Crane Tipping - Brain Waves.avi
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- čas přidán 27. 08. 2024
- Unfortunately, sometimes cranes tip over. Finding the load required to tip a crane is a basic problem in statics. I show you how to set up and solve a tipping problem along with some pictures of cranes to make the point.
Good place to visit, every time! Thanks!
You're most welcome. I'm glad you like the videos :-)
Continue to share these amazing videos
Very helpful with how to set up tipping point problems. Thank you!
Can you explain please
This video shows how to set up a statics problem of a rigid body tipping over using moments by setting the moment of the rear wheel to zero which signifies the point at which the crane will lift off the ground.
This is the best explanation ever.
Wow, thanks
You made this seem so easy! Thanks for the quiz help
I don't understand English properly but i got solutions and understand it.👍
Very helpful , Thank you for sharing your knowledge with us
If you start adding more ballast you'd bend ether the jib or more likely the outriggers...I stick with the load charts..they' save a lot of time and accidents lol
I may be asking a question that has already been asked but why are we subtracting the forces from the weight and the crane's center of gravity when they are both pointing in the same direction?
even though my English is not that good I will do my best , the reason is because both forces are trying to rotate the crane in opposite directions on the front foot
Neat stuff, its cool how you take your time to go over every aspect of the diagram... however, and I may be jumping the gun here, but for me, doing so seems to over-complicate the problem unnecessarily...
I simply take a look at the diagram and almost visualize a very simple see-saw image... M = F x D... as long as moment on one side equals moment (in opposite direction on other side) are equal... that is the point where equilibrium is maintained, and in the case of Statics here, the tipping point of the crane...
That said, I'm still new to this subject, and am really enjoying your videos, looking forward to seeing what the later topics hold :) Thank you!
impressed clarification
Thanks for putting this together. If the problem showed 4 outriggers instead of 2, to solve a similar problem, would you simplify the problem as how you solved it in this video? Or would you need to build a 3 dimensional free body diagram to compute the unknowns?
Asking this because I'm looking at a problem with 3d diagram depicting all 4 outriggers, but the solution is completed assuming 2 reactions and solved accordingly? I'm curious if that is the way to go with such crane problems. Thanks in advance.
What kind of equation is this. ..like algerba or something..
Dear Sir , thanks for your information . but i have one question at what radius and what angle crane may tipping at 125000 N
where can i see tipping load with counter weight?
Thank you for sharing your knowledge... I is a great help for me which i operate boom truck crane 2.9 tons capacity with out any proper knowledge on it...
Samuel Uykieng i am mobile ciren opeter job in india my name shadab alam
it's very helpful sir thanks for sharing.how to calculate the tipping load when crane rotate by 45 degree angle?
What if crane is lifting from right side or left side than how do i calculate
Thank you again, I found your videos very interesting...
very helpful sir , very grateful
It so useful this video and easy explanation but My question is, why you are not including the crane’s arm weight on the free body diagram ?
I assumed that the arm was light compared to the weight. But, it's not hard to add in the weight of the arm. Just add another downward force at the center of mass of the arm :-)
Crane weight only or with counter weight 500000n ????
Thank you for the video.Like this moment hits in the middle. What i want iswhen outriggers dimensions 4mx2m and bom is at 26,5 degree which is above a outrigger. Like this how can we calculate forces of 4 outriggers? Can you help sir?
how about gravity caused due to crane boom? should we plus it into equation?
I have a rear mount 1996 year 1295 national crane, rear mount I have owned for 10 years, any reason not to "I make" counter weight just for ease of mind. I think 500 lbs. or so. Any thoughts on this. Thank you.
clyde berry fairly bad idea. Could result in possible loss of backward stability. (Most particularly in high boom angle situations, especially with no load.) You would get about the same amount of leverage by simply lifting over the rear. (Engine block, cab etc). It is possible to add counter weight/weights but you must get it approved in writing from the manufacturer.
Thank you very much. This is one of very useful example to learn statics.
Is it possible to solve this problem using virtual work method?
Put extra counterweight, load chart will change and the integrity of the boom will be different too when doing lifting.
you will only get benefits until you reach the structural limit of the boom.
