Statics 6.73 - Determine the reactions at the supports at A, E and B of the compound beam.

Question: Determine the reactions at the supports at A, E and B of the compound beam.
Problem 6-73 from:
Engineering Mechanics: Statics, 14th edition
Russell C. Hibbeler
Thank you guys for watching.
Please let me know if you have any comments or suggestions and also if you have any other problem you would like to go over with.

[@Mostafa.Koriem]

Thank you for this very informative video!

[@alexandersadigursky1240]

why not component for Cy and Dy

[@alondrarivera6153]

Hi, thank you for your videos. I have a question, why do we not include Bx as a reaction? I thought it was a pin. Is it a weightless link then? Thank you in advance!

[@LearningbyTeaching]

Hello, if we look at the figure the at B there is a link attached to it. So similarly to what we did for the link CD, we disconnect this link at B and replacing it with a force that is in the line of action of the link. In this case this link was totally vertical and that's why only By is included.
I hope this clarifies your question!

[@keifalasawie6450]

Good

[@hussain901]

The pin at B is two force member right? Like in CD THAT'S Why you worte the reaction is By

[@holamaful1]

hi, how would you do the shear diagram and bending moment for this exercise?

[@LearningbyTeaching]

Hello Marcel, sadly I will be really busy this last part of Fall2021 semester. But you could guide yourself by one of my shear and bending diagrams videos:
1 - czcams.com/video/elnwOEDfLIk/video.html&ab_channel=LearningbyTeaching
2 - czcams.com/video/l_khO0MLGKQ/video.html&ab_channel=LearningbyTeaching
3 - czcams.com/video/KvpedXCsPh4/video.html&ab_channel=LearningbyTeaching
4 - czcams.com/video/fgJgnMECQzc/video.html&ab_channel=LearningbyTeaching

[@holamaful1]

@@LearningbyTeaching Perfect! Thanks for the help

[@f006]

Why we did not calculate the shear forces for point c?

[@LearningbyTeaching]

Hi, the question did not ask for the forces at point C. :)

[@hussain901]

Hi , isn't point B pin conectd that means there's Bx and By right? So where is Bx
Thanks alot.

[@BG-uf8kh]

no need. there is no horizontal forces

[@bruvocado]

The whole class is currently copying from this

[@lazuli9381]

Too small to see

[@LearningbyTeaching]

Hello, thanks for the comment. I will try to write bigger for following problems!