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Mechanical Engineering: Particle Equilibrium (12 of 19) Pulleys and Mechanical Advantage

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  • čas přidán 6. 08. 2024
  • Visit ilectureonline.com for more math and science lectures!
    In this video I will calculate the forces and the tension of pulley systems.
    Next video in the Particle Equilibrium series can be seen at:

Komentáře • 178

  • @maxheuser4968
    @maxheuser4968 Před 9 měsíci +7

    The free body diagram is key to the analysis. And it vastly simplifies the calculation. Just learnt something new ..... at age 70. Never too late

    • @MichelvanBiezen
      @MichelvanBiezen  Před 9 měsíci +2

      Yes. I am having fun learning things I didn't understand as a student. 🙂

  • @alexanderson8701
    @alexanderson8701 Před 7 lety +21

    I watched a similar video on this subject by DrPhysicsA, and I ended up being confused - many thanks for clearing up my confusion with your clear explanation.

  • @prachikhandelwal146
    @prachikhandelwal146 Před 7 lety +8

    you are awesome Sir I used to afraid from dealing questions on pulley system. but you clear my concept... thanks

  • @jamesstockton7986
    @jamesstockton7986 Před 4 lety +1

    That was the clearest explanation of pulliys I have seen.

  • @rameshhariharan2623
    @rameshhariharan2623 Před 4 lety +3

    great. easy to understand by all. great explanation . thanks sairam sir

  • @guloguloguy
    @guloguloguy Před 4 lety +6

    Thank you, very much, for this very practical lesson!!!

  • @edgelordrob
    @edgelordrob Před 2 lety +4

    These videos are really good I was feeling like there was something I was missing in regards to my education about pulleys and this is it. He really shows why pulleys work and not just how.

    • @MichelvanBiezen
      @MichelvanBiezen  Před 2 lety +2

      Glad you liked the video!

    • @xmo552
      @xmo552 Před rokem

      @@MichelvanBiezen
      I have a question about the last 2 free body diagrams. On the 4th one; why did you split it beneath the middle pulley while on the 5th one you split it above the middle pulley ?
      Edit:
      Nevermind 😁 it was the last thing you said.

  • @yonatanshenhav1208
    @yonatanshenhav1208 Před 4 lety +2

    a very clear explanation. thank you for making this video

  • @ESN1961
    @ESN1961 Před 4 lety +1

    Michel, спасибо Вам и Архимеду!

  • @ouvidofreitas7815
    @ouvidofreitas7815 Před 7 lety +1

    This professor is the best!

  • @longlong1149
    @longlong1149 Před rokem +1

    Good theory. I remember the days at the end of junior school. That's cherished memory.thank you.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      Thank you. Glad you enjoyed it and gave you some good memories. 🙂

  • @Aarsha112
    @Aarsha112 Před 4 lety

    You're really great sir

  • @valveman12
    @valveman12 Před 4 lety +2

    Great video, thank you :-)

  • @MazielRodriguez
    @MazielRodriguez Před 3 lety +1

    Flawless :) thank you

  • @vegaswajeel1
    @vegaswajeel1 Před 4 lety +1

    If the second pulley had 4 pullies instead of 2 in the same sequence would the force be .25 vs .5? Similar to the 4th example?

  • @internetrules8522
    @internetrules8522 Před rokem +2

    Pulley system 2 was a mindblow to me. I managed to predict 50 newtons on each end of the rope because you taught us that all the ropes have to have the same tension, and i predicted 50 newtons on the left rope attached to the ceiling, but had no idea what the weight on the right rope attached to the ceiling would be and was really surprised at 150 newtons total force.
    I think the way it works is like: In pulley system 1, we have 100 newtons of force pulling down (the weight), and 100 newtons of force pulling up (50n from ceiling 50n from person pulling)
    But in pulley system 2, there is 150 newtons of force pulling down, the weight (100n), and the person pulling (50n). half of the weight is going into the ceiling, which means the other half HAS to be going into the pulley, and the person pulling is ALSO putting 50 newtons into the pulley, so it has to be holding 100 newtons.

