Electricity 04 | Combination of Resistances | Series and Parallel | Class 10 | NCERT | Udaan
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- čas přidán 24. 12. 2020
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In this ongoing UDAAN Batch, Rakshak Dua Sir of PhysicsWallah is explaining to you about the (Electricity 04 , Combination of Resistances , Series and Parallel)
In this lecture, we have covered these important topics:-
1:-Series and Parallel Combination
2:- Solving Problems
3:- Division of current/voltage in series and parallel
4:- Deriving series and parallel formula
5:- Resistance of ammeter and voltmeter
6:- Finding SI unit of resistivity
7:- challenger Questions
There are many other important topics PHYSICS that we are going to cover in upcoming videos for 2022 exam. Stay tuned with Physics Wallah Foundation.
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which topics will be taught for how many days.
Available at PhysicsWallah App
Duration:-2 months (Dec 2020 - Feb 2021)
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4)Scheduled Syllabus released describing :-
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Available at PhysicsWallah App
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Download Lecture Notes From PhysicsWallah App(bit.ly/2SHIPW6)
Scheduled Syllabus For Udaan ( Class 10 ) released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App :bit.ly/2SHIPW6
Duration:-2 months (Dec 2020 - Feb 2021)
Free Batch Exclusive on our CZcams Channel : Physics Wallah Foundation - 9 & 10
Batch Details
1)Best Faculties across India for different Subject/Topics.
2)Complete & Relevant Syllabus Coverage of Class-10th within 2 Months- Fastrack Dec 18,2020-Feb 24,2021
3)Monday-Saturday : scheduled Classes everyday ( for each Physics, Chemistry,Mathematics , Biology and SST)
Physics:Mon,Wed,Fri (4:00 p.m)
Chemistry:Tues, Thurs, Sat(4:00 p.m)
Mathematics:Mon, Tues, Wed,Thur,Fri,Sat(7:00 p.m)
Biology:Mon,Wed,Fri (6:00 p.m)
History & Geography: Wed,Thur,Fri,Sat (5:00 p.m)
Civics & Economics: Mon,Tue,Thur (3:00 p.m)
4)Scheduled Syllabus released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App :bit.ly/2SHIPW6
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czcams.com/video/IaLfEIVbD54/video.html
Sir plzz... Subscribe me
Sir.. could u plz solve the previous year numerical question 2 which was given as homework in lecture 3 .
Q."Resistance of wire 0.01cm radius is 10ohm........find the the length of the wire"
Sir please conduct classes for ICSE Board students(class 9 and 10) as for us(ICSE Board students) good teacher are not available easily on CZcams......🙏
Sir please explain once again why voltmeter is connected in parallel and ammeter in series
Please do reply or explain in lecture please
sum of all resistor .. Accroding to ohm's law current is inversely proportion to resistant.. so, sir how current remains same in series..
sir, please explain..
Anyone noticed that during lecture there were no ADS.... That's excellent sir.... for not distracting students during lecture... 😃☺☺👌👌
Yes....He is really working hard for all of us.....May almighty bless him....😇😊
Yes you are correct
No ADS = NO MONEY💰🤑💵...
THANK YOU SIR💓
Bhai lekin humko ads se koi problem Nahi honi chahiye...
Sir Ka ek hi income source hai is channel se woh BHI ads ke through..
Although sir humme free de rhe hai Sara content Toh hume ads se koi problem Nahi honi chahiye...
Because with ads there are more than 6 Teachers and other staff , technician which are dependent upon it ..... 👍🏻
@@arshdeep5847 but they are also earning from their APP also....... And their crash courses
It's amazing that Sir is not disturbed by any person going and coming in the room
wahhhhhhhhhh ji wahhhhhhhhhhhhhhhh sir ager by chance disturb ho gaye to use kyu dikhaya jaege ..........hadd hi hai
Yes bhai you are right😇
Anyways from where are you,?
