by latter.
In the last step for finding RTh, 5 ohm and 4ohm resistors r connected in series so RTh should be 9ohms?
there is a short circuit after 4 ohm resistance (where he replaced the independent voltage source with the short), hence it is not taken into account
Another way to think about it: across the 4 ohm resistor, the potential difference is 0 (the resistor is connected to the same node!), thus no current will flow through it (ohm's law). Thus it's as if the resistor doesn't even exist, since R = V / I (both V and I are 0) = 0.
Thanks Sir.. Please Upload some more numerical problem related to Superposition, Thevenin, and Norton theorem ..(In this lock down period).
Zeher lecturer sir ji ❤️
Thank you sir
Suppose 2ix is not zero then after we have to open circuit the dependent source or not?
No , dependent source will remain as it is.
But I am unable to do it with thevenin s
Thanks Sir😊
10=4ix,ix=2.5A
E=5(I+2ix)+10=5(I+5)+10
E=5I+25+10=5I+35
So Rab=5,Eab=35v(one minute)
Thank u sir
Sir, please make videos on state space analysis.
Why the independent source has been open-circuited when it equals Zero?
Or,you can also find Rn by adding a 1V voltage in a-b terminal and short circuiting the 10V.
Then the 4ohm will be ignored due to being short circuited.
Then the voltage source,5ohm and dependent sources will all be in parallel and you can find i=1v/5 =0.2
Rn=v/i =1/0.2
@@mumtaheenareza6484 why we applied kcl at the reference node b
Y CZcamsr only solve common problem..
That's the problem - they rarely go into advanced ones.
If there is only one dependent source then why the value of Inor is 0
why 4ohm is not consider when find Rn ?
Becoz of short circuited voltage source
As the voltage source is now short circuited, the 4 Ohms resistance comes in parallel with a short circuit. As you know when a s.c is parallel with any resistance, the overall resistance is 0 ohms. Hence, the 4 Ohms is not considered when Rn is being calculated.
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Hi
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