    • @internetrules8522
      @internetrules8522 Před rokem +1

      Third pulley system predictions: it's gonna be 33 in each rope, the top pulley is going to be holding 66 newtons, and the person pulling would be lifting with 33 newtons. so 3x mechanical advantage.
      Fourth pulley system predictions: The bottom pulley is connected to 3 ropes, so that has to be 33n in each rope. The middle pulley is 2 of those ropes, so that has to be 66n newtons from the middle pulley pulling on the cieling. The top pulley is holding 33n from just the weight, but if we also add the 33n from pulling on the rope it will be 66n. So middle pulley is 66n, top pulley is 66n, for a total of 132n on the ceiling
      This feels wrong and like more mechnical advantage should mean more weight on the ceiling, but more mechanical advantage literally means we have to put less force into the system. we are only addding 33 newtons of down force into the system by pulling down with 3x advantage, where as when we had 2x advantage we had to put an extra 50 newtons of down force into the system. So more mechanical advantage weirdly enough means less strain on the system because it's being divided up more i guess.
      Fifth pulley system predictoins: I flipped the video vertically and it seems to literally just be the fourth one but upsidedown, so that we are pulling up instead of pulling down. as an initial guess that should mean only 100n in the cieling cuz we are removing our downforce, but that shouldn't be possible cuz we are lifting a fraction of the 100n so the cieling can't be supporting all of it.
      Oh i forgot to also add the upforce instead of just removing the down force. If we represent downforce as negative upforce, then we went from -33n to 33n, for a difference of 66n, but i only did a differnce of 33. So my initial guess should be that the ceiling is holding 66n.
      Ok now to actually try to figure out whats going on: the bottom pulley is directly connected to the middle pulley, so pulling on the middle pulley by 1 is just as good as pulling on the bottom pulley by 1.
      I see 3 things coming out of the bottom pulley, one of them being our up force, so i FEEL like we should be lifting 33n but one of the things coming out of the bottom pulley is just a direct connection to the middle pulley.
      So really, if we consider that pulling on the middle pulley is just as good as pulling on the bottom pulley, and we consider that the middle pulley has 2 connections to the top pulley, and the bottom pulley has 1 connection to the top pulley, that's just as good as if the bottom pulley had 3 connections to the top pulley. We also have 1 connection to the person pulling the rope, who is applying an up force. so it should be 25 newtons of force being pulled, and 75 newtons on the ceiling.
      Time to see if my predictions were right i guess

    • @internetrules8522
      @internetrules8522 Před rokem +1

      Ok I think I got every answer correct, but I messed up visualizing the free body diagram on the fifth pulley system. Thank you for these videos!

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      Glad you figured it out! 🙂👍

  • @ismailcetin3253
    @ismailcetin3253 Před 4 lety +1

    I watch your videos from Turkey dear Michel Van Biezen from Istanbul Technical University and your teaching is very professional and clear. I want to say that you should consider adding a subtitle to your videos because the translation of CZcams algorith is not very clear and it may make a mistake and give us a wrong word. I encountered with lots of videos which was translated bad. Respect from Turkey.

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety +1

      Hi Ismael, welcome to the channel and thank you for the suggestion. At this time we don't have the time to work on subtitles, since both my wife and I work other jobs besides making these videos, but later after we retire, we may want to do that on the more viewed videos.

  • @faysameru
    @faysameru Před 4 lety +2

    God bless you

  • @slicenfun2968
    @slicenfun2968 Před rokem +1

    Excellent video!

  • @Imustfly
    @Imustfly Před 4 lety +5

    Not sure if you'll even see this, but here goes: In the 4th example, how can the amount of weight supported by the attachment point at the ceiling (133N) be more than the amount of weight being hauled (100N)??

    • @avcomth
      @avcomth Před 4 lety +1

      100 Newton came from the mass of the object and another 33 came from external force that is acting on the end of that rope (the line with arrow) I understood it rightaway when thinking like this 😄

    • @ashchbkv6965
      @ashchbkv6965 Před 2 lety

      You have to apply force to pull it down remember?

