Projectile Motion - A Level Physics
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- čas přidán 22. 05. 2012
- A description of projectile motion, how a bullet or ball fired at an angle to the horizontal will travel through the air, and how to describe its trajectory. A full set of A Level Physics Revision videos is at • A Level Physics Revision
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Very clear descriptions here that have really helped the students I teach. Thanks.
A Level Physics Online Thanks. Kind of you to say so.
Yo Physics Online stop stealing content off the real GOAT
when i looked at this tutorial... the thought came to my mind was...
"if i had such video 20 years back" learning would have been more easy and interesting.. i have always loved physics
:)
nice job..i hope kids of this generation make ample use of such great videos.
I haven't done these calculations in 20 years. My son is now in AP Physics and needed my help. This was exactly what I needed. It is very well done and I am truly grateful for the refresher.
As level people where are you at 🌚
Neeeeeeerrrrrrrrrd
@@imamgiuseppe5103 Geeeeeeeeeeeek 😪
So since 3 years passed what was your a level grade? 😁
Sir u r in which country
I've just chosen A level
My Ib Physics test is comming up. All i can say is I love you for making this video
Thanks. I hope it went well.
I actually used this to help me with my NAPT test for the navy Thanks I needed a refresher
I absolutely love the way you teach- it's all very easy to understand because you explain each step in the working out of a solution. You earned yourself a subscriber! Keep it up!
I love the simple, clear no fluff teaching style. It reminds me of how I was taught back and school and later in sixth form. Thank you for your vids.
I'm just starting out teaching AS Physics from GCSE, wow your videos are amazing! Clear, fully relevant and no nonsense.
Thankyou and I look forward to watching more of your videos as I progress.
This is my first quarter of physics (in college and never took in high school) and I was really struggling to understand or follow anything that was going on. In this 30 minutes video, you cleared so many things up for me, I can't thank you enough!!!
How’s life now
"And on that sad note, I hope that's been helpful." Haha, humorous and educative...thanks for the video!
I'm replying to your comment because I want you to look back in time
Damn, you commented 7 years ago, are getting any kind of nostalgia
@@A.K9488 And you commented 10 months ago, how're you feeling?
@@ranonymous27 Feeling terrified and depressed
Have my AS physics exam in 4 days 💔
Please pray for me 🥺🤧
@@A.K9488 I'll keep you in my prayers InshaAllah. Just wake up early, and utilize all the time you have revising and solving past papers, focus on the topics you find difficult and solve topicals for them, then leave it for God. Hope everything turns out well, I'm rooting for you, you've got this!!
@@ranonymous27 Thaankyou soo much for the kind words❤
You're soo nice
I'll try my best 🥲
You, my friend, are a life-saver! Thanks for creating and compiling all these videos together!! :)
29:10 RIP Harambe :'(
35:58
For most questions on A-level physics projectile motion we make the assumption that there is no air drag or other forms of frictional resistance.
a powerful teacher....i always recommend my fellows to use this channel
Thank you so much for these videos! I am a student at high school in the Czech Republic and I am taking leaving exam in a few days. Without you, I would be lost. I did nothing for last 4 years.. and now, I found my textbooks so uninteresting. Your videos don't give me just information, but also motivation to study. :)
I’m just starting on my engineering after a long years of gap, I find your videos very helpful. Thank you so much sir😊
A huge lifesaver, thank you so much for taking the time in making this video!
Best physics teacher ever. You explain everything so clearly.
so today i had a quiz in my AP physics class and i didnt know anything about the topic we were on because i was in the hospital for almost all of it and i watch this in the morning and i saw my grade after i took and i got a 14/16 and thats without the curved so thanks to you i got a good grade because of how well you explained this. so thank you so much for the taking the time to upload this video :)
Thanks and well done.
no, thank YOU
Yes. That is Newton's first law: a body continues in its state of rest or uniform motion unless acted on by an external force. So if no friction - and assuming the ground was flat - the ball would just continue to roll along the ground at uniform velocity since no forces would be acting in the horizontal direction.
This is an extremely helpful video! I'll surely go through this channel whenever I find difficulties in my A levels course. Thank you!
Thank you so much for this lecture, it is much appreciated. Projectile motion used to be my weak point for mechanics 1 in physics, but this video has helped me grasp it and now in mathematics mechanics 1 it's possibly my favorite topic!
This is one of the best videos I've found on projectile motion. Great job and thanks.
Thank you so much! You've allowed me to understand in 10 minutes what I've been struggling with at College for a month.
the best youtube video you can ever find for projectory motion
11 years later- still a legend.
I am a non physics specialist teaching A level physics for the first time this year. I'd be lost without your videos!!!! Thanks very much for such a great resource!
I'm very grateful for your kind feedback. I am also glad that the videos are being of some help.
