Extraordinary Conics: The Most Difficult Math Problem I Ever Solved

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  • čas přidán 16. 06. 2024
  • This is a real math problem I faced, and the process I went through to solve it. Despite being a difficult problem, I tried to focus on the beautiful visuals and interesting discoveries I made about conic sections that I doubt anyone knows about. While this isn't my typical style of video, there was a ton of coding that went into this (all open source) and an interactive app of this entire video. Check them out below!
    Source Code: github.com/HackerPoet/Conics
    Download Windows (64-bit): github.com/HackerPoet/Conics/...
    Chapters:
    0:00 Introduction
    0:23 5 Elements
    3:47 Duality
    5:49 Skew Axes
    7:39 My Hardest Problem (Part 1)
    10:14 My Hardest Problem (Part 2)
    13:59 My Hardest Problem (Part 3)
    In Homage To:
    3Blue1Brown: / @3blue1brown
    Mathologer: / @mathologer
    Definitely subscribe to these channels if you like this video!
    Six Umbrellas - The Psychedelic And (CC BY-SA 4.0)
    Six Umbrellas - Monument (CC BY-SA 4.0)
    www.sixumbrellas.de/
    Meydän - The Beauty of Maths (CC BY 4.0)
    / meydansound
    Yakov Golman - Dance (CC BY 4.0)
    yakovgn.awardspace.info/

Komentáře • 1,2K

  • @feynman6756
    @feynman6756 Před 4 lety +3823

    "I'm not 3b1b"
    He said it to hide the truth.

  • @Yogfan800
    @Yogfan800 Před 4 lety +5090

    i didn't understand like 90% of this video but yeah shapes are cool.

    • @CodeParade
      @CodeParade  Před 4 lety +989

      Thank you! I know the actual material is dense, but I was hoping the visuals still make it fun and interesting to watch.

    • @conlangnovids4974
      @conlangnovids4974 Před 4 lety +148

      @@CodeParade I loved this I didn't understand 10% of it but It was cool
      I Love math and coding so this was really good

    • @firSound
      @firSound Před 4 lety +142

      Watching advanced material well beyond one's current knowledge and comprehension of a subject, strengthens diffuse mode learning. So even if you don't know it, you're actually smarter.

    • @EtanMarlin
      @EtanMarlin Před 4 lety +9

      I agree 😂

    • @user-kx8pu6ys5i
      @user-kx8pu6ys5i Před 4 lety +26

      @@firSound yes my brain is better now

  • @Jellylamps
    @Jellylamps Před 4 lety +774

    My favorite thing in math is “oh you can just do this simple and seemingly unrelated thing to figure out the problem and it always works”

    • @chriskrofchak
      @chriskrofchak Před 4 lety +53

      ALL OF MY PROOFS CLASS...

    • @ferociousfeind8538
      @ferociousfeind8538 Před 4 lety +62

      It's like shooting a duck to get winter to come and go. Like, what? What?? But it works, and some guy 500 years ago proved it works with like... wait, how did he know any of that? Q... quantum theory and general relativity? What does THAT have to do with a DUCK and WINTER?
      Ahem. Math might not be for me lmao

    • @Ssacred_
      @Ssacred_ Před 4 lety +13

      @@ferociousfeind8538 you ever thinked how fucking blown mind is the 2 grade ecuation, just that simple thing, like how the fuck did they figure out, srry for my english eksdi

    • @RagbagMcShag
      @RagbagMcShag Před 4 lety +7

      @@Ssacred_ A part of my brain melted inmidst of this comment chain

    • @Ssacred_
      @Ssacred_ Před 4 lety +2

      @@RagbagMcShag xdd

  • @abigailmcdowell4248
    @abigailmcdowell4248 Před 4 lety +1707

    I now really REALLY want 3b1b to prove all the assumptions in this video 😅

    • @conlangnovids4974
      @conlangnovids4974 Před 4 lety +99

      why not we all ask 3blue1brown (:

    • @adammoussa7295
      @adammoussa7295 Před 4 lety +43

      yeah good idea, let's start bombarding his videos comment section!!

