@@S3ven4 I know this is a year late lmao. But it was because (1/2, 1, 0) can be scaled to be (1, 2, 0). They're are both the same thing if we are talking about them being in the span. Its just nicer looking to put (1, 2, 0) rather than (1/2, 1, 0).
@@QuickSilver-mp9sv I figured it out but I can't remember what it was anymore. It might've been multiplied by a weight of two but I really can't remember
Understanding eigenvalues and eigenvectors helps visualize how shapes transform under various operations.
Why is one of the vectors in the basis (1,2,0)?
Yeah I came to the comments just to ask this. I think he made a mistake.
@@S3ven4 I know this is a year late lmao. But it was because (1/2, 1, 0) can be scaled to be (1, 2, 0). They're are both the same thing if we are talking about them being in the span. Its just nicer looking to put (1, 2, 0) rather than (1/2, 1, 0).
Can you further explain how you got that basis in the eigenspace example?
Thank you Seth Rogen
Since any vector times the identity matrix is itself; that means that In contains every vector in Rn as an eigenvector for lamba = 1, right?
Thank you Seth Rogen for becoming my math exam it is incredibly appreciated.
good video though some handwriting is not easy to read
14:33 that first vector in the basis is supposed to be [1/2 1 0] right?
@@paulcartie7095 oh I see now, thanks for the clarification
@@S3ven4 Did he make a mistake? Can't see the reply for some reason
@@aimenfaiz99 I have the same question. Did you figure it out?
@@QuickSilver-mp9sv I figured it out but I can't remember what it was anymore. It might've been multiplied by a weight of two but I really can't remember