    • @gabrielandag5180
      @gabrielandag5180 Před rokem

      Because you have that force (F) included as weight to carry by the ceiling

    • @narendrarathore747
      @narendrarathore747 Před 11 měsíci

      Only movevable pulley can reduce the force

  • @gerardd5068
    @gerardd5068 Před 4 lety

    It would be interesting to give the ratio of the load lifting speed to the speed of the driving force F if for example we have a winch with a motor.

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety +3

      The ratio for the speed (or distance traveled) is the same as the force required to lift the load. If you need 1/4 the force you will have to pull 4 times as far.

  • @mostirreverent
    @mostirreverent Před 4 lety +1

    I understand that each side of a rope takes part of the weight but ultimately the ceiling mount should be the weight of the object divided by the mounting string in the pulling string???

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety +2

      The force on the ceiling will be equal to the weight + force (when pulling down) or will be equal to the weight - force (when pulling up).

  • @user-ji3tw6wb4r
    @user-ji3tw6wb4r Před 5 měsíci +1

    Thank you for your prompt reply🙂

  • @keatonray9140
    @keatonray9140 Před 3 lety

    Wouldn't this be isnt as effective as the last part because you are lifting so you have to multiple the gravity? I didnt go to college and just looking but am i right?

  • @SineEyed
    @SineEyed Před 4 lety +3

    Wait, so... arranging our pulleys a certain way has the consequence of imparting a net gain of force on the point of contact with the fixed plane? We effectively make the object to be displaced _heavier_ than it actually is? That's weird..

    • @ChayaKhy
      @ChayaKhy Před 4 lety +2

      Well, you´re not really making the object heavier. In short: the upwards forces need to balance completely with the downwards forces. The amount and arrangement of pulleys does not change that.
      When pulling upwards, the force we apply should be subtracted from the force the ´fixed plane´ needs to apply to keep the weight non-moving. If we pull in the opposite direction (downwards) then our force is acting in an opposite direction from the 'fixed plane' force. In order to make up for us pulling on the ceiling in addition to the weight, it needs to counteract that with an equal and opposite reaction.

  • @jryer1
    @jryer1 Před 8 měsíci +2

    Can a 2000 lbs weight dropping 2 ft, lift a 500 lbs weight 8 ft (ignoring friction)?

  • @sanskartiwari2996
    @sanskartiwari2996 Před 6 lety +4

    these pulleys look scary but are really easy to solve

  • @bahmanrafiee1667
    @bahmanrafiee1667 Před 4 lety

    thank you

  • @arunbabu007
    @arunbabu007 Před 7 lety +3

    lots of doubts analysing the first diagram
    1.how pulley is fixed
    2. rope fixed ?
    3.how load is being lifted
    4.drawing free body diagram ..how different is it from previous first diagram n first diagram of this video where tentions get divided

    • @MichelvanBiezen
      @MichelvanBiezen  Před 7 lety +4

      1. pulleys are fixed to the ceiling
      2. ropes are held in place by the force (as indicated)
      3. loads are held in place by the forces (as indicated)
      4. The free body diagrams are the same as any free body diagram.

  • @magiccards88
    @magiccards88 Před 2 lety +1

    I have a question... If in diagram 2 you switch the load and the ceiling around, do you then go from having 2:1 mechanical advantage to a 3:1 mechanical advantage?

    • @MichelvanBiezen
      @MichelvanBiezen  Před 2 lety +1

      Not sure what you mean by: "if we switch the laod and the ceiling around". We'll have to make some more examples of different pulley combinations to illustrate some other setups.

  • @user-ji3tw6wb4r
    @user-ji3tw6wb4r Před 5 měsíci +1

    I can understand the first four questions, but why should the middle pulley be included in the analysis of the fifth question?

    • @MichelvanBiezen
      @MichelvanBiezen  Před 5 měsíci +1

      The free body diagram indicates that there are four ropes at the top supporting the weight on the bottom. The sum of the tensions must equal the weight of the object.