@@bapugaming104 bhai nakkoo behn bolo
@@bapugaming104 tu bddha sweet hai
Bhai aap kaha se ho bolo to
Amazing sir mera electricity chapter bahut weak tha lakin aab bahut strong Ho gaya Thank you sir
Kewal like ke na likha karo
@@savitendra.Kya
@@pure.1m.1dayago97 kya ,kya?
Same same but now all things is correct
Sir ji salute h apko Kya padhte h sir maza AA jata h...pure saaal smjh nhi aya electricity apne toh....chutikiyo me samjha diya....aisehi light v kra dijiye jldi
Sir padhte nahi padhate hai😂😂
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@@nandiniiyyy Yupp it happens some time. I write it for fun .Sorry If you hurt😶😌😌
I write it nahi, I wrote it hoga😂😂
@@ayan.yadav. 😂bus kr yrr
He made me believe electricity is not boring moreover he reads the doubt of your mind so he is the best explainer thanks to him to make my weaker chapter to loved chapter!!!
The only channel which teaches each and every concept practically...resolves the concepts so well! 😊😊🙏
Now there are ads but still not a problem at all.
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No bro vedantu also cleared the concept well!
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This channel is not only a channel,but its a family. It gives emotion.And i am proud to be a part of this family!proud to be PWIIAN
padh le salee
@@dta4321 apne kaam se kam rakh
Beta pehle 9th clear karle
Copy paste 😂
Sir when that chapter will finnaly end then please make video on most important and hard questions
Your teaching style is sooooooooooooooooo good
For more physics video visit
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22:28 previous year question 1 ans is 25(D)
czcams.com/video/7YpKj97ZJcM/video.html jrur sune 🚩❤️
Samz aaye to like kre❤️
We should share these videos with those who cannot afford expensive education
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Yes
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Though I am an ICSE class 10 student but I am listening to ur lecture as I love the way u teach 😄
U & alakh sir 😇
Itna padhaku
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Concept is power
@@pramilabhandari6017 i am also icse student
Time waste🙂🙂
Christmas day ke din bhe kaam se chutti nhi le is dun bhe work kar rhe h enjoyment choor ke
what an effort love you & whole team (physics wallah foundation)
Haa sahi kaha uper se christmas special video laaya chemistry (pooja mam) ne....
❤️🧡
czcams.com/video/Sm-Rikzm06E/video.html
Sir the answer for the homework question 1 is d 25 because if we assume that a wire is cut into 5 equal parts the resistance of each part is equal to a .so when the each piece of wire is arranged in series the resistivity of the wire (R) will be a+a+a+a+a i.e. 5a
Now when the pieces are arranged in parallel the resistivity is(1/R' )=1/a+1/a+1/a+1/a+1/a
So our 1/R'= 5/a
So R'=a/5
Now ATQ, we have to fine the ratio of R /R'
So 5a/a/5= 25
So at last we can conclude that the ratio is 25/1
Therefore the correct option isD
excellent
Maja aa gya sir Ji Kaas aapka lecture daily ho physics padhne me maja aata hai...😘😘
this teacher is amazing i dont know why didnt bore after an hour and understood everything and i love he translate words in shudh hindi but sir why arenot teaching us chemistry you told us in 1st video.
thankyou sir
Yess sir I also want to learn chemistry to u
Chemistry ki mam bhi acche hai bhaut
Sahi bola bilkul bhi bore nhi hote..h hum 👍👍👍❤️
bhai chemistry agar is andaaz me chaayiye to magnet brains wale sir ke paas jana hogo aur agar physics to physicswallah se achha koi nhi bhai
@Vishal Xth C 21 ok i will but you also have to see his video although this all waste we can do self study is you are intrested for olympics 2o21 tokyo
The onlyyyy channel. they didn't give anyy ad between the video rest of all the educational channels givess ads but thisss 💯😊😊😊
Before I don't understand this chapter
After watching the physics wallah lectures I love this chapter
Thank you so much sir
Who noticed that the black board is more a mirror 🪞😂😂
Mee 😅
It's a smart board 😂😂
I also
It's a smart board nigga 💀💀
Lecture mai dhyan doh
Fully Impressed .Extremely Delighted😃😄
Hlo
Both the challenger problems of previous lecture also solved successfully 🤟 and also solved both the previous year numericals homework questions 🤟🤟
That in last "padhai karte rahe all the best" gives another level of motivation
A circuit is composed of conductors (wire), power source, load, resistor, and switch. A circuit starts and ends at the same point. Usually, copper wire without insulation is used as a conductor. A switch is used to make or break a circuit. Resistors control the flow of the electric current in a circuit. A resistor is a passive element which means that it only consumes power but does not generate power. A load in a circuit consumes electrical energy and converts it into other forms of energy like light, heat, etc. A1/R eq =1/R 1 +1/R 2. Req< min {R 1, the R 2 }
Homework:-
Ans 1:- 25
Ans 2:- i)In order to 9 ohm, we will connect two resistors each of 6 ohm in parallel combination and one resistor of 6 ohm in series...