    • @ck88777
      @ck88777 Před 4 lety +58

      3b1b kinda just demonstrates other people's proofs and theorems idk if hes capable of proving all this in a timely manner

    • @abigailmcdowell4248
      @abigailmcdowell4248 Před 4 lety +31

      @@ck88777 doesn't need to be timely, and I think it'll be an interesting enough exercise for him to want to show

    • @shadiester
      @shadiester Před 4 lety +73

      Another commenter, Rishabh Dhiman, included this relevant information which I thought might be of interest:
      """I was really delighted to see a relatively large youtuber talk about point-line duality and projective geometry.
      If you want a proof of these properties and a lot of other cool properties I would highly recommend AV Akopyan's book Geometry of Conics. [1]
      Also, the line formed by the three collinear midpoints is called the Newton-Gauss line. [2]
      The proof for the case of the tangent ellipse being a circle is called Newton's Theorem. [3]
      The fact that the centres are collinear comes from a more general fact about the locus of pole of a fixed line with respect to the the inconics of a given quadrilateral being collinear. This is Theorem 3.16 on page 88 of Geometry of Conics.
      When the fixed line is moved to infinity, we get centre of ellipses and hyperbolas.
      [1] AV Akopyan's Geometry of Conics geometry.ru/books/conic_e.pdf you can also buy a physical copy on Amazon
      [2] Newton - Gauss Line en.wikipedia.org/wiki/Newton%E2%80%93Gauss_line
      [3] Newton's Theorem - www.cut-the-knot.org/Curriculum/Geometry/NewtonTheorem.shtml
      """

  • @sireevictineerivero342
    @sireevictineerivero342 Před 4 lety +970

    "There is a conic that passes through any 5 points."
    Yeah.
    "Parabolas are halfway between an ellipse and a hyperbola."
    Mhmm...
    "The equation can be simplified by this matrix."
    Uh...Right. Sure.
    "AcosTheta + B....."
    ...I guess?
    "Frobenius product."
    Now you're just making up words.

    • @scptime1188
      @scptime1188 Před 4 lety +57

      I get the conic stuff and tangents and all that, but everything in the written proof section about the matricies and stuff, i was completely lost.

    • @TheMajorpickle01
      @TheMajorpickle01 Před 3 lety +21

      @@arnehurnik If you don't understand matrices, it's an entire topic in a physics undergrad. Not to discourage you from looking it up but don't be mistaken into thinking it's a minor undertaking. If you are used to linear math non linear math is a headache

    • @Temeliak
      @Temeliak Před 3 lety +11

      @@arnehurnik 3blue1brown made a quite nice and relatively easy to follow series on linear algebra, a good way I think to wrap your head around matrices

    • @gamma-bv6ty
      @gamma-bv6ty Před 3 lety +6

      @@TheMajorpickle01 Matrices are part of linear algebra so I don't really see what's nonlinear about them. Also, the actual theory of matrices would be covered more in a math undergrad than a physics undergrad.

    • @TurkishLoserInc
      @TurkishLoserInc Před 3 lety +6

      @@gamma-bv6ty Any reputable Physics, math, and comp sci dept is going to be sticking you into a sophomore-junior level linear algebra class that will essentially focus on matrices. All engineers were also required to take it at my school, as any FEA(finite element analysis) is likely going to be done with either calculus or simpler linear algebra.

  • @johnerickson8160
    @johnerickson8160 Před 4 lety +291

    A mathmatician: Aw yes a very satisfying math problem
    Me: Whoa look at the cool lines on the screen

  • @dumbeh
    @dumbeh Před 4 lety +2145

    me having no idea what any of this means.
    “ah yes of course... the... matrix.”

    • @nixel1324
      @nixel1324 Před 4 lety +115

      Don't forget to... invert it?

    • @zadejoh
      @zadejoh Před 4 lety +74

      @@nixel1324 in case you're serious, a matrix is basically a grid of numbers. Inverting a matrix is the equivalent of finding the reciprocal of a number (let's say 8 and 1/8). Multiplying 8 and 1/8 gives 1; for matrices A multiplied by its inverse A^-1 gives back the identity matrix which is the matrix equivalent of the number 1. Of course finding the inverse of a matrix is not as easy as the reciprocal of a number at times, but this is the gist of it.

    • @MrTtawesome
      @MrTtawesome Před 4 lety +26

      @@miso-ge1gz When you switch the numerator and the denominator. Say you have 5/2, the reciprocal is 2/5. Or 3, which can be written as 3/1, it's reciprocal is just 1/3. Multiply a number by its reciprocal and you always get 1, which is pretty cool

    • @vikaskalsariya9425
      @vikaskalsariya9425 Před 4 lety +9

      @@miso-ge1gz You haven't seen the Neutron style.

    • @michalgolonka832
      @michalgolonka832 Před 4 lety +11

      Same. F*ing same. Matrixes, tangents, sinh, cosinh. I vaguely understand sin and cosin

  • @Nasrul260
    @Nasrul260 Před 4 lety +886

    Math with text: **boring**
    Math visually: *_"let's get funky!"_*

  • @Vit-Pokorny
    @Vit-Pokorny Před 3 lety +94

    programmers be like: "Just knowing it works was good enough for me"

    • @dreckneck
      @dreckneck Před 3 lety +8

      This makes a mathematician cry 😂😭

  • @skj983
    @skj983 Před 3 lety +37

    Kids today are lucky to have these kinds of visualizations for geometry. This type of stuff works wonders for the young mind in developing a very valuable sense of intuition for mathematics. This is really great work. Keep it up!

