Simultaneous Equations Matrix Method : ExamSolutions

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Simultaneous equations Matrix method.
How to solve Simultaneous Equations using the Matrix Method.
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[@autonerecords1410]

i have for some completely unknown reason taken math on for an attempt at getting into a engineering bachelor at 62. These videos are helping me get in deeper and deeper. Thankyou ..i think? Seriously great tutorial 👍

[@ExamSolutions_Maths]

Mainly A-level. What you see at present is all I have. I intend to cover the further maths later this year.

[@almanyanyukwenihango7896]

Sir I still don't understand how matrices work and I am about to face my exam

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you are a living legend

[@ozzyfromspace]

Thank you! I'm doing machine learning and we're right at the beginning, doing linear regressions and such, and we've gotten to the point where we're using normal equations to solve for the model parameters using matrices. I hadn't touched matrices in years really so I was really fuzzy on the mechanics. I appreciate the brush-up :)

[@ExamSolutions_Maths]

Pleased to hear it has offered some help. Good to also hear about real life applications.

[@ExamSolutions_Maths]

Well done and good luck at uni.

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Your explanations are so much more understandable than my teacher's explanation. Thanks a lot for all your help! ;)

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I am pleased to hear it helped.

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Thanks

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Only person who explained this properly

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Second thaat

[@eduardosilva4814]

11 years later this video is still doing wonders :)
Thank you for the explanation, your videos about matrices will be very useful on my linear algebra exam

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[@ExamSolutions_Maths]

You're very welcome!

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[@ExamSolutions_Maths]

Good luck

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May d almighty bless d work of yr hand

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[@ExamSolutions_Maths]

Yes

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This really helped me out ...

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[@WatchmanEl]

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this helps alot.

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If I continue to get support then I will.

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[@leophelan6768]

great video I understood the textbook but I need to see it worked through and you provided it perfectly.

[@ExamSolutions_Maths]

Happy to hear it helped Leo

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[@ExamSolutions_Maths]

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very complicated explaination

[@AHSK-yh5ch]

If for the values that switch would their signs switch as well. And if the signs that switch, what would happen if there is no sign to swap around

[@amitkshankar]

Thank you - Brilliant
Your video helped me to understand the concept in python :)
import numpy as np
A = np.array([[5,-2],[7,6]])
c = np.array([[16],[-4]])
print(np.linalg.inv(A).dot(c))

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[@ExamSolutions_Maths]

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[@ExamSolutions_Maths]

That's okay. Thanks for watching.

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Thank you sir

[@jayagnihotri5807]

@meganthompson x=3 y=7.
I did it lots of different ways, matrix method as Mr S demonstrated works out.

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This is correct Megan Thompson

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[@ExamSolutions_Maths]

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Helpful

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[@ExamSolutions_Maths]

Thanks

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[@ExamSolutions_Maths]

No worries!

[@roukyntentie490]

Thanks

[@meg_anthompson6300]

Hi, I was wandering how would you work out this equation:
5x+3y=36
8x+2y=38

[@madpheasant47]

Just the same way, x=3, y=7

[@mybishthing]

can you please do one for matrices with no solutions, one solution, infinite solutions when there is an unknown constant in the square matrix!

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[@YashVerma_twistedsoul]

So what if our equation was a singular matrix, we couldn't find the values of x and y then?

[@btgkeim039]

When changing A into inverse , weren't you supposed to change signs of the major diagonal?

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Thank you

[@ExamSolutions_Maths]

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Thankyou.

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Thank u

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[@ExamSolutions_Maths]

Best wishes

[@jaced5989]

I followed step by step and still got, -10.7 , -9.6 for
2x + 3y = 18
3x + y = 13
The answer is supposed to be 3, 4
Idk how I got mine…….

[@jayagnihotri5807]

ExamSolutions
Sir is it possible to have a simulataneous equations that cannot be solved by matrices which has no solutions, one solution, infinite solutions and where there is an unknown constant in the square matrix?
Finally can there be imaginary roots for matrix equations?

[@Playlist_Two]

Not all pairs of simultaneous linear equations have solutions:
If the equations are inconsistent,
(their graphs are parallel and thus do not cross)
or, if the equations are dependent,
(the graphs coincide and thus do not cross at a single point)
the determinant will be zero.
If the determinant is zero, there will not be a solution.
I know this answer is literally 7 years too late but someone else peeping the comments might be interested. 🤣

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Thank you and best wishes

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Legend

[@king0vdarkness]

for 3x3 do you have to do another method?

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Yes
Do want solution ???

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Tonkaabirira

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How did you find 16 and -4

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