If the 5-kg block is suspended from the pulley B and the sag of the cord is d = 0.15 m, determine the force in cord ABC. Neglect the size of the pulley. Get the book: amzn.to/2h3hcFq
I think what through most of us off was that the picture is not symmetrical, the pulley is not in the middle therefore we couldn't use the Pythagorean theorem.
A string ACB of length l carries a small pulley C from which a load W is suspended as shown in Fig. Find the position of equilibrium as defined by the angle a.
I think what through most of us off was that the picture is not symmetrical, the pulley is not in the middle therefore we couldn't use the Pythagorean theorem.
That's what was messing me up
Same here.
A string ACB of length l carries a small pulley C from which a load W is suspended as shown in Fig. Find the position of equilibrium as defined by the angle a.
Such a helpful explanation, thank you!
it does't look like pulley is half way between chord AC
yea it doesn't it must be given
Imagine having a pulley like that on a rope. The natural weight of the pulley will make sure the pulley is in the center
@@abbsquqa6828 thank u brother 🙏
Thank you
Tnx for ur best explanation
Thank you for your help!!
Thank you man!!
Thank you!!
Que libro usas?
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The pulley is not in the center though!
Ya .i think you're right
@@zhakmaldhlk9102 it can only be in the centre as it is on a pulley and there is nothing to hold it to one side the picture may be inaccurate.
thank you