ii) In order to 4 ohm, we need to connect two resistors each of 6 ohm in series combination and one resistor of 6 ohm in parallel....
Apne kese Yeh first one 21 nikala
@@letsstudywithpriyanka5171 It's in parallel so find equivalent. 1/R'= 5/R +5/R+ 5/R+5/R+5/R= 25/R.
R/R'= 25.
@@letsstudywithpriyanka5171 I get the part at which u are confused. So eventually each resistors will be R/5 but since it is to be connected in parallel we will add the reciprocals of the resistors i.e 5/R
@@Laisora. hii
@@Laisora. thank you
Thank you soo much sir for giving this wonderful lecture..... Tomorrow was my exam and i woke up all night listening your lectures
I have no words to explain your teaching ideas love you sir keep it up
PYQs:-
1: Given that 1 wire of resistance R is broken down into 5 parts.
This means that each part will be of resistance R/5.
Resistance of Wire:- R
Total number of parts:- 5
Combined resistance of all parts:- R'
5/R + 5/R + 5/R + 5/R + 5/R = 1/R'
25/R= 1/R'
R' = R/25
Now R/R' = R / R/25
= R× 25/R
R and R get cancelled out, so;
R/R'= 25
2. i. We have to connect two resistors in parallel and 1 in series to get Total resistance of 9 omega
ii. We have to connect 1 resistor in parallel and 2 in series to get Total resistance of 4 omega.
Bro we don't need to do series connection as said by sir, do we? We directly can get answer using parallel
It's R\5*
😮
Ncert ka question chep diya
I attended these lecture first time and I don't believe that whole chapter including numericals are in just 6 videos really amazing .and I solved the numericals very quickly . thank you sir .🙂🙂🙂🙂🙂🙂🙂🙂👌
My opinion towards this video is same.
Me to
22:35
i) 25
ii) 9 ohm = 2 in parallel with 1 in series
4 ohm = 1 in parallel with two in series
wrong hai 1st question.............5 aayega
Sahibola
22:50
1) (D) 25
2) In case (i), 2 of the 3 resistors are to be connected in parallel and the third one to be in series with the first two.
In case (ii), 2 of the 3 resistors to be connected in series and the third one to be in parallel with both of them.
U are right
Kaise nikla tha answer
I want to see this platform at 100 million❤❤❤
Sir i am a iit aspirant but i am in class 12 i watch your vedio because some of my concepts are weak ..thanks sir for great explanation 😊
😑😑😑
Is any one ask you?
IIT nikal gyi bhaiya aapki ?
@@AnandSingh-hn7xt bhai wo 12th me 10th concept pad rha he obv nhi hogi
@@meiniit2025 baat toh shi hai 😂
Sir I love ur teaching style ....thankyou for all ur efforts.
Sir the and of first question is (D) 25
And and of second question is (I)__two resistance in parallel and one resistance in series= 9 ohm
(ii)_two resistance in series and one resistance in parallel.__4ohm
Sir aap prabu ho jinke physics teacher ache se nhi smjh pate hai school me .
