Dex- First, thank you so much for all the hard work and time you spent dedicating to uploading all of these videos. I will be sending you a donation on Patreon soon! The only bit of constructive feedback I have to offer is the volume is a little low sometimes. I don't know if it's the specific microphone you are using, your mouth is too far away from the mic, or something else, but it can be hard to hear even when I have the volume turned up all the way. Beyond that, great job, my friend. Bravo!
the 400 N force is a vertical force, so it is multiplied by the vertical length (4 m). The 300 N force is a horizontal force so it is multiplied by the horizontal length (5m).
I know this is super late lol. But the reason he did that is because why are actually looking at cos(theta) for the y-component at F3 which is 4/5. Just look at the triangle and you will see this. Now for the x-component of F3 you use sin(theta) or 3/5.
i know this is a year ago but, for anyone else, if you're thinking this way, or having this issue, you're trying to think about cos and sin as specific to the X and Y axis, when they are for triangles. Cos is for finding the side of the triangle adjacent to the angle. Not for the X axis. In this case, the way the angle is represented, the Y side of the triangle is adjacent to the angle given. For F2, the X side of the triangle is adjacent to the angle. Remember cos(theta) = sin(90-theta) for triangles and shit i think actually i just made that up but try it its true
Sin and Cos come from Trigonometry. Cos is used to find the opposite side from the angle of the triangle, while Sin is used to find the adjacent from the angle.We split up the forces into sides of a triangle using trig
i dont understand why you use cosine instead of sine for "F1y", and sine instead of cosine for "F2y". I also do not understand why you dont use x-forces for F1 and F2?
Dex-
First, thank you so much for all the hard work and time you spent dedicating to uploading all of these videos. I will be sending you a donation on Patreon soon!
The only bit of constructive feedback I have to offer is the volume is a little low sometimes. I don't know if it's the specific microphone you are using, your mouth is too far away from the mic, or something else, but it can be hard to hear even when I have the volume turned up all the way. Beyond that, great job, my friend. Bravo!
thank you so much
thank youuu so much for the video!
Dude, super helpful thanks
Hey bro after 6 years you have a student like me keep going you have a best teaching ever! Your the best i love you!
You are amazing 🤩
Awesomely explained!! thank you so much!!
You a real G
Very helpful broo, Thank You!.
Thank u
quick question. im confused on why Force B along x is making it go CCW, Since the force is pointing right shouldn't it be CW?
perfect, thanks!
Where is the answer to your question??
I dont understand why the distance for moment at A y axis is 5m while the other one is 4m.
the 400 N force is a vertical force, so it is multiplied by the vertical length (4 m). The 300 N force is a horizontal force so it is multiplied by the horizontal length (5m).
how cosΘ can be used to find Fy.....isn't that for Fx and sinΘ for Fy. I am confused:(
I was thinking the same thing!
thanks
sound quality is Very law in your all video..
Why are you using 400 instead of 300
?I'm a bit confused! why did u multiply the y at F3 with 4/5, while the sin(theta) is 3/5
sin is 4/5 theta is between 4 and 5
me too
sin is opposite/hypotenuse which is 3/5
cos is adjacent/hypotenuse which is 4/5
right???
I know this is super late lol. But the reason he did that is because why are actually looking at cos(theta) for the y-component at F3 which is 4/5. Just look at the triangle and you will see this. Now for the x-component of F3 you use sin(theta) or 3/5.
i love you bro
Why is it that for F1, you used cos to find Fy and not sin? Also for the corner of F2, why does that become sin to find the Fy?
i know this is a year ago but, for anyone else, if you're thinking this way, or having this issue, you're trying to think about cos and sin as specific to the X and Y axis, when they are for triangles. Cos is for finding the side of the triangle adjacent to the angle. Not for the X axis. In this case, the way the angle is represented, the Y side of the triangle is adjacent to the angle given. For F2, the X side of the triangle is adjacent to the angle. Remember cos(theta) = sin(90-theta) for triangles and shit i think actually i just made that up but try it its true
@@FlorecentTurtle yo I know your comment was a year ago, but here I am asking the same question, thank you for your explanation!
This problem was on my first test this semester (2nd time taking statics) and I got it wrong FML
you need to explain how you are getting sin and cos for the first 2 forces.
Sin and Cos come from Trigonometry. Cos is used to find the opposite side from the angle of the triangle, while Sin is used to find the adjacent from the angle.We split up the forces into sides of a triangle using trig
I still confused to calculate force 3 with point B
i dont understand why you use cosine instead of sine for "F1y", and sine instead of cosine for "F2y". I also do not understand why you dont use x-forces for F1 and F2?
Its like the components of vector opp to vector is sine of vector
Problem 4-105
Replace the loading system acting on the post by an equivalent resultant force and couple
moment at point P.
please give the solution