As del h is verry verry less then del s we can say side surface area =~0 ..so we can ignore side integration ..symmetry can't make side integral zero...and your video is helpfull for me..thanks and keep it up😍😍
Well understood sir.....😍😍😍 Sir kl paper h nd ye bot imp topic h aur bada v bt ab jakr acha feel ho ra apka video dekhne k bad..😊 sir ur way of teaching is really appreciable
I have some doubt Sir..Plz clear it.. 1) Why energy density is different in both medium? Is it not against the law of energy conservation.. 2) It is said that 'D' is medium independent, then why its value is changing on changing medium..Why Magnitudewise D is not same?? Plz reply Sir..Thankyou..
You did not show why the line integral of the electric field is zero, because Faraday's law dictates that this line integral is equal to the time derivative of the magnetic field.
super work u have done with big fault! if your camera would be fixed every thing could be more n more effective. by the way your quality is superb.........thank you.!
You can, and the result will be the same. Aka, the flux cancels out due to the symmetry of the faces of the cube. It is simpler to understand with cylinder because of the intuitive symmetry.
EMT Hi, Can any one tell me why the net flux from the curved surface of the cylinder is considered as non-zero while calculating the electic field applying Gauss Law but flux from the same curved surface is considered as Zero while finding out the Boundary Conditions for dielectric - dielectric interface.
Rudraprasad Pani. In guass law we consider line charge coming out of top bottom and side in which top and bottom is zero.. But in boundary condition we are taking surface charge density for which cuveture part is zero due to symmetry(equal and opposite direction )
Bhai tengential electric field nikalte samay hamne line integral Liya tha aur normal component nikalne ke liye surface integral Kiya hai waha electric field ka normal component wala term height negligible hone ke Karan khatm hua hai
here we use cylindrical closed surface, we take differential surface ds on the curve surface assume on right side and it's direction is unit normal vector I.e same as tangential components of D in same direction...But when we take differential surface ds on left side of this assumed Gaussian surface it's unit normal vector is opposite to the tangential component of D Vector... so after adding such equal and oppsite components around a closed surface there is a cancellation...which is due to the symmetry of cylindrical curve surface......hope u got it......thanks....
Excellent drawings and explanation, thank you so much for making this video, greetings from Mexico
Watch in 1.5x to save time
in 2x bro
@@gurjotsingh5924 definitely 2x
As del h is verry verry less then del s we can say side surface area =~0 ..so we can ignore side integration ..symmetry can't make side integral zero...and your video is helpfull for me..thanks and keep it up😍😍
In that Gaussian surface D1n is in the same direction as D2n (which is explained otherwise).. it's the bottom area which is in negative direction.
Absolutely amazing explanation. Thank you so much.
Well understood sir.....😍😍😍 Sir kl paper h nd ye bot imp topic h aur bada v bt ab jakr acha feel ho ra apka video dekhne k bad..😊 sir ur way of teaching is really appreciable
What an explanation !
Thanku sir 🙏😊
I have some doubt Sir..Plz clear it..
1) Why energy density is different in both medium? Is it not against the law of energy conservation..
2) It is said that 'D' is medium independent, then why its value is changing on changing medium..Why Magnitudewise D is not same??
Plz reply Sir..Thankyou..
I have same doubts, did you clear them yet?
a perfect explanation of the topic.
thank you so much sir 🙏🙏🙏
Thanks a ton 😇
Integration over Edl is not equal to zero.... it is the emf generated in a loop... i.e - dB/dt.
Best explanation
Thank you for this wonderful video
You did not show why the line integral of the electric field is zero, because Faraday's law dictates that this line integral is equal to the time derivative of the magnetic field.
Marvelous explanation sir
How the closed integration of flux density D around the closed surface becomes zero? You said due to symmetry. But how? You didn't explain.
your video is really good and helpful . Can i get more questions on this types of problems or can you suggest the book for this ??
Nicely explained
Tysm sir
Awesome Explaination!!!😘😘😘
Thanks sir.. for wonderful vedio
Thankuuuuu sooooo muchhhh, its helpp m a lotttt lots of love from my friends shabih and rana hassan
super work u have done with big fault! if your camera would be fixed every thing could be more n more effective. by the way your quality is superb.........thank you.!
this video do not deserve dislikes
sir , 'row s' is the surface charge density of interface , not the cylinder , and thanks for the video , its very helpful
Thank you so much sir very good explaination
Awesome explanational
Awesome...easily understood
i am sure this dude is using BIBLE of electromagnetics........."n. o. SADIKU"
its a book btw
I AGREE
Awesome video! Thanks a lot.
Great video man keep it up
why should i take cylindrical gaussian surface? and why not a cubical gaussian one?
You can, and the result will be the same.
Aka, the flux cancels out due to the symmetry of the faces of the cube. It is simpler to understand with cylinder because of the intuitive symmetry.
That chap won't reply because he doesn't know.
Thankyou so much sir
Thanku so much sir ❤
thanks sir
Thanku sir ur lecture is nice
Superb class sir
very well explanation
Nicely explain
Sir could please provide link for lecture notes
informative...thank u sir!!
Thank you sir
EMT
Hi,
Can any one tell me why the net flux from the curved surface of the cylinder is considered as non-zero while calculating the electic field applying Gauss Law but flux from the same curved surface is considered as Zero while finding out the Boundary Conditions for dielectric - dielectric interface.
Rudraprasad Pani. In guass law we consider line charge coming out of top bottom and side in which top and bottom is zero.. But in boundary condition we are taking surface charge density for which cuveture part is zero due to symmetry(equal and opposite direction )
Bhai tengential electric field nikalte samay hamne line integral Liya tha aur normal component nikalne ke liye surface integral Kiya hai waha electric field ka normal component wala term height negligible hone ke Karan khatm hua hai
thank u sir........super lecture
but feeling somewhat slower
keep in 1.5x speed
At 23.26 sec why we r taking minus sign there even there is no tangential normal component in region 1 how can we indicate the direction of normal d
Expression for Q in pillbox not explained well :(
Can you share pdf file this lecture
Tq sir
Sir, Can I get your notes?
Thank you so much sir
Will u pls explain cancel due to symmetry...in cylindrical system?
here we use cylindrical closed surface, we take differential surface ds on the curve surface assume on right side and it's direction is unit normal vector I.e same as tangential components of D in same direction...But when we take differential surface ds on left side of this assumed Gaussian surface it's unit normal vector is opposite to the tangential component of D Vector... so after adding such equal and oppsite components around a closed surface there is a cancellation...which is due to the symmetry of cylindrical curve surface......hope u got it......thanks....
EPOV CHANNEL thank u so much
it is not all due to symmetry,it is because "delta s" is perpendicular to the "D",so dot product will be zero.
Is this about boundary conditions for two lossless media
Can you provide your notes please
closed line integral of Electric field is zero this is not the maxweĺls equation.
2:13
Can you please provide them in PDF form please sir
sir ap jo lecture banate hai uska notes nhi hai sir
Bahut aachha matter ha thanksssssssssss
Tq so much
Helpful 👍👍
sir are these boundary conditions for finite conductivity media or infinite conductivity media?
Can U Give me the soft Copy of these Notes ???
thank you
Interesting
Very nice sir ji
very nice
Great
very good sir
thanks
Good
Sir hindi mixed english. Ma videos
D is electric field density h na sir
D is electric flux density.....
I also confused here😅
Bro can u tell me the name of the reference book plzz
Mattew Sadiku
Sir apki notes Ka pdf mil Jayega kya
Sir uses ....book by sadiku
Could plz share pdf file
Too slow. Getting bored. Wasting my time.
thank you sir