🥇🥇🥇🥇
Sir's examples are just awesome
🔥🔥🔥
yea unlike vedantu 😂😂
@@sarthak1835 Vedantu to Bhai videos mein bhi promotion karte Hain🤣🤣
Bhai monitization on nahi hai abhi
Free main padha rahe hain to koi ad aaye toh isse kya fark padta hai
@@sunnykumarrelaxing1579 mai to chahta hu ki ads aay hamare sir ka bhi benefit ho we all love udaan batch's teachers including alakh sir
Previous years numerical:
1) d- 25 ohm
2) i) first two are connected in parallel and its equivalent resistor is connected in series
ii)first two are connected in series and its equivalent resistor is connected in parallel
Solution hai
BRO SOLUTION LF Q1
im grateful for all of ur vids sir .
Homework questions:
Q1- D) 25
Q2 - 1) by mix ( two parallel and one series )
2) by mix ( two series and one parallel)
1) wrong the answer is 25
Hiii
22:28---> 1. (D) 25
2. (I) Two resistors in parallel and one in series with them.
(ii) Two resistors in series and one in parallel with them.
question number 1 how ans came 25 can you explain me plss
(Q.1.)----answer-----(25ohm)
(Q.2)---answer------- (a) -- for --9 ohm -- fist we solve 2 parallel resistors and add with one 6ohm serries
(b)--- for 4 ohm---- first add 2 series of 6ohm with parallel one resistor of 6 ohm
Awesome teaching sir i see this lecture now because i am studying in class 10 9:51
Best teacher I've found on CZcams 🥺🥺🥺
THANK YOU FOR THE CLASS SIR
He is the bst teacher of physics 🙏🙏🙏awsm explanation sir ...
For more physics video please visit
#awadheshsirphysicsclasses
Rty
Gjb ka channel bnaya h
Alakh Sir aapne ....
i was not able to understand anything from this chapter but your lectures made it so clear! Thank you very much sir
Best explanation...❤❤❤🔥🔥
Rakshak Sir Op...🔥❤🔥🌚
Nice teacher of physics 🔥👍
Sir... Thanks u so much for this wonderful lecture ♥♥
22:47 Ye ek wire Hai ek taar Jiski ressistance R hai 😂
What a rap sir 😂
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Rap nhi hota hai woh
Usse rhyme kehte hai
Sir aapka class karte karte pata hi nhi chalta 1 ghante kub beet jatein hai... ☺
Bhagwan bhi chahte hai ki 10th hum aapse hi karein isliye xam postponed.... 👏
Waah!
Kya padhaya hai...
Bhai waah!
Maze aa gye😀🎉🔥
Sm2u😍😍
Amazing explanation ❤️
Sir the answer for the
Home work question 2
i : mixed circuit where 2 are in series and one in parallel
ii:mixed circuit where 2 are parallel and 1 is in series
The perfect class by a very perfect teacher without any distraction by doing Ads
Am very happy that physics wallah started foundation channel.. 💕
Hi
@@sauvikseth bhai kaam karo yaar behan ke sath bat mat karo!!12 me sab aayega physics me...
Thank you so much for clear my all doubt 🙂
Best explaination sir
Best channel
Fabulous explaination of teachers
We love studying with you. You are the best teacher ever KOP we will always your pigeon and pigeoneya. We love you sir 💝💝
kop means?
Q:-2
we connect two resistance in parallel and one in series so. the answer of 2 parallel resistance is 3 and one series is 6 and total we get 9 ohm
.
.
we connect two resistance in series but which are parallel of one so. the tota is 12 and one is 6 we get 4 ohm
Thanks you so much sir cleared my problem in this chapter
Thanks you sir you are best physics teacher ❤️
Your teaching style is just amazing
I become a big fan of This sir Eventhough I'm not a cbse student i understand the concepts very well
Insta use karti hain aap?
Me too
very helpful video in lockdown 😊
Your explanation is awesome ☺️👏
Disadvantages of series circuits
An open in any one device will also interrupt current flow to all remaining devices.
A short in one device will cause an increase in current through all the devices.