  • @Angelogilo001
    @Angelogilo001 Před 4 lety +1

    Can someone explain why the load is attached to one pulley instead of one end of the rope?
    Thank you

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety +3

      When you take a simple example with one pulley, you will see that the tension on the rope is half the weight of the load, but if you place the load on the rope on the other side, then the tension will equal the full weight of the load.

  • @abelermiyas6994
    @abelermiyas6994 Před 6 měsíci +1

    Why did you use the second pully in the free diagram on pully system 5 and didn't use the second pully on pully system 4?

    • @MichelvanBiezen
      @MichelvanBiezen  Před 6 měsíci +1

      On system 5, the bottom 2 pulleys are connected, so they act as a single sub-system.

  • @shadowkxm
    @shadowkxm Před rokem +1

    can anyone explain how we draw the free body diagrams which determine the strings that are aiding at pulling the weight at the bottom? for example, in the example second from the left, why do we determine that only two strings are in effect, and not the third string? I feel like in an exam i could just as easily encompass the 3rd string in the free body diagram and wouldnt get the answer of 50N.
    many thanks

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      Essentially you can draw them anywhere you like. The guidance is that you draw them such that the boundary cuts through the strings (or forces) that you are interested in. In a tatic case (like this) the sum of the forces pulling upward must equal the sum of the forces pulling downward.

    • @shadowkxm
      @shadowkxm Před rokem +1

      @@MichelvanBiezen Thanks Michel. appreciate it. I think asking the question, which strings are pulling the object in the opposite direction - is helpful. thanks so much for taking the time to reply!

  • @karthikp2650
    @karthikp2650 Před 6 lety +3

    Is there any relationship between load and pulley diameter, sir please explain

    • @MichelvanBiezen
      @MichelvanBiezen  Před 6 lety +4

      The pulley diameter matters in compound pulleys.

    • @DibyarupRoy
      @DibyarupRoy Před 4 lety

      Yes they do matter when the pulley has mass.

  • @norman1826
    @norman1826 Před 4 lety

    fantastic...how do you determine the 100N the weight

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety

      The 100N weight is just arbitrary. (It is a nice round number)

  • @screechowl9605
    @screechowl9605 Před 4 lety +3

    How can you get more than the load with a suspended load? # 3.

    • @avcomth
      @avcomth Před 4 lety +2

      The additional load came from the external force pulling the end of that rope (line with arrow)

  • @genieyas5186
    @genieyas5186 Před 5 lety

    Hello my professor, is there a ploycope or document with this lectures and exercises?

    • @MichelvanBiezen
      @MichelvanBiezen  Před 5 lety +2

      No, not yet. That is something we are considering doing in the future.

  • @louf7178
    @louf7178 Před 8 měsíci +1

    In the last example, what if the FDB boundary was cut around the pulley with the weight?

    • @MichelvanBiezen
      @MichelvanBiezen  Před 8 měsíci +1

      The tensions in the 3 strings will still add up to the 100 N weight.

    • @louf7178
      @louf7178 Před 8 měsíci +1

      @@MichelvanBiezen But that would be 33 N (each).

  • @nancysmith9487
    @nancysmith9487 Před 11 měsíci +1

    Newtons are smart way for geniuses to understand. Simple lbs. Would be easier to understand which one would be better or easier to pick up most weight with minimum force numbers. 25 newton's...
    Appreciate your time and upgrade of my IQ

  • @md.salahuddinyousuf755
    @md.salahuddinyousuf755 Před 4 lety +1

    Great

  • @chesleygirlviolinmusic5629

    What is the mechanical advantage of example 2? Is it 2? And how about the MA of example 1? Is it 2 as well? I need a confirmation so badly... please reply

    • @MichelvanBiezen
      @MichelvanBiezen  Před 5 lety +1

      The mechanical advantage is defined as the weight lifted divided by the force required to do so. The first two examples: mechanical advantage = 2:1 The third example MA = 3:1 The last example MA = 4:1

    • @chesleygirlviolinmusic5629
      @chesleygirlviolinmusic5629 Před 5 lety

      @@MichelvanBiezen thanks prof michel...you saved my day

  • @RW1LD
    @RW1LD Před 4 lety

    At 2:23, You show there is "(150 total), 100N pulling on ceiling", when the total load is 100N shared by 2. it should be 50N?