  • @John-hz8xy
    @John-hz8xy Před 4 lety +116

    He makes Desmos look like a children's toy.

  • @Otori6386
    @Otori6386 Před 4 lety +70

    I know enough to know I don't know enough to fully appreciate this
    hehe pretty lines and shapes

  • @jakehate
    @jakehate Před 4 lety +248

    "you might have seen a comic section represented like this before"
    Me: hmmmm yes go on

  • @kebman
    @kebman Před 4 lety +28

    I think you'll _love_ POV-Ray. It's an old raytracer. You have to program the inputs. Modellers exist for it, but the true joy of using this program is wading through the pleasurably well-made documentation, and the complicated yet fully logical mathematical models used to trace the forms. You can make some very complex forms with it, including quartic objects, and objects modelled with various forms of "noise" algorithms, and of course fractals. I don't know any other raytracer that is so comprehensive, and yet logically set up. It might be old, but it still has it's uses.

  • @columbus8myhw
    @columbus8myhw Před 4 lety +90

    15:30: "And negative areas are hyperbolas." Correction: this is area squared, so negative 'area squared', or imaginary areas, are hyperbolas.

    • @CodeParade
      @CodeParade  Před 4 lety +63

      You're correct. I was trying to say 'the areas of the curve below the x axis' but it was confusing because I'm also talking about literal area.

    • @Keldor314
      @Keldor314 Před 4 lety +5

      This might be an interesting area for further investigation. Clearly any intuitive "area" for a hyperbola is infinite since it's an unbounded shape, but here we have a solution that assigns such an area to an imaginary number. So what's the deeper meaning here?
      Also, what about the duality between positive and negative area? Negative area is one of the two solutions to a square root, but is there a geometric meaning to negative area that's distinct from positive area? Maybe you could introduce some idea of handedness depending on whether the elipse goes around its center in a clockwise or counterclockwise direction according to the parameter theta? This makes sense in the context of a mirror image perhaps.
      Finally, is there some way to give meaning to area as a generalized complex number?
      What about instead of looking at a plane (being the cartesian product of two real lines), we look at a "hyperplane" (the cartesian product of two complex planes) instead? If we take the original problem to be looking at the planer cross section through real directions, is there meaning in looking at a complex area as a solution to where the complex conic section becomes an elipse in a different cross section?
      Could all this be related ultimately to the same structure that gives rise to the Fundamental Theorem of Algebra?

    • @hybmnzz2658
      @hybmnzz2658 Před 3 lety +4

      @@Keldor314 it is common to see diverging things have a connection to imaginary numbers.

    • @samuelthecamel
      @samuelthecamel Před 3 lety +1

      @@Keldor314 In abstract math, divergent sequences often "converge" to some negative or imaginary number. For example, 1+2+3+4... = -1/12. Although this isn't really an iterated sequence, it may be related in some way.

    • @hiiistrex2838
      @hiiistrex2838 Před 3 lety +1

      @@samuelthecamel how is 1+2+3+4... Supposed to equal -1/12 tho
      I feel like I've seen it before but it makes zero sense
      Or it makes -1/12 sense idk

  • @johan7999
    @johan7999 Před 4 lety +2

    You've fed the curiosity within me. I'm enjoying your source code, your math and you're fascination for these mathematical discoveries!
    You sound like a child when he first are a candy, absolutely wonderful!

  • @AgentMidnight
    @AgentMidnight Před 4 lety +14

    I'm an absolute sucker for clean, fluid math visuals. Instant subscription.