I am really thankful to you for giving lecture free of cost.It developed my concepts on projectile motion.Sir your lectures makes it an ideal foundation for those students who intend to take their studies to a more advanced level.Physics is my favourite subject.KEEP IT UP!
hi, I'm a junior in high school, and physics is my hardest class right now, for a number of reasons, but mainly because I don't have a very good teacher. Thank you so much for posting this video, it helped clear up a lot of my confusion in projectile motion. You've accomplished in 36 minutes what my insufferable physics teacher couldn't in three weeks.
Well that teachers gone now😂
You just earned yourself a new subscriber!
This guy is super good at explaining physics. HELPED ME A LOT. Thank you
You are AMAZINNGG!! You have cleared all my doubts regarding Projectile Motion. My Physics teacher should watch your videos and learn how to teach. You are a life saver!
Thank You so much!
May God bless You! :)
This has got to be the best video for projectile motion! Thanks Sir
I would recommend this video to all my Physics classmates this clears up a lot of things, thank you very much :)
Oh my gosh. i just wanted to take a minute to say thank you. i have just started to watch these because i have been really struggling with my physics. THANK YOU :') you really helped, thank you so much! ^_^ -Yanna from Cyprus! Subscriber gained:}
Got my exam tomorrow, this really helped to make me feel more confident
Thank you for clarifying all of the formulas!!
My best compliment for the clarity of your tutorials. I've followed this video and it's everything crystal clear. You mentiioned that the distance is the same for all angle θ and (90 - θ). I stuggle to prove it mathmatically but I was unsuccessful. May you show me how to do so? Thank you very much, and thank you again for your video!!!
Many thanks. I'm delighted they have been of some help.
This massively helped me tonnes, I'm resitting AS but I found your channel literally days before the exam! Gutted was an understatement. There's a question type bothering me at the moment with projectiles, where the horizontal range is extended by the height of the drop being longer on the second side of the parabola. If you or anyone else can help it would be immensely appreciated.
There are 3 parts to the question, a) and b) I have covered, it's c)
An Athlete is performing the long jump.
Horizontal Velocity= 8 M/S
Vertical Velocity= 2.8 M/S
a) Show that the total time the athlete spends in air is around 0.6s (assuming his centre of gravity is at the same height as it was at take off)
b) Calculate the horizontal distance jumped by the athlete.
c) In reality, when the athlete lands his centre of gravity is 50cm lower than its position at take off, calculate the extra horizontal distance this allows the athlete to jump.
Its been 8 yrs and no one answered😅
Thank you so much. I learned more from this 36 minutes than I did in 6 hours of physics class per week.
Thanks, this kind of explanation is what I wanted to hear for a long time
best physics youtuber by far
Thank you so much! Physics makes much more sense to me now.
For Jake Cosgrove: This would be for example if the trajectory were to go up and then over a cliff so the projectile ends up lower than it started. The equations still work as long as your signs are consistent. Up = positive and down = negative. So for example the net vertical distance change is negative.
Hello. I want to search the approximate methods in quantum mechanics in particular the Hartree method, Hartree-fock method ab initio and density function theory . Possible to help me.
DrPhysicsA oo
Thanks. There is a full set of my A Level Physics Revision videos. I have put the link in the description above.
Wow this has been helping people out for years. I remember my physics 1 course looking at this vid.
Thank you so much for helping me understand this! It really helps and the video is very thorough!
Thank you soo much ! :) I understood more in 10 mins of this video than 2 hours in class. :)
You are fantastic. This is helping me pass my physics subject at Sydney university. Many thanks.
you are a man of letters in physics. I admire you sir.
I like your videos. Thankyou for sharing. Your generosity towards others is appreciated.
Amazing video. Thanks so much, you make it fun and interesting which I didn't think physics could be until I saw this video. You have restored my faith in this science subject.
Thank you so much for this clear and easy to follow video. I'm taking the MCAT soon and my physics needs some refreshing.
Your explanation was clearly explained and included all the required details. Thanks very much.
Oh my goodness, what I can say is that they have not been of "some" help, but rather A LOT OF HELP! Thank you, thank you so much! I finally understand this topic! =D
ur r great sir i have been back of this chapter for a long time but nothing was going to mind but ur teaching helped me gain back intrest in physics
thanks you so much for this video :D it really helps that you sound a bit like sir bruce forsyth (in a good way) and so I now have your voice repeating this lesson in my head when I see one of these projectile questions, thanks again :D
Ur video tutorials are the best..thanks dr physicsA
you have explained the projectile motion to a very good depth and it has cleared all my the ambiguities that i had with this topic Sir thanks
This was an amazing video, very well explained thanks a lot!