    • @CybAtSteam
      @CybAtSteam Před 4 lety

      When you are pulling UP, the ceiling only has to carry the weight MINUS the force of pulling UP.
      When you are pulling DOWN, the ceiling has to carry the weight PLUS the force of pulling DOWN.

  • @itsyourboymob7704
    @itsyourboymob7704 Před 4 lety +3

    I have question in the last question, my friend and I cut between 3 ropes. We manage to have tension of 66N instead of 75N

    • @user-lr8od4uz1n
      @user-lr8od4uz1n Před 4 lety

      @Priya pari In this example friction and the weight of pulley doesn't exist

    • @user-lr8od4uz1n
      @user-lr8od4uz1n Před 4 lety +1

      I have the same question just like yours. I suspect that there should be a criteria for deciding a free-body diagram, which in this lecture the professor didn't teach.
      My guess would be that a free-body diagram must containt all ropes directly or indirectly pulling the thing.
      Since a norm of tension force on a rope is constant everywhere and every rope lifting the weight is actually one rope, the answer is the weight divided by the number of ropes in the diagram.

    • @prostoprohozhijnadjadjupoh5802
      @prostoprohozhijnadjadjupoh5802 Před 4 lety

      @
      Oliver Rusta
      If you cut ropes at the level where there are only three ropes (just above the lowest pulley), the middle rope will have tension not the same as the lateral ropes, but two times greater.

    • @prostoprohozhijnadjadjupoh5802
      @prostoprohozhijnadjadjupoh5802 Před 4 lety +1

      @@user-lr8od4uz1n Not necessarily. In the example #2, the last part of the rope is ignored because it does not touch a movable pulley. In general, only movable pulleys play a role in distributing a force. Non-movable pulleys only change the direction of the force.

    • @davidmintmier6040
      @davidmintmier6040 Před 3 lety

      @@user-lr8od4uz1n the criteria I use is I draw a box around the parts that begin to move when the rope is pulled.

  • @nuavecmoi
    @nuavecmoi Před 2 lety +1

    When it comes to mechanical advantage, does it matter if the pulley is fixed or not?

    • @MichelvanBiezen
      @MichelvanBiezen  Před 2 lety +1

      There are different pulley arrangements. Some have the pulleys fixed and others do not.

  • @kateystevenson7912
    @kateystevenson7912 Před 3 lety +1

    Thanks!

  • @niyatiskitchen345
    @niyatiskitchen345 Před 7 lety +1

    which questions are asked to engineer in Pulley industry?

    • @carultch
      @carultch Před 2 lety

      1: What is the rated capacity of the pulley as the sum of the two tensions?
      2. What is the coefficient of friction the pulley makes with the axle?
      3. What is the range of cord diameters that can pass around the pulley?
      4. What is the radius of the cord around the pulley?
      5. Can you provide a drawing that shows the mounting interface of the support bracket, so that I can work it in to my drawing?

  • @zezebeavogui6694
    @zezebeavogui6694 Před rokem +1

    I'm not sure if the weight supported by the ceiling can be less than 100N.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      For the example where the force is directed upward, the tension at the ceiling will be less than 100 N

  • @michaelszczys8316
    @michaelszczys8316 Před 3 lety +2

    I’m confused with number 2 being more than the total of the weight

    • @richardweiler1552
      @richardweiler1552 Před 2 lety

      The ceiling must hold the 100 N weight and the 50N downward pulling force. (Draw the free body boundary around the the whole thing.)

