Your channel turned out to be a game changer for me at so many levels chad. Im indian i learnt English with usa accent from CZcams and i still had some accent when it comes to academic terms , you help me out a lot not just with academics but english too , your channel is one presious one 👍👍👍👍💯💯💯
I am studying med. I haven't touched these Physics and Chem for like 6 years after high school because of COVID and certain conditions. And now I got back to my track, I have tons of difficulties. But, all your videos truly helps me and I really wish I knew this channel back in the days in my high school. You definitely have talents in making things simple and finding out this channel is one of the best things I encountered through out my life. Thank you sincerely for all these explanations. You are my teacher and you have my respect!!
Glad to hear you found the channel and it is helping you - all the best in your educational endeavors. Thank you for the kind words and Happy Studying!
Great video Chad, I like how you built from problem to problem with examples as you did in your Orgo play-list which got me an A, counting on your brilliance again! God bless you. And to anyone watching, this man is the real deal!
Hi chad! for the first two body tension problem why didn't we solve for both tensions(which is tension for 6kg and 4kg) or are they the same at opposite sides, I got total tension at 60, with -24 for 6kg and 84 for 4kg making 60 in total.
The tension in that rope between the 6kg and 4kg weight is the same all along the rope - does that answer your question? I draw that in and explain it at the 10:30 mark - same tension T value, but at the point of attachment to the 4kg block it will point right, and at the point of attachment of the 6kg block it will point left... this is how we actually create tension in a rope: hold two ends and pull in opposite directions. Hope that helps!
In that case we would just have to subtract the force of friction from the tension in the rope (due to the suspended mass) to find the net force on the block. You would need to know either the frictional force itself or the coefficient of kinetic friction for this :)
Your channel turned out to be a game changer for me at so many levels chad. Im indian i learnt English with usa accent from CZcams and i still had some accent when it comes to academic terms , you help me out a lot not just with academics but english too , your channel is one presious one 👍👍👍👍💯💯💯
Thank you - Glad you found us. Happy Studying!
I am studying med. I haven't touched these Physics and Chem for like 6 years after high school because of COVID and certain conditions. And now I got back to my track, I have tons of difficulties. But, all your videos truly helps me and I really wish I knew this channel back in the days in my high school. You definitely have talents in making things simple and finding out this channel is one of the best things I encountered through out my life. Thank you sincerely for all these explanations. You are my teacher and you have my respect!!
Glad to hear you found the channel and it is helping you - all the best in your educational endeavors. Thank you for the kind words and Happy Studying!
Great video Chad, I like how you built from problem to problem with examples as you did in your Orgo play-list which got me an A, counting on your brilliance again! God bless you. And to anyone watching, this man is the real deal!
Thank you very much - glad the channel is helping you so much.
this is amazing teaching. you make physics so interesting and not boring at all.
Glad you think so - Happy Studying!
you're the best Chad! Thank you!
Most welcome and Thank You!
in the first two body pulley problem, why does the g in the mg part not equal 9.8 but just 5g or 10g for instance?
such a great video with great teacher
Thank you x2
Hi chad! for the first two body tension problem why didn't we solve for both tensions(which is tension for 6kg and 4kg) or are they the same at opposite sides, I got total tension at 60, with -24 for 6kg and 84 for 4kg making 60 in total.
The tension in that rope between the 6kg and 4kg weight is the same all along the rope - does that answer your question? I draw that in and explain it at the 10:30 mark - same tension T value, but at the point of attachment to the 4kg block it will point right, and at the point of attachment of the 6kg block it will point left... this is how we actually create tension in a rope: hold two ends and pull in opposite directions. Hope that helps!
For the last problem had friction been applied how would that look? Do uou have anither video to break that down by chance?
In that case we would just have to subtract the force of friction from the tension in the rope (due to the suspended mass) to find the net force on the block. You would need to know either the frictional force itself or the coefficient of kinetic friction for this :)
Do u teach in schools tooo
I used to and miss the face-to-face teaching, but now am doing only online teaching.
Hello, I want your email can I have, please?