  • @yinq5384
    @yinq5384 Před 4 lety +15

    6:55
    We consider the standard ellipse (x/a)^2 + (y/b)^2 = 1 as an example. (General cases are same after one rotation and translation.)
    All points on the ellipse have the parametric form P(a cos(s), b sin(s)).
    The obvious choice of vectors A and B are A = (a,0) and B = (b,0).
    In general, say we know one skew vector A = (a cos(t), b sin(t)), and we try to find out another vector B so that
    A sin(theta) + B cos(theta) + C representing the same ellipse. (C = the zero vector here since we assumed the center is the origin.)
    Assume B = (a cos(s), b sin(s))
    A sin(theta) + B cos(theta) = (a cos(t) sin(theta) + a cos(s) sin(theta), b sin(t) sin(theta) + b sin(s) sin(theta))
    For any angle theta, the above point is on the ellipse (x/a)^2 + (y/b)^2 = 1.
    Thus (cos(t) sin(theta) + cos(s) sin(theta))^2 + (sin(t) sin(theta) + sin(s) sin(theta))^2 = 1.
    Simplify and we get 0 = [cos(t) cos(s) + sin(t) sin(s)] sin(theta) cos(theta).
    Thus 0 = cos(t) cos(s) + sin(t) sin(s) = cos(s-t).
    We can choose s = t + pi/2.
    That is,
    B = (a cos(t+pi/2), b sin(t+pi/2)) = (-a sin(t), b cos(t))
    To summarize, "Skew vectors" ARE still "Perpendicular" in the parametric sense.
    7:10
    Area:
    |A x B| = | (a cos(t), b sin(t)) x (-a sin(t), b cos(t)) | = a cos(t) b cos(t) - b sin(t) (-a sin(t)) = ab
    Thus pi |A x B| = pi ab = Area
    C^2 Invariant:
    |A|^2 + |B|^2 = (a cos(t))^2 + (b sin(t))^2 + (-a sin(t))^2 + (b cos(t))^2 = a^2 + b^2
    Inside Test:
    Using the parametric form again, say P - C = P = k(a cos(s), b sin(s)).
    Point P is inside the ellipse if and only if |k| < 1.
    |(P - C) x A| = kab (cos(s) sin(t) - sin(s) cos(t)) = kab |sin(s-t)|
    |(P - C) x B| = kab (cos(s) cos(t) + sin(s) sin(t)) = kab |cos(s-t)|
    |A x B| = ab as we already calculated.
    Then
    |(P - C) x A|^2 + |(P - C) x B|^2 = (kab)^2 and |A x B|^2 = (ab)^2
    Then Inside test formula is equivalent to k^2 < 1.
    Tangent Test:
    Necessity:
    Suppose there is a tangent line. P is any point on the line and R is the direction vector of the line.
    Denote the tangent point by T. Then (P-T) // R. Thus R x (P - C) = R x (T - C).
    Actually, we can use similar parametric form as above, say R = k(a cos(s), b sin(s)) and T - C = T = (a cos(t), b sin(t))
    Then |R x A|^2 + |R x B|^2 = (kab)^2 as before,
    and |R x (T - C)|^2 = (kab)^2 |sin(s-t)|^2.
    The formula is equivalent to |sin(s-t)| = 1, i.e. the different between t and s should be pi/2.
    And the tangent line passing through T(a cos(t), b sin(t)) is indeed with the direction vector (a cos(t+pi/2), b sin(t+pi/2)) = (-a sin(t), b cos(t)).
    Sufficiency:
    For any line L, we can always find a tangent line TL parallel to L. Thus the two lines have the same direction vector R but different points P_1 and P_2.
    For TL, we know |R x A|^2 + |R x B|^2 = |R x (P_1 - C)|^2.
    If L satisfy the tangent test, then
    |R x A|^2 + |R x B|^2 = |R x (P_2 - C)|^2.
    Thus |R x (P_1 - C)|^2 = |R x (P_2 - C)|^2,
    |R x (P_1 - C)| = |R x (P_2 - C)|
    R x (P_1 - C) = R x (P_2 - C) (there are exactly two tangent lines out there, that's why there are two cross products with opposite directions, we can choose the one with the same direction)
    R x (P_1 - P_2) = 0
    i.e. (P_1 - P_2) // R, meaning P_1 and P_2 are on the same line. That is, L is actually the same as TL.

  • @lock_ray
    @lock_ray Před 3 lety +26

    After taking a more advanced linear algebra course I came back to this video and actually understood it this time! Thanks for the motivation CodeParade!

  • @R23874
    @R23874 Před 4 lety +2

    Mind is definitely blown. Stumbled upon your channel today and I'm so glad I did, all of your content is incredible. Will be eagerly watching your github as well.

  • @ItsLogic
    @ItsLogic Před 4 lety +414

    Oh my god, He's back.

  • @kikivoorburg
    @kikivoorburg Před 4 lety +16

    Wow this is amazing. Really demonstrates the crazy interconnected nature of mathematics!

  • @Dezomm
    @Dezomm Před 4 lety +1

    I love this channel so much. Gets me excited about all the complex stuff out there I don't know about yet. Really great stuff dude.

  • @XIIJaguar
    @XIIJaguar Před 4 lety +2

    This was great! I enjoyed every second of it. You spent the right amount of time on every point to have me intrigued.

  • @StNick119
    @StNick119 Před 3 lety +16

    I'd love to see more "hardcore maths" videos like this.

