Please check my video on solving diophantine euations in 2 variables. There I have explained how general solution is written in terms of a parameter t. Diophantine equations if solvable have infinite solutions and the different values of t give the infinite solutions
Mam I have a problem that Prove that x^2 +y^2=z^2 With y even are x=r^2-s^2 , y=2rs , z=r^2+s^2 where r and see are arbitrary integers of opposite parity Can you prove it
thank you so much for your detailed explanations
Thank you for your comment
Thank you mam
Thank you for watching
Can you explain the part where you introduce t, and how you go from 6(450) = 450-6t
Please check my video on solving diophantine euations in 2 variables. There I have explained how general solution is written in terms of a parameter t. Diophantine equations if solvable have infinite solutions and the different values of t give the infinite solutions
Mam I have a problem that
Prove that x^2 +y^2=z^2
With y even are x=r^2-s^2 , y=2rs , z=r^2+s^2 where r and see are arbitrary integers of opposite parity
Can you prove it
Is this the way
x^2 +y^2 = (r^2-s^2)^2 + (2rs)^2 = r^4 +s^4 -2r^2s^2 + 4r^2s^2
=r^4 +s^4 + 2r^2s^2 = (r^2+s^2)^2 =z^2