I need to meet you if possible
Thank you so much for your videos, you explain it really well and everything is alot clearer now, thank you!
The ads kept on saying, 6 year old math problems doesn't help. Well, for me 90% of the things i learnt was because of the old videos. ^^ THANK YOU MR.!
As others have said, in the SUVAT equations each one misses one of the 5 terms. Generally, the question you are asked to solve will enable you to determine which one to use. You will be given some variables and asked to find another. Find the SUVAT equations which covers that group.
dude u r awesome. I understood all... thanks to u.
+MRA 7 a real lifesaver!
Thank you so much - never understood this and ive got my retake coming up (got a C beforehand)... thanks to you im aiming for an A :D
Very useful video!! Stuff I considered tricky is explained here step by step, helped me a lot, many thanks.
DrPhysicsA, I LOVE YOU!
Much much better than my physics teacher...thank u very much sir for your valuable video
the video is specifically clearand i understood the equations and the methods of it. i gradually thank you
Extremely Helpful
5 years late, but this has helped me so much. THANK YOU SIR
The sad,sad tale. Ahaha,love the humour mate.
Your videos are entertaining + educational (of course). Wish I thought of watching these videos way earlier so I didn't have to repeat my exams again in January. :< Hoping to get all A's this time and I am actually confident I will after watching your videos. c:
And if you don't mind, please give me some tips please for Edexcel AS exams :D
One bit that might confuse is that the launch angle resulting in the same range applies to any 'complementary angles' like 30 and 60, but not to others (45 degrees gives you a longer range, and 90/2=45 so it is its own complementary; but 20 and 40 for example would have different ranges)
This is gold. Thank you!
Thank you so much !!! you saved my life . Finally i understood it
Thank you soooooo much!!!!!! I finally get it now.....yassssss!!!!!!!! And I just subscribed too
thank you very much, pls make more vids like this it helps save lots of life :D
As the projectile describes the arc it has a horizontal and vertical component to its velocity. The horizontal component does not change. The vertical component gets smaller as the height above ground increases. So the tangent of the angle will decrease.
Thanks for very kind words. Glad to have helped. Physics is fun.
Not if you are talking about each being the same range (ie horizontal distance) from the source. The reason is that time taken is determined by the horizontal component of the velocity which doesn't change (since there is no horizontal force acts on it).
Your ways of teaching make this so easy to learn, thank you for uploading these videos. I have been thinking about going to university to study Physics, and have gained my qualifications to become an electrician, will a lot of this relate?
thanks for making such a wonderful video it really helps
very educational indeed , great work !
Physics and you are really helping me!! Thanks
Thanks for the kind comments. Stick with it. It's a great subject.
omg ur soo good at explaining ur even better than my university professor !
THANK YOUU soo much !!:D
I hope so. My videos cover the bulk of the syllabus of most of the A-level physics courses. But at present they only cover a small amount of the physics that would be taught at university. Thanks for your comments and good luck for the future.
PEACE BE UPON YOU, Sir
You are A great teacher !!
hope you will upload more video like this.
Your videos are very good but I would recommend you break them up into smaller sub categories of larger topics for easier scanning for specific topic within such a large category of 'Projectile Motion'.
Nice video for preparing IIT JEE.
thaaaanx sir.....I was absent in these lectures this video helped me a lot for the midterm
Yes. I do not separate the two because the playlist attempts to cover material required for a number of different exam boards including AQA, OCR, Edexcel, CIE
the poor monkey sacrificed himself in the name of physics, but did not die in vain, for we all learned projectile motion from his death. what if the projectiles mass was insufficient to penetrate the monkey? then he'd have a red spot underneath his hair. all joking aside this was a very excellent presentation of ballistics in general. I loved the step by step processes our astute professor led us on. well done, thank you for not taking your viewers knowledge for granted and omitting necessary steps as some of our instruction is presented these days at least in my experience sometimes. I am a faithful subscriber sir.
This explanation is awesome and interesting.... thanks for saving me with it!...... would you describe any of ur video about resultant? would you n't mind telling me about vertical and horizontal component..... also about according to formula v=u+at, where V is final velocity or just velocity.....
Thank you so much for ur time Sir. I might not fail physics now.
+Dark Sky Hope the exam goes well.
+DrPhysicsA
Are you still going to post more videos?
Isn't it a class 9th topic. Cause it is so easy
@@mannyheffley9551 mate, I was learning how to expand brackets in year 9. This is more A level based.
Thank you so much sir... Nw I hv got the concept much clearly than what is being taught in the class...nw I feel better before I was very scared n nw it's going Gud thank so much sir
Thanks for making this easy to understand
Why, from the start of the video, is the vertical component equal to v•sin■ and the horizontal equal to v•■ ?
This is so helpful and clear! Thank you so much!
Thanks.