  • @petereziagor4604
    @petereziagor4604 Před 2 lety +3

    Haha, this is interesting
    I hope it's as easy as it's here when I try to solve one myself 😄

    • @MichelvanBiezen
      @MichelvanBiezen  Před 2 lety +1

      It looks like you managed quite well

    • @petereziagor4604
      @petereziagor4604 Před 2 lety +1

      @@MichelvanBiezen what exactly do you mean? It looks like you managed quite well 🤔

    • @MichelvanBiezen
      @MichelvanBiezen  Před 2 lety +1

      You figured it out quickly by taking a look at the diagrams. 🙂

    • @petereziagor4604
      @petereziagor4604 Před 2 lety +1

      Oh yes, you're right. I understood everything well despite this been the first time I'm seeing a solution of it's kind. Thank you for making learning easy @@MichelvanBiezen

  • @kabicarabuena7383
    @kabicarabuena7383 Před rokem +1

    What about the weight l mass of the pulley(s) in addition to the given load?

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      In most examples we ignore the mass of the pulleys. If they have mass you do have to add their mass to the free body diagrams. (We probably should add some example videos)

    • @kabicarabuena7383
      @kabicarabuena7383 Před rokem +1

      @@MichelvanBiezen why ignore the fact? Please teach correctly.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      In almost all cases, the mass of the pulley is insignificant to the mass of the object. That is why the mass of the pulley is ignored.

  • @borolo222
    @borolo222 Před 4 lety +2

    Why in example 3 the force on the ceiling is higher than the object itself?

    • @paoloaloyon1475
      @paoloaloyon1475 Před 4 lety +7

      Because there is the force applied in addition to the weight

    • @leif1075
      @leif1075 Před 4 lety

      Wait why at 4:57 is it 67 Newtons..shiuldnt it be 33..and ifnits,double then it should,be 66..where did he get 67 from?

    • @paoloaloyon1475
      @paoloaloyon1475 Před 4 lety +1

      @@leif1075 it's actually two 33.333... N pulling down, so according to the free body diagram for that single pulley, the force pulling up should be 66.666...N ≈ 67N

    • @JohannesHeld
      @JohannesHeld Před 4 lety

      @@leif1075 100/3=33,3333333333333333333333
      33,33333333333+33,333333333333=66,66666666666666=67

  • @rchydrozz751
    @rchydrozz751 Před 4 lety +2

    Does that F mean Fig Newton?

    • @carultch
      @carultch Před 2 lety

      No, it has nothing to do with fig newtons. The namesake of the fig newtons is town in Massachusetts that is a suburb of Boston, which has nothing to do with Isaac Newton.
      F stands for force, and its units in the SI system are in Newtons, named for Isaac Newton who is credited with the fundamental laws of motion. It is just a coincidence that fig and force both start with an F.

  • @phupwintthu877
    @phupwintthu877 Před 3 lety

    Thanks sir

  • @satyajitsahu6614
    @satyajitsahu6614 Před 7 lety +1

    last one is important

  • @arunavamajumder6823
    @arunavamajumder6823 Před 6 lety +2

    Thanks a lot. Sir u are very cute

  • @TantricViper
    @TantricViper Před rokem +2

    Wow! The fourth pulley system - the tension on the ceiling cannot exceed the weight. Draw a free body around the weight and all the pulleys. The sum of forces in the vertical direction must be zero. Therefore the tension on the ceiling is 100N up as the weight pulls 100N down (of course ignoring the weight of pulleys and rope).

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      A good way of looking at it.

    • @ashirbadmeher6059
      @ashirbadmeher6059 Před rokem +1

      That’s a wrong way of looking at it. There are 2 downward forces on the pulley attached to the ceiling, F which is the applied force to keep the rope tight and the weight of the object. F is being applied downwards so it will get added to the weight hence the 133 N force on ceiling. It’s easier to understand if you imagine hanging a second weight of 33 N where F is being applied. So the force on ceiling will be the sum of 2 weights

  • @abhishekpanchal5003
    @abhishekpanchal5003 Před 6 lety +3

    Last example why tension is not 33N?

