NCCER Level 1 Module 8 Introduction to Building Envelope Systems (Section 1)

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  • čas přidán 22. 08. 2024

Komentáře • 3

  • @nahidsanaei1037
    @nahidsanaei1037 Před 2 lety

    Thank you for the videos. I have been watching them and learning! One thing that no matter how I calculate is the window opening of 5.7’ while min opening hight is 20” and min opening width is 24”! I wish you or someone would explain the math. Thank you.

    • @billryan6030
      @billryan6030  Před 2 lety +1

      Hi Nahid,
      You know, I struggled with this as well for a while. Then I went back to the code book for an interpretation. It still wasn't clear.
      Here is what I have learned and applied to this "math" inconsistency. You are correct- when you multiply 20" minimum height(1.667 or 1"-8" ft) and 24" minimum width (2-0" ft) you get 3.33 sq ft, far less than the 5.7 sq ft code requires for openable space.
      So think of it this way instead: If you want t 24" (2"-0") min. height for your egress window you will need to make up the difference with a width of 2'-10 1/2" (34.5") width to gain your 5.7 sqft of openable space. Conversely, If you had a 20" (1-8") min. width you will need to make that up with a height of 3'-5" (41") to gain the 5.7sqft required.
      Code simply states that you cannot be narrower than 20" in width or shorter than 24" for a window used for egress.
      I hope this helps.
      BR

    • @nahidsanaei1037
      @nahidsanaei1037 Před 2 lety

      @@billryan6030 thank you for the great explanation.