An object 4 cm in size is placed at a distance of 25 cm from a concave mirror of focal length 15 cm.
Vložit
- čas přidán 10. 09. 2024
- Q- An object 4 cm in size is placed at a distance of 25 cm from a concave mirror of focal length 15 cm. At what distance from the mirror should the screen be kept so that a sharp image of the object can be obtained on screen? Find the nature and height of the image.
Hlo bhaiyya I had so many problems with calculations in physics and By seeing your videos its very easy You explains soo nicely
Love from kerala💞
Thank you so much sir for your explanation ❤❤❤❤
Sir why we finding h'
Because question asked us to
Hy h' is the symbol for size of image and it is asked in the question to find the size of image
Oh thanks
But why it is enlarged as when magnification is less then 1 the image is diminished and when it is greater than 1 the image is enlarged ,here the magnification is -1.5cm ,can someone explain?
@@ananya_s_club the magnification we found in this question is -1.5cm. You might misunderstand the concept of magnification. Here the (-) sign indicates that the image is inverted, and if the magnification is in positive so the image will be erect. It doesn't matter whether the magnification is in (-) or (+) we have to check that the image magnification is greater than 1. Like in the ques the magnification is -1.5 we have to ignore the sign whether it is positive or negative we have to see that the magnification is greater than 1 (I hope it helps)
Brother is question me 'v' ko ham negative nahi lenge kiya ? Kiyu ki concave me to v- me hota ha
Please reply brother
Concave me u negative hota h v ki value tho nikali h 👍🏻
Thanks 😊
Please explain alll theorem and question from chapter Quadrilateral and Triangle
Kindly explain me how and why size is enlarged
Though its magnification is -1. 5
Negative means that the image is real and inverted. If magnification is equal to 1 then image size is equal. If 0 is less then m greater then 1, then m is smaller than the object. Hope you find it helpful and if magnification is positive, then image is erect and virtual.
Negative means that the image is real and inverted. If magnification is equal to 1 then image size is equal. If 0 is less then m greater then 1, then m is smaller than the object. Hope you find it helpful and if magnification is positive, then image is erect and virtual.
How the size is enlarged
.. Because Height of image is large than 1
Magnification of this question is 1.5 means Enlarge..
the magnification we found in this question is -1.5cm. You might misunderstand the concept of magnification. Here the (-) sign indicates that the image is inverted, and if the magnification is in positive so the image will be erect. It doesn't matter whether the magnification is in (-) or (+) we have to check that the image magnification is greater than 1. Like in the ques the magnification is -1.5 we have to ignore the sign whether it is positive or negative we have to see that the magnification is greater than 1 (I hope it helps)
@@Arckuo bro saved me lmfaoo
Sir exploitation fast hai sir and detail explain kariye sir
ㄘㄗㄊㄜˇㄜㄘˉㄨㄊㄧㄊㄙ