  • @TuddYT
    @TuddYT Před 4 lety +3

    I loved this! Please keep making this kind of high quality hardcore math + code content :)

  • @johanrojassoderman5590
    @johanrojassoderman5590 Před 4 lety +1

    Really interesting and thoroughly explained. I'm nowhere close to the mathematical prerequisites but still managed to grasp it thanks to the theoretical and visual explanations. Would definitely not have anything against seeing more hardcore math videos, but i think most of your videos are extremely interesting. Definitely one of the more unique math/coding channels on youtube, and far too underappreciated if you ask me. Keep up the good work!

  • @larrywestenberg7839
    @larrywestenberg7839 Před 4 lety +1

    This was awesome! I don't "do" this sort of math - but you made it completely "followable" for me. What a cool trip that was!! The animations brought the equations to life very well. Bravo, buddy!!

  • @haph2087
    @haph2087 Před 4 lety +4

    Wow. This was lovely. I am not at the point in math to understand all of this, but I understood most of it and learned a lot. Those visuals are amazing too.

  • @orbitalteapot21
    @orbitalteapot21 Před 4 lety +45

    9:00
    The mid points lie on a line is called "Gauss line of a complete quadrilateral". Whose existence in proved in the Gauss Bodenmiller Theorem

    • @Dekross
      @Dekross Před 4 lety

      I only know gauss for the xyz problems :v

    • @Icenri
      @Icenri Před 4 lety +2

      Thanks! I came back to this video looking for this comment. I studied projective geometry but never got to that theorem and in the video it seems so obvious that it has to be connected to the complete quadrilateral and the harmonic conjugate somehow.

  • @MusicEngineeer
    @MusicEngineeer Před 4 lety +1

    it is so satisfying, being faced with a challenging math problem, sitting down for many hours or even days (or more), researching, thinking, finally arriving at a solution, implementing it, testing it - and seeing it WORK ...and then harnessing the so found solution to do all the cool stuff that one wanted to do with it! thanks for the video and the code. should i ever be facing a similar problem, i now know, where to look. yes - i would definitely like to see more videos of this sort.

  • @hyperspaceadventures1416
    @hyperspaceadventures1416 Před 4 lety +2

    I loved this!
    Please make more hardcore math videos! CZcams really needs more beautifully visualized math stuff.

  • @modus_ponens
    @modus_ponens Před 4 lety +9

    Whoah what animations and effects! On top of that using c++.
    Also interesting findings indeed. Enjoyed the math content, particularly the matrix derivation, as it showed quite some many tricks.

  • @martinbrink6711
    @martinbrink6711 Před 3 lety +6

    CZcams desperately needs more hardcore math videos! I'll be looking forward to your next masterpiece!

  • @cboniefbr
    @cboniefbr Před 4 lety

    I love your "usual" contente, but this video was amazing. Looking foward for more of the kind.

  • @lenardvandermaas6893
    @lenardvandermaas6893 Před 2 lety +1

    I love that you made this video! I'm a big fan of implementing math into code and making cool stuff like this (or actually using it in a game or something). I'd love to see more videos like this!

  • @7s1gma
    @7s1gma Před 2 lety +5

    Mind blown confirmed. More hardcore math videos please.

  • @NovaWarrior77
    @NovaWarrior77 Před 4 lety +6

    16:15 yes, more like this if you can please! This was awesome! I'm sure that if you're consistent, you will blow up!

  • @admiralhyperspace0015
    @admiralhyperspace0015 Před 4 lety +1

    Dude, this is awesome. I can't tell you how much ny mind is blown even though I only know about conic sections and don't know the calculations that you did. I want more. I just subscribed for this. I envy that I have don't have the same amount of math and coding knowledge as you.

  • @DrConrad2122
    @DrConrad2122 Před 4 lety +1

    I love this style of video. It really shows just how beautiful math can be. Keep it up!

  • @DeveloperDesmond
    @DeveloperDesmond Před 4 lety +216

    CodeParade! This video is amazing!
    Here's my criticism:
    - When you have variables on screen, like A, B, or R1, it's really hard to keep track of *what* the variable represents. Salman Khan does a really good job in his videos of alleviating this problem in two ways: 1.) He keeps the diagram on screen when doing algebra. 2.) He color codes the variables to the diagram. If x represents a distance, he'll draw the distance in blue, and then use the same color blue whenever he writes x. If you pause your video at 10:34 or 10:25, you'll notice a block of text and a diagram, but no way for the viewer to quickly relate the diagram to the text.
    - You introduced the problem statement at 8:00, which is probably too late. I also don't think you explained the *why* well enough for this problem. 3Blue1Brown's video, "This problem seems hard, then it doesn't, but it really is
    ," is an example of Grant Sanderson's effort to tell an engaging narrative, even when the problem being solved isn't important.