Thank you so much sir for this awesome explanation.....After watching your video...I am able to solve each nd every numerical related to combination of resistance.... Thank you so much 😊
❤
Sir bhot jyada Maja aa Raha hai Aapke sath padhne me aur challenger questions Karne me ... Sir aap mahan ho😀😀😀
This channel save our tution fee and save time
Ans1 25 (option D)
Ans2 .{1} - (two in parallel with one in series.)
{2}- (two in series with one in paralle)
Or hum tum ek series m
Sir , you are the fantastic teacher ,
Are Sir...kya samjhaaya hai aapne!
Itne crystal clear concepts shaayad hi kisi aur teacher ne aaj tak convey kiye the. Thank you soooooo much , Sir!😊😊
Sir you teach like my tuition teacher.
Thank you sir
Your explanation is great sir 😊🙏
Awesome 👍👍👍👍👍
czcams.com/video/7YpKj97ZJcM/video.html jrur sune 🚩❤️
Samz aaye to like kre❤️
*Merry Christmas* 💝
Whole journey of Recent *EDUMANTRA Crisis* 👇🏻👇🏻👇🏻
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This topic is deleted from boards sllaybus..but still very very important and helpful 😊
Thank you sir I understand whole chapter from your video
Excellent teaching sir..jaha se divide hota hai wahi se derivation start karo....making learning simple..salute sir🙏❤️
Clear explanation
🌿🌿🌿🌿 sir,
No add... during. Video..nice sir
Homework question answers
1. 25:1 option D
2. (i) 2 in parallel and 1 in series
(ii) 2 in series and the whole in parallel
Chl
H.W
1.) 25 .
2.) i )9 ohm =two resistor connected in series and one in parallel.
ii .) 4 ohm =one in series and two in parallel.
Sir very good teaching style...thank u so much💖🙏
Thank you so much for the best explanation sir😊😊❣️
For getting 9 ohm we connect one resistance in series and other two resistance in parallel
For getting 4ohm we would connect two resistance in series one of the resistance in parallel
Thank you sir you are the best teacher ☺️☺️☺️
Alakh sir thanks for providing us with the best teachers ever😘😘
24:25 (Q No.1) Ans. (D) 25
Q No. 2 Ans. (a) First two resistors of 6 ohm each are connected in parallel combination and then 1 resistor of 6 ohm is connected in series with them to get 9 ohm resistance.
(b) First 2 resistors of 6 ohm are connected in series combination and then 1 resistor of 6 ohm is connected in parallel to them to get 4 ohm resistance.
But brother I could get 2 ohm in parallel and rest of six ohm added then we get 8 ohm ..
How would you get 9 ohm
Sorry bhai it's my mistake
It's my fault
Q1) D)25
plz, explain.....
Thanku this answer is help me wese to sir ne btaya tha but thoda confuse ho gyi m first numerical try kiya is chapter ka so thanku.....
Previous year Numerical 1: option (D)
2:- 1/R=1/6+1/6
=2/6
=3
Rs=R+R³
=3+6
=9(i)
Rs=R1+R2
=6+6
=12
1/Rp=1/Rs+1/R3
=3/12
=4(ii)
answer of challenger problem
1. (D)
2. (i)connect 2 resistor in parallel and the third one in series with this.
(ii)connect 2 resistor in series and the third one in parallel with this.
Sir aap bhout pyara samjhate ho koi bhi concept maza aa jata hai
Superbbbbbbbbbb sir!
Best explanation !! Thank u sir🤗🤗
👍👍👍👍... Excellent explanation 👍
Ghnta life simple 😑
Great explanation sir !!
I watch more than 50 vidios in CZcams but you explain aosome 💯💯😊
Challenger problem 2. i for 9 ohm two in parallel and one ☝ in series
ii) for 4 ohm two in series and ☝ in parallel combination
Anybody notice ....alak sir kabhi bhi like ya subscribe krrne ko nhi kahte......
Love u sir😁😘
Yes
Ans 1 :- 25 (option D)
Ans 2:- 1) two in parallel with one in series
2) two in series with one in parallel
i can listen to him all day long
Sir please tell answer of challenger question in next lecture....