    • @MichelvanBiezen
      @MichelvanBiezen  Před 6 lety +1

      When you look at the free body diagram, the weight is supported by 4 strings at the top of the diagram, each holding 25 N

    • @bruinprideee9970
      @bruinprideee9970 Před 6 lety

      I am still confused by this. Why do you draw the free body diagram to include the pulley above the pulley that's attached to the weight? If you draw the FBD as you did in the previous 4 examples, there would only be 3 forces pulling up on the pulley while the only downward force would be the weight of the mass. Therefore, if you draw it like that, the tension would be 33N. So my question is, why do you draw the FBD different in the last one vs the other 4 examples?

    • @MrBox999box
      @MrBox999box Před 6 lety

      BruinPrideee - I think the fbd includes the free hanging ones and excludes those who are hanging solely from the ceiling

    • @chesleygirlviolinmusic5629
      @chesleygirlviolinmusic5629 Před 5 lety

      @@bruinprideee9970 if the free end of the string is pointing upward, that will be included in the FBD.. If the free end of the string is pointing down, it wont be included in the FBD..

  • @LateNightRituals
    @LateNightRituals Před 2 lety +1

    God bless ur soul daddy

  • @kevinhill9428
    @kevinhill9428 Před 4 lety

    Drawing a dashed line around a region on the blackboard is not drawing a free body diagram. You have to actually draw the forces.

  • @vladkola8436
    @vladkola8436 Před 4 lety +3

    What makes learning fun? This hurt a little.

  • @fatimahajouj9302
    @fatimahajouj9302 Před 2 lety +1

    ولك يسعد دينك

  • @paulor.r.correia1789
    @paulor.r.correia1789 Před rokem +1

    Excelent 🇧🇷 🇧🇷 🇧🇷 🇧🇷 🇧🇷

  • @southern_merican
    @southern_merican Před 2 lety +1

    Someone correct me if im wrong, but if i hang 100n from the ceiling then the force on the ceiling is 100n, plus the weight of the pulleys and rope. So if his formula which seems right, IS right. The he should have said "plus the weight of the pulleys" . Because they are not light and several will get above 50 lbs quickly.

    • @MichelvanBiezen
      @MichelvanBiezen  Před 2 lety +1

      For the purpose of understanding the principle of how the pulleys work, we are ignoring the weight of the pulleys.

  • @nielsmadsen2185
    @nielsmadsen2185 Před 4 lety +1

    Newton is the unit of force. Weight meaning mass should be measured in kilograms.

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety +2

      weight does NOT equal mass weight = m x g (mass x acceleration due to gravity)

    • @nielsmadsen2185
      @nielsmadsen2185 Před 4 lety +1

      @@MichelvanBiezen I agree, but go to the store and for 10 N of sugar?

    • @nielsmadsen2185
      @nielsmadsen2185 Před 4 lety +1

      I agree, but go to the sore and order 10 N of sugar

    • @robertgheorghe982
      @robertgheorghe982 Před 4 lety +1

      @@nielsmadsen2185 weight is not mass !!! As a dog is not a cat that is way you can't buy 10N of sugar

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety

      In the US we buy pounds of sugar which is indeed a unit of weight and not mass. However there is nothing wrong with buying kg of sugar by adjusting the scales so they convert the 9.8 N of sugar they are measuring and depicting it as 1 kg.

  • @robbevington1754
    @robbevington1754 Před 3 lety

    #2 look to me wrong 2 rope should still only have a total of 50 not 100

  • @garyweaver6026
    @garyweaver6026 Před rokem +1

    Drawing #4 is wrong. A 100n weight can not pull down with 133n.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      The drawing is correct. The 100 N weight is beying pulled UP, and the force downward required is 33 and 1/3 N (Rounded to 33 N).

    • @garyweaver6026
      @garyweaver6026 Před rokem +1

      @@MichelvanBiezen How can 100n pull down with 133n? I have several pullies and rope, I can build this to see what weight reads on my scale.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      We now have about 1/2 dozen videos on different pulley combinations. Try to duplicate some of these examples to see how it works.

  • @steveeverett4108
    @steveeverett4108 Před rokem +1

    What bothers me is w is a force and not a mass.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      w = m g (just like F = m a).

