Distributed loading on a beam example #1: rectangular loads

This engineering statics tutorial goes over en example with a simply supported beam with a uniformly distributed load applied to it. A rectangular shape with a constant density will have a uniformly distributed load across its length. The goal of this problem is to find the values of the reaction forces at the supports, using knowledge of centroids from the previous video.
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Thanks for watching, I hope it helps!

[@iftiimiye1038]

thanks for amezing explanation.clear

[@Engineer4Free]

You're welcome, thanks for watching =)

[@14henrylover]

really helpful thank you sir

[@Engineer4Free]

Thanks for the feedback! f you haven't already, make sure you check out engineer4free.com/statics for the rest of the tutorials!

[@mx520rider]

How do you solve when A and B aren't on the ends of the beam? Thanks

[@Engineer4Free]

Then you would have some kind of overhanging beam. Here are some examples with overhanging beams: czcams.com/video/BHNf-uwW7wg/video.html - czcams.com/video/QgjMRrrMqiE/video.html

[@MomenMusameh]

what is the relation between centroid (center of area ) and distributed forces?

[@Engineer4Free]

Centroid of the shape of a distributed load represents the x location of the equivalent point load. It's needed for the sum of moments about a point calculation. Please watch videos 58-65 here: engineer4free.com/statics it will explain the method and go over enough examples to be confident in what's going on.

[@MomenMusameh]

@@Engineer4Free you are the best thank you ♥

[@user-ug1bx2su5k]

when we change the distributed force to concentrated force how can we find the point of action of this force ?

[@Engineer4Free]

Please watch videos 58-65 here: engineer4free.com/statics it will explain the method and go over enough examples to be confident in what's going on

[@eykaaaa99]

For pin support where is the Ax

[@Engineer4Free]

Ax = 0 because there are no horizontally applied loads. It's pretty okay to not bother writing that, but if you are on a test I would still explicitly write Ax = 0 just to communicate without doubt that you know what is going on.

[@s_naeemnaqvi8725]

you saved my ass