    • @phileiv
      @phileiv Před 3 lety +7

      That's really interesting. I came back to this video after a couple of days because i found it a bit confusing, and i had paused at exactly 10:34.

  • @atimholt
    @atimholt Před 4 lety +7

    A lot of what you’ve shown is *exactly* the math I need for my own project. Thank you!

  • @AngrySkyBandit
    @AngrySkyBandit Před 4 lety +1

    I have been curious about this very question for years. Never took the time to figure it out, and I stumble upon this video on yet another youtube bender. Many thanks for the ride!

  • @AristAristA
    @AristAristA Před 4 lety +1

    having a look into your mind and your experimental math approach was awesome. Very cool video !

  • @eofirdavid
    @eofirdavid Před 4 lety +75

    I think that many of the phenomena that you mentioned follow from the fact that an ellipse is simply the image of a circle under a linear transformation (multiplication by a matrix where you columns are your vectors A and B). I think that your cross product which measures the area is (up to a constant) the determinant of the matrix. When you rotate the vectors, you multiply by a rotation matrix, and since it has determinant 1, and det(XY)=det(X)det(Y), then you know that it should not change the determinant, so the new crossed product should still compute the same area.
    For the |A|^2+|B|^2, this computes the Frobenius norm of a matrix. Unlike the determinant, this norm in general is only submultiplicative, but luckily for us it is multiplicative when you multiply by rotation matrices.

    • @pianojay5146
      @pianojay5146 Před 4 lety +5

      Ofir David cool idea

    • @uganasilverhand
      @uganasilverhand Před 4 lety +2

      I've considered versions of the ellipse formula since high school such as: (x-a)^2/sin^2(theta)+(y-b)^2/cos^2(theta)=r^2 -- no need to calculate eccentricity, it's actually built in now and describes any simple 1 or 2 focii solution as a projection from a spheroid or cone as theta is similarly a projection of the angle from the plane or the "light" source.

    • @lj8324
      @lj8324 Před 3 lety

      Ah yes..

    • @thegamehouse4245
      @thegamehouse4245 Před 3 lety +1

      I totally understand what you mean.

  • @adamschultz7127
    @adamschultz7127 Před 2 lety +4

    "iT tUrNs OuT yOu JuSt InVeRt ThE mAtRiX" like that means anything in the world to anyone but Lawrence fishburn

    • @debblez
      @debblez Před 2 lety +2

      correction: anyone who passed 10th grade

  • @veztron
    @veztron Před 4 lety +1

    this is absolutely fantastic. The visualization are beautiful and everything is so clear

  • @insightfool
    @insightfool Před 4 lety +1

    Thanks for this explanation with such a good visualization. I normally gloss over when watching math videos, but this one was really engaging.

  • @Sciencedoneright
    @Sciencedoneright Před 3 lety +3

    11:17 Even though honestly, I didn't understand the concept, that simplification was *BEAUTIFUL!*

  • @ddiva1973
    @ddiva1973 Před 4 lety +30

    Hard core math is good for the brain, keep going!

  • @death1weller
    @death1weller Před 2 lety

    this is so relaxing to watch. it's like listening to music or a relaxed podcast on another language. I love listening to this while working, so my mind doesn't get distracted by it but can't drift off to unrelated things since it keeps my interest on trying to understand it ksksk

  • @shoveler1238
    @shoveler1238 Před rokem

    Loved this video! Well above my understanding, but everything was really well explained and the visualizations were a great addition.

  • @ChrisDjangoConcerts
    @ChrisDjangoConcerts Před 4 lety +3

    You should do more math videos! These are really awesome !

  • @Tehom1
    @Tehom1 Před 4 lety +11

    Definitely more hardcore math videos if they're going to be this good.

  • @stefanamg63
    @stefanamg63 Před 4 lety +1

    This was stupendously mind-blowing.
    I wish you had made this video 2 years ago when I was writing code which solved a 'tangents between 2 ellipses' problem. I ended up brute-forcing it after struggling for almost a year.

  • @FF-qo6rm
    @FF-qo6rm Před 4 lety +1

    This was great! I would certainly watch if made more videos of this sort!

  • @Magnogen
    @Magnogen Před 4 lety +5

    I'm intrigued to see a collaboration between 3b1b and cp. It would make a cool watch.

  • @DeGandalf
    @DeGandalf Před 4 lety +69

    I have NO idea about this math stuff, but with the nice visuals it was still entertaining; I enjoyed it.