    • @steveeverett4108
      @steveeverett4108 Před rokem +1

      Just seeing a hanging mass represented in N and not kg whereas N is a vector. Just an odd representation, but I understand.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      Ahh, I see. I think it is just a matter of getting used to it. When I moved to the US it took me a while to get used to pounds and miles. 🙂

  • @jeffreychavey4161
    @jeffreychavey4161 Před 3 lety +1

    Pulleys all pull their own weight.

  • @narendrarathore747
    @narendrarathore747 Před 11 měsíci +2

    Sorry 100 pulley will not lessen the weight even a gram if it is fixed only movevable pulley can lessen the weight

    • @MichelvanBiezen
      @MichelvanBiezen  Před 11 měsíci +1

      The weight of the object will not change, but the force required to lift is will.

  • @kmoses2814
    @kmoses2814 Před 4 lety

    In conclusion divid the weight by the numbers of pulley and you get your answer

    • @MichelvanBiezen
      @MichelvanBiezen  Před 4 lety

      When the pulleys are in this arrangement, yes.

    • @kmoses2814
      @kmoses2814 Před 4 lety

      Michel van Biezen which other arrangement do you know?

  • @Tazman333
    @Tazman333 Před 4 lety +2

    Not true. You can not reduce a single line anchorage compared to the weight no matter how many pulleys you use. You only reduce the force need to lift it.

    • @CybAtSteam
      @CybAtSteam Před 4 lety +1

      Yes, you can. If you are pulling UP the force on the single ceiling line is the weight MINUS the force needed to pull UP.
      Notice how he alternates his examples between pulling UP and pulling DOWN. For pulling up, the force on the ceiling is the weight minus the pulling up force while for pulling down that force is added to the weight.

  • @user-eg8wp2in3m
    @user-eg8wp2in3m Před 4 lety +1

    ΔΙΟΡΘΟΣΕΤΟ ΔΑΣΚΑΛΕ.ΕΙΝΑΙ 37,5 ΚΑΙ ΟΧΙ 33

  • @wadetaylor4697
    @wadetaylor4697 Před rokem +1

    Hey genius! 3,4,5 are 100 ceiling weight.

    • @MichelvanBiezen
      @MichelvanBiezen  Před rokem +1

      The values shown in the video are correct for example 3, 4, and 5. (They are not equal to 100N)

  • @younotme1617
    @younotme1617 Před 6 lety

    The weight on the ceiling is wrong in every diagram except the first one. Or are we talking force needed which is not the same. No amount of pulleys with reduce the overall weight nor increase the weight. (Not including the weight of the equipment used) Left to right three and 5 are 100% wrong no amount of pulleys will reduce the weight of the single ceiling fixture ! ILLOGICAL Unless someone can explain ?#

    • @MichelvanBiezen
      @MichelvanBiezen  Před 6 lety +2

      The video is correct.

    • @ianbrown_777
      @ianbrown_777 Před 6 lety

      Imagine a tree branch as a pulley. You are holding a 100kg man off the ground with your own 100kg body. It's 1:1 so you need 100kg of force to lift (hold) 100kg weight. The BRANCH however is holding twice your weight.
      Diagram 1 also reduces the weight (on ceiling) - that is, as long as you are holding the rope and sharing some of the weight. If you tie it off, the weight on the ceiling now goes up to equal the weight of the load.

    • @richardschot7693
      @richardschot7693 Před 4 lety +1

      The video is correct and explains it perfectly.

    • @carultch
      @carultch Před 2 lety

      @@ianbrown_777 A tree branch doesn't need to be 100 kg itself to support a 100 kg person.
      For instance, a standard 8 ft long, 2x12 plank has a mass of about 17 kg. But even a 100 kg person wouldn't hesitate to stand on it, as it can support a lot more than 100 kg of load as it spans its length across two support points.

    • @ianbrown_777
      @ianbrown_777 Před 2 lety

      @@carultch Correct. I'm not talking about how much the branch weighs - just the extra weight on it. I was just trying to explain in another way to the OP how the weight on the ceiling fixture will change (- either up OR down) depending on the system you attach to it.