E2 Reaction Mechanism - Hoffman Elimination vs Zaitsev's Rule

This organic chemistry video tutorial provides a basic introduction into the E2 reaction mechanism. The hoffman product is the least stable alkene and the zaitsev product is the most stable alkene. The hoffman product can be formed using a bulky base with a sterically hindered alkyl halide or using an alkyl fluoride.
Stereochemistry R/S Configuration:
• Stereochemistry - R S ...
Optical Activity & Specific Rotation:
• Optical Activity - Spe...
SN1, SN2, E1, E2 Reaction Mechanisms:
• SN2 SN1 E1 E2 Reaction...
SN2 Reaction Mechanisms:
• SN2 Reaction Mechanisms
SN2 - Test Question:
• SN2 Reaction Mechanism...
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SN1 Reaction Mechanisms:
• SN1 Reaction Mechanism
Carbocation Stability - Hyperconjugation:
• Carbocation Stability ...
Carbanion Stability:
• Carbanion Stability
Protic Vs Aprotic Solvents:
• Polar Protic Solvents ...
E1 Ring Expansion:
• E1 Reaction Mechanism ...
E2 - Test Question:
• Zaitsev vs Hoffman's P...
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E2 Stereochemistry - Newman Projections:
• E2 Stereochemistry Wit...
SN1, SN2, E1, E2 - Practice Test:
• SN1 SN2 E1 E2 Reaction...
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www.video-tutor.net/orgo-chem...
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bit.ly/3PKEApB
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[@Mirwhosane]

Hi

[@alondraherrera4170]

didnt really explain what an e2 reaction is and how it works, do you have a video on that?

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[@yuridanylko]

Say there is a molecule (a triene) in which a bulky base is used to to create a hoffman product via an E2 reaction.
The first option will result in a cis disibstituted pi bond.
The second option will result in a geminal disubstituted pi bond.
There is also a trisubstituted pi bond possible towarss the middle of the alkene.
Will the major product be the cis or geminal alkene? What drives this? Stability of the carbocathion? Steric hindrance? Stability of the end product?

[@shaktisinghhemant1937]

Thank you so much

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Have a great day....

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[@nikodg194]

The reason why the Hoffman product forms while e2 elimination of fluorine is due to enthalpy of the fluorine carbon and that's why it dont want to go easily at least that's what my profesor says

[@jellyfam1197]

I have two orgo professors both highly respected in their fields, both had different reasoning. Consensus is that no one exactly knows, there’s 2-3 hypotheses as to why Fl- is Hoffman

[@lizareizis2517]

what makes a good or bad leaving group?

[@JamesKing-pl2xu]

The size i believe because its size is what determines the polarizability (ability to stabilize the charge). Therefore I- or Br- are better leaving groups than say F- and Cl-

[@puneetgill4064]

for -O-CH(CH)3, will its preference be 1>2>3 because of steric hindrance?

[@maureene7138]

It will actually prefer 3>2>1 for E2 and E1

[@sakshamshrivastava4221]

Thank sir

[@xxcoltonxx2540]

What about when its an alkyl group connected to a benzene ring, kinda need to know how to find the minor product there don't we....

[@albertlee8586]

If E2 is favored with a polar aprotic solvent is there a reason you use methanol for many of the solvent examples? Thanks for the video, super helpful for a quick MCAT review! Edit: type

[@annablueseas]

i was thinking the same thing! i was so confused

[@bobu5213]

So in both the E1 and E2 reactions, both the minor and major product always form if possible?

[@muslimgirl1481]

Yes bcz both are regioselective ( can give major and minor products) and sterioselective ( can form cis and trans product) also.

[@kraken6161]

now is hoffman product the minor or the major because once the minor was hoffman then the major was hoffman

[@KshitijPunani]

Thanks nro

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god bless you

[@David-fh6rr]

But why does is the conjugated product formed? The MeO- doesn't know it has to make the conjugated product, it has no brain.
Does the double bond already draw electron density from the a-CH bond to make it more likely to break before it happens?

[@ashueje6416]

Both the products are formed in the reaction the conjugated diene is majorly formed as it is more stable .
the reactions occus so as the products have a lower Potential energy than the reactants is their is reconance then the stability of the alkene is more so this is the only reason why a cinjugated di ene is formed in major.

[@theg.o.a.t1014]

Now I am maestro after 12min watching

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Haa bhai, JEE 2025. Halo arenes and amines ke PYQ me bohot use hota hai E2 mechanism

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[@riyashukla7959]

Is it Saytzeff or Zaitsev??

[@solshinez]

both spellings are valid

[@FBR2169]

6:22 why is the major product Hoffman????

[@jadesamanta7717]

The big, bulky base (tert-butoxide) cannot penetrate into the center of the molecule to deprotonate those Hydrogens (remember, the space-filling model: those electron clouds in the middle carbons are large). So, the only H the base can reach are the terminal ones on the end. Therefore, the Hoffman product forms, even though its technically less stable than Zaitsev. It is the only E2 reaction that can feasibly take place there.

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Hindered! like a got dam bush!

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