    • @younlok1081
      @younlok1081 Před 4 lety +1

      yes satisfying

    • @fish8622
      @fish8622 Před 4 lety +1

      I understood half of it. So I knew what he was talking about, what he was trying to do, and what he did. I have entirely no clue as to how he did it.

    • @dexstevens5993
      @dexstevens5993 Před 4 lety

      Fish same

  • @MrJammer328
    @MrJammer328 Před 4 lety +1

    This is the first video I’ve see of your channel and wow that was great. Such a great application of linear algebra in geometry

  • @tamimabdullah4638
    @tamimabdullah4638 Před 4 lety +1

    I would love to see more hard core math videos from you. Really appreciate your work. 👏👏👏

  • @Galbex21
    @Galbex21 Před 3 lety +3

    I dont understand almost anythung but its so beautifully represented and edited that its still a pleasure to watch.

  • @sofia.eris.bauhaus
    @sofia.eris.bauhaus Před 4 lety +3

    okay, i understood roughly half of the non-hardcore part an none of the hardcore bit. still learned come cool things in a short time. thanks, will rewatch! B)

  • @lakshita7557
    @lakshita7557 Před 4 lety

    One of the best things I have seen in a while
    Please make more videos of this kind

  • @diegobellani
    @diegobellani Před 4 lety +2

    Oh my god this is flippin' awesome! Now I'm even more interested in linear algebra, please do more hardcore math videos!

  • @Francis-ce1qb
    @Francis-ce1qb Před 3 lety +3

    I have no idea what I’m watching but i still find it interesting listening to it

  • @positivefingers1321
    @positivefingers1321 Před 4 lety +43

    Yay code parade!

  • @Rotem_S
    @Rotem_S Před 4 lety

    This is great! In the past a few mathematicians tried to show me the wonders of projective geometry and I wasn't that thrilled, but seeing some more complex uses without all the annoying rigor is much more interesting (also your plots are a bit better than the whiteboard we had)

  • @desidudes78
    @desidudes78 Před 4 lety +1

    Thanks for the time you spent to make this beautiful video. I enjoyed it

  • @chaimlukasmaier335
    @chaimlukasmaier335 Před 4 lety +4

    I heard a really good lecture series on harmonised coordinate systems this semester...
    So there was not that much new stuff, but you animated it really well.
    For all who speak German, i can recommend "Geometriekalküle" by Jürgen Richter-Gebert

  • @yuryeuceda8590
    @yuryeuceda8590 Před 3 lety +3

    The way it changes from parable to hyperbola is like when a star converts to a black hole. Interesting

  • @flick2040
    @flick2040 Před 4 lety +1

    The animation and motion in this video is so incredibly pleasing.

  • @MinhTran-wn1ri
    @MinhTran-wn1ri Před 4 lety +1

    Refreshing video. The music and visuals were captivating. I wish mathematical concepts were taught this way when I was in grade school -- with visuals, animation, perhaps with code that students can play with. Of course back then, 3B1B wasn't a thing.

  • @Lord_Bon
    @Lord_Bon Před 3 lety +3

    I have no idea of whatever this video was about, but I still want to someday understand it all

  • @joaogabrielneto697
    @joaogabrielneto697 Před 4 lety +13

    I'm a lawyer, why am i seeing this and why its so interesting?

    • @maxwellsequation4887
      @maxwellsequation4887 Před 3 lety

      Too bad for you
      Now you are just a lawyer
      Always remember Fermat, one of the greatest mathematicians ever was a lawyer

  • @atomiccompiler9495
    @atomiccompiler9495 Před 4 lety +2

    I would love to see more mathematical content on this channel.
    Wonderful video by the way.

  • @DavidScherfgen
    @DavidScherfgen Před 4 lety +2

    Great video. Coincidentally, it helped me understand a paper about fitting ellipses to images using gradients at the pixels as tangents. It makes use of the dual conic. The paper was so complicated to understand, but when I saw your video I instantly got it. Great work!

  • @mistycremo9301
    @mistycremo9301 Před 4 lety +5

    I don’t know any linear algebra, but this definitely seems like a cool problem!

  • @caps_lock
    @caps_lock Před 4 lety +25

    5:54 BRUH

  • @tessisaturtle5217
    @tessisaturtle5217 Před rokem

    i'm looking forward to coming back to this video in a few years and actually understanding what he's talking about
    geometry is so cool

  • @tobuslieven
    @tobuslieven Před 2 lety +1

    This is jam packed with mind blowing facts. It just keeps going. Love it.

  • @Menaiya
    @Menaiya Před 3 lety +3

    My brain is fried. This reminded me of a lot of math I've forgotten.