Yes master, agreed.@@NGHmusic
It's very important to us thank you Sir as you share nice information
I'm quite late, but thanks very much :-)
purdueMET welcome
How summation of B gone zero?
havent noticed any consideration about the boom angle
Sir I m very confused to
for example given 15 radius and 4 ton load than after which use crane how to confirm plz give me ansr sir
why not taken the load of arm (boom)?
Great, I like static physics. So much easier than elastic physics.
Join the rigging and lifting group
Could turn the boom degree higher
When you take a moment about ( B ) why neglect the reaction in ( A )
He is determining the weight at which the crane begins to tip over when there are no counterweights at A the crane has to rely on its self weight to carry the load.So the tipping over threshold the force is O there he has to workout the others.In real the the counter weight are there supporting the crane so it can carry much more weight.
Thanks sir
Good job....
Thanks :-)
I dont understand
Thanks!
Informative, but Need to work more on Risk Assessment
This video may encourage an incompetent person to use the tipping capacity as the maximum load not to exceed. Where in reality the crane is already overloaded just before the calculated tipping capacity, I.e,, when the combined CoG of the crane upper and lower works, the boom and load is on the fulcrum point - the outrigger or end of crawler track. Stick to the load chart.
nice
شرح جميل بس ياريت لو كان مترجم
This is for lifting engineer😔
If you put more counterweght more than it can stand...the structure such the slewering table wont last long...but you are damn smart..i wish you are my father😁
❤
Ok
u d best
your lecture is not very clear sir. Its must have somany details. but you didn't
wrong lecture
😩😫🤣😂😭
Sorry, it is totally useless. You never know where is the center of gravity, as it changes with the different angles of the boom. Tho ... nice theoretical exercise. Thank you any way
Actually, there is a chart for the crane that shows cg at different boom angles and positions.
Could you please make a follow up video about the length and angle of the arm? Thanks!
it's very helpful sir thanks for sharing..do you have videos for crane capacity calculation?
so, how do you know that the center of mass is in the middle?
are all cranes designed to have the C.G in the middle?
that's assumed by definition of the problem. IRL you weigh a crane on 3, 4 or more weights and calculate the actual c.g. When designing a crane you decide for yourself where cg should be.
what about the weight of the crane arm? shouldnt this be taken into account?
Question how do you convert the crane boom angle degrees to feet from the center pin/ fulcrum to the boom tip..... I can see it's illustrated in the LMI computer but how does that calculation work if I wanted to measure that
Very Helpful Video for me...Thank you sir
At what degree should the pad be from the hydraulic Jack of the out rigger?
I would think since the Jack is directly on top of the pad the answer would be at 0ﾟ
How to calculate main hook swing impact force towards the boom?
Thank you for your videos they are very helpful but I have a question. Why was the weight "w" multiplied by the distance 16m instead of 24m? (in the moment of b equation)
His Analysis assumes what weight W will cause a tipping, hence FA is zero,the tipping occurs at B (the Fulcrum) and not at A.
thank you for your video !they is very useful to my safety job in site
Greaqt video, Professor French.
I think the mass of the boom should be taken into account.
Hello sir i want to know concept of crane part tie beam , post and geeb i want to know crane structure and slove numerical by lami theorem
When u were drawing your FBD, why did u leave out the hydraulic arm sustaining the boom.
The Hydraulic Arm was left in the FBD because the static analysis presents a conservative case...
I have a 1996 year 1295 national rear mount, I have had for 10 yrs. I would feel safer with " I make" counter weight, any reason not to do this? I am thinking 500 lbs. Any ideas?
Sir, i saw this video carefully, its been very helpful for me but one thing i cant understand properly why you put the value zero of reaction force in point A, what is the reason ?
your kind reply highly appreciated.
Because he wants to find the critical cared weight, so in this case there will be uplift which makes no reaction at the point A.
it is just like putting pen on your finger and trying to keep it save (I hope the example is clear).
What's if the weight is below the ground base of the crane (like if the crane is lifting a boat from the water?) the center of mass moves...
2:41 Letter W has been tipped over!
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