An intuitive way to think about this, is that there are 2 ropts in the equation, and it's 2 roots exponentially added on top on each other, therefore the whole root woild be a 4th root. To counterract the 4th root, you need to multiply by the 4th power. Since the base is 3, the power has to be 2 to the 4th power, or 16.
Bro, this is not even close to the difficulty of an olympiad problem.
9=3^2=(sqr3^2)^2=sqr3^4 => sqrx=4 x=16
This can be Olympiad bro
An intuitive way to think about this, is that there are 2 ropts in the equation, and it's 2 roots exponentially added on top on each other, therefore the whole root woild be a 4th root. To counterract the 4th root, you need to multiply by the 4th power. Since the base is 3, the power has to be 2 to the 4th power, or 16.
It’s so obviously 16 this is no big deal at all
3^√x/2 = 3^2 √x/2 = 2 √x = 4 x = 16
√x = 4, x= 16
Using ln gives the same answer is it still correct
x=16
Only 2 sec
Impossible
😌😌😌😌😌
@@math77brpossible
@@math77br if sqrt(3)^2 is 3 and 3^2 is 9, then 4^2 is 16 so 16!