  • @stirrcrazy2704
    @stirrcrazy2704 Před 3 lety +17

    Apparently software engineers also fall into the trope of “engineers can’t do proofs.”

    • @Kittoes0124
      @Kittoes0124 Před 3 lety +3

      Can confirm. One has the ability to implement most algorithms in software; through rigorous experimentation and validation against credible sources. Explaining how any of the maths actually works would be damn near impossible however...
      For example, I wrote all of this: dev.azure.com/byteterrace/CSharp/_git/ByteTerrace.Maths.BitwiseHelpers?path=%2FProject%2FBitwiseHelpers.cs, and yet it still feels like sorcery every time I make a function call! The fact that unit tests pass and pretty results appear on my screen is enough for me.

  • @Scrum-Master
    @Scrum-Master Před 4 lety +2

    Once again, I'm blown away by the quality of your content.

  • @akmalbakar5078
    @akmalbakar5078 Před 4 lety +1

    Loved this! Would love to see more of this type of content

  • @joshuadelacour1106
    @joshuadelacour1106 Před 4 lety +3

    For anyone interested, the "Insights into Mathematics" channel has a few videos covering this and other related concepts. I recommend Cromogeometry.

    • @Icenri
      @Icenri Před 4 lety +1

      Good recommendation!!

  • @pranavlimaye
    @pranavlimaye Před 4 lety +3

    I should probably come back to this video 10 years later because I'm too young to understand anything but this stuff sounds interesting

  • @Concentrum
    @Concentrum Před 3 lety +1

    i'm so glad i found your channel, you are amazing man

  • @DFTricks
    @DFTricks Před 3 lety

    Great stuff, and very well presented! The beauty is in the Pythagorean Theorem applied to ellipses.

  • @leo.maglanoc
    @leo.maglanoc Před 4 lety +4

    more hardcore math videos plsssss

  • @OrangeC7
    @OrangeC7 Před 4 lety +3

    5:40
    Everyone else: *theorem*
    Desargues: Well, you see, I find it more fitting to call it a "converse"

    • @cfgcfh6350
      @cfgcfh6350 Před 4 lety

      Converse is just the inverse of a theorem..

  • @WhattheHectogon
    @WhattheHectogon Před 4 lety +1

    Please, more! This was truly excellent

  • @bobmcbob8044
    @bobmcbob8044 Před 4 lety +2

    Yes, I would definitely like to see some more hardcore maths stuff. It's very interesting, and great how so many patterns arise in unexpected places.

  • @joygodwinwilliamhenry406
    @joygodwinwilliamhenry406 Před 4 lety +3

    How do u get these ridiculously awesome insights though you didn't solve the problem completely these sort of intuitions are really useful to make useful hypotheses which simplifies a really complex problem

  • @TheBcoolGuy
    @TheBcoolGuy Před 4 lety +8

    Me and my passing grades in post-secondary maths: Ah, yes. _Of course!_

  • @nathanielscreativecollecti6392

    I freaking love it. This was beautiful. Thanks for scratching my math itch.

  • @Puddlestomps
    @Puddlestomps Před 4 lety +1

    This is really cool. Would definitely watch more stuff like this!

  • @undefined12
    @undefined12 Před 4 lety +3

    Nice vid. That line with midpoints is called "Euler Line"

    • @maxwelljiang4729
      @maxwelljiang4729 Před 4 lety +1

      no, it the newton-gauss line

    • @philippkusterer9230
      @philippkusterer9230 Před 4 lety

      Not 100% sure, but isnt the euler line the line where almost all centers of a triangles lie?

    • @maxwelljiang4729
      @maxwelljiang4729 Před 4 lety

      yes. the euler line contains the orthocenter, circumcenter, nine-point center, and centroid of a triangle. not to be confused with the newton gauss line, which connects the midpoints of the diagonals of a complete quadrilateral. :)

  • @jucom756
    @jucom756 Před 4 lety +31

    "I'm not 3 blue 1 brown"
    My brain: the f*** yes you are
    Also my brain: oh wait yeah he isn't
    I really thought i was watching a 3blue 1brown video, this could make for a collab

  • @GermanTopGameTV
    @GermanTopGameTV Před 3 lety +1

    This was super satisfying to see. The way the minimum and maximum solutions boil down to a simple minimum on a quadratic equation was just beautiful. This made my headache go away it was so pretty.

  • @santiagocalvo
    @santiagocalvo Před 3 lety

    even tough i didn't understand pretty much anything i loved the video, don't even know why, i struggle enough with simple math when coding and watching this is such an inspiration to keep learning and trying to be better, thnx a lot!!!