Solve Globant PySpark Interview Question | Apache Spark |

[@user-ic2ft8ed1r]

from pyspark.sql.functions import from_json,col
df1 = df.withColumn("Parsed_JSON",from_json(col("address"),"street string,city string"))
df1=df1.withColumn("Street",col("Parsed_JSON").street).withColumn("city",col("Parsed_JSON").city).select("*")
display(df1)

[@sreenivasm9931]

Globant 😂😂😂😂😂. Such a worst and ruthless company I ever seen. This company forcing their employees to resign without compensation.

[@vaibhavverma1340]

res = df.select(col("name"), json_tuple(col("address"), "street", "city")).toDF("name", "street", "city")

[@amanpirjade9]

Make pyspark video for beginners to advanced

[@GeekCoders]

Please check my databricks and pyspark series

[@cnureddy4078]

Col("parsed_json.*") Instead Col("parsed_json").*...this should work

[@GeekCoders]

Thanks for it. I was writing the same but didn’t see that I wrote parsed_json. Thank you