Common chain rule misunderstandings | Derivative rules | AP Calculus AB | Khan Academy
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- čas přidán 27. 08. 2024
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Three common student misconceptions when applying the Chain Rule (from AP team at College Board).
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This channel is the reason i got 98/100 in Basic Calc. Amost all STEM students in my school relies on your videos. Keep it going!
I think 99% of schools may just adopt this program and get more successful in teaching
sir you teach very nicely... thanks for taking lots of efferts
Six minutes in, as I drink some wine, I'm genuinely wondering why the hell I'm required to take Calculus. It has nothing to do with my major, and I seriously doubt anyone uses this stuff other than NASA scientists.
**sigh**
This video is incredibly valuable.
This guy is a legend 🖤
Would this be the same as cot(x) then? If so, why is it left as just (1/sinx)*cosx?
It was probably left unsimplified like that so it wouldn't distract from the main point.
great work. well explained. it is a confusing one.
Am very happy viewing this. Thank you
This helped me so much
I thought the derivative of ln(u) was u'/u so couldn't you use that to get cos(x)/sin(x)?
Yes, that is simply an application of the chain rule.
the king is back !
Thanks!
OK. Perhaps one should mention your result as written are diff. coeffs, without a terminal dx.
Great video
2:47
Why doesnt he just bind some keys to quickly change the colors?
Dont stop keep it up ;)
Who's taking the AP Calculus test in May? :^)
me
@@jensmalzer6344 me
I just googled a picture of Sal Khan, and he's nothing like I imagined him to be. I pictured a generic white man from Texas with short brown hair
I mean his name shouldn’t have lead u to that conclusion but ok
2:45 " we have to take the derivative of outer function with respect to inner function"
Actually that is not true,
The outer function is ln(x), and inner function is sin(x), if what you said were true then it would be d/dx (ln(x)÷sin(x)) which is complicated.
Actually the first part of the answer would be ' derivative of the whole function with respect to the inner function.'
i.e., d/dx (ln(sin(x))÷sin(x)
The outer function is ln(sin(x)), and the inner function is sin(x). So if we take the derivative of the outer function with respect to the inner function, we have d/dsin(x) ln(sin(x)), which is 1/sin(x).
What you have written, d/dx (ln(x)/sin(x)), is not the derivative of the outer function with respect to the inner function; it is the derivative of the quotient of two functions with respect to x. This is not what was said in the video.
Why could this video not have come out last year...RIP me