Physics, Torque (12 of 13) Static Equilibrium, Ladder Problem
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- čas přidán 10. 01. 2015
- Static Equilibrium, The Ladder Problem; Shows how to use static equilibrium to determine the force of friction between the bottom of the ladder and the ground surface. The sum of the forces in the x-direction, the sum of the forces in the y-direction and the sum of the torque are set equal to zero.
Torque is a rotating force. It is a measure of how much force is acting on an object that causes the object to rotate. The object will rotate about an axis, which is called the pivot point. It is labeled with the letter P or O. The distance from the pivot point to the point where the force acts is called the moment arm or the lever arm. This distance is labeled with the letter r. This distance r is also a vector, and points from the axis of rotation to the point where the force acts. The force is labeled with the letter F.
You can see a listing of all my videos at my website, www.stepbystepscience.com
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wow my physics teacher makes this so much harder than it needs to be
i just watched all 12 of your torque videos and i just want to say thank you so much!!! you help students like me who struggle so much with certain concepts. i feel so much better about my midterm now, thank you for taking the time to make these!
Great, thanks for commenting and I hope the midterm goes well.
i have found in my many college classes that there are 2 types of teachers. teachers like you are the best, they actually want their students to learn and understand. and the other are there to flex their brains so to speak. making thngs way harder than they need to be to appear more impressive.
I appreciate your comment. Thanks very much and best wishes to you.
I was just using this to learn ladder examples before my test on momentum and torque and it’s very helpful.
Great to hear! Thanks for watching
best explanation ever. You helped solved my homework
+Chantel Jose Thanks for the positive comment. You can a listing of all my videos from my website, www.stepbystepscience.com
Thank You Very Much! This was clear, and just what I needed
Thanks so much! I've got my Statics final in about 1.5 hours and this helped a bunch.
Great, hope it goes well!
My goodness... I'm not so good at this critical thinking sometimes, so given this problem to solve even with all of the tools, I wasn't able to "put it together" like a puzzle. Thank you for the succinct walk-through on how to solve these ladder problems
My pleasure, glad to be helpful!
Really clear explanation. thanks a lot!
Thank you my good sir. Really helpful for recapping for my AP physics test
+InfamousReaper Great, hope the test went well. You can see a listing of all my videos at my website, www.stepbystepscience.com
Yep, this was the video that made me understand after watching multiple lectures and other videos. Thanks!
You are welcome and thanks for letting me know.
Thank you Sir for the time and patience to teach us!! So clearly explained! Thank you very much
Thank you so much for the great comment.
That was really awesome...... Keep it....!much appreciate
Great video, dude!
Thank you! Your explanations were really helpful
Anytime, thanks for the comment.
very helpful ! Thank you very much!
Great explanation of the problem, thank you sir!
you are very welcome.
That helped out a lot thanks! The best explanation of this problem I could find online.
@Ben Fox, thanks for the "best" comment, I think they turned out pretty well but they (static equilibrium videos) have not gotten much traffic yet. Tell all your friends.
Will do! I'll be checking out some more later as well.
I finished all my homework but on the quiz I finished so poorly because I couldn't understand which numbers to plug into the equation. At 5:15 you explained the equation perfectly. I love how you use "r * f * sin()" instead of " f*perpendicular and whatever". Both ways work but I'm glad I've learned about the other way
Great that you found the video explanation to be helpful, thanks for the comment!
Thank you for making me understand this concept...
It really helped
Glad to hear that, you're very welcome
Most Excellent!! thank you... great graphics... that's a cool program you're using.... so easy to read and follow...
Thanks for the positive comment. It is not really a program, just Apple Keynote with animations. Works pretty well.
Thanks man, feels bad when you say that's alot to do and my physics department is probably laughing at the prospect of putting a problem so simple to them on the exam.
No problem, thanks for watching.
Thanks bro! With this video I subscribed to your channel! :)
Thanks for subscribing
you made this problem so easy to follow!
Thanks, it is a complicated one.
I appreciate this so much thanks!
You are very welcome. You can see a listing of all my videos at www.stepbystepscience.com
Amazing lesson. I have a physics final in 8 hours and i learned more from your videos than 3 months of lectures. God Bless!!
Hope the final went well, thanks for the great comment!
Great video!
Thanks, glad you liked it!
Thank you Sir you my best lecture ever may God bless
Very nice of you to say....thanks for watching and commenting.
my physics teacher suggested me to watch this really thank u for the brief explanation
You're very welcome! Thanks for watching!
thanks!! i needed it soo much for my pre-medical entrance exam
You're welcome and best of luck!
Thanks for the detailed explanation 🙏😊
My pleasure 😊, thanks for watching
I'll start off by saying thank you so much for these videos! I'm studying physics with the OU alongside my full-time job and having content like this really helps me understand concepts faster than using my textbooks!
A quick question on this though, would there not be a coefficient of friction where the ladder meets the wall? Assuming the ladder is stationary there would be a coefficient of static friction and if the ladder were sliding there would be a coefficient of sliding friction.
We assume there is no friction between the wall and the ladder.
You're the man!!!
Ok, and thanks for the comment.
So in theory, if we solve for the friction force like we do in the video, but also find the magnitude of the normal force in by summing the forces in the y direction, we could find the value of mu correct?
Excellent! Thank you ❤️.
You are welcome!
God bless you Sir!!! Thanks alot for your vidoes
So nice of you, you are most welcome.
TY very well explained.
Thanks. You can also see a listing of all my videos by topic at www.stepbystepscience.com
Super helpful
May the lord reward your hardwork
Thank you so much. Best wishes to you!
Just a query can we take torque from the point on the wall? Btw nice lecture
Thank u for ur clear cut explanation sir...☺️
Most welcome, thanks for watching!
Thank you Sir!!! It's very helpfull
Most welcome!
Outstanding 🎉
Thanks so much!
So good!
Nice, thanks!
do one on momentum
helpful, thank you!
You are very welcome.
I have great thanks for you .keep it up 💯💯💯💯💯 percent
Thank you too!
nice explaination
Thanks and you are very welcome.
clearly understood sir thanq this makes me good marks in my semister
Hope the semester ends well.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank u sir
5.5m is the vertical distance from the pivot, aren't we supposed to use horizontal (perpendicular) distances ??
Thank you sir
Most welcome!
You said that the x distances given are the lever arms, but this doesn’t really make sense to me. With our torque equation where Tp + Tl = Tw, are we not talking about torques acted upon the ladder? Therefore, the ladder should be our lever arm right? However if we treat the x distances as lever arms, this ends up being the torques that the forces produce onto the floor, which doesn’t make sense
Good question, but starting at about 5:00 minutes into the video I explain how we get around the fact that we do not know the lever arm.
How do you decide which point is best to take the torque from?
The pivot point.
Why are we choosing the bottom end of the ladder to calculate the torque ?
Why can't we use the center of mass of the ladder ?
thank you
You are very welcome, You can see a listing of all my videos at my website, www.stepbystepscience.com
How is the lever arm of the force from the wall (Fw) 5.5m when the pivot point is set at the base of the ladder touching the ground?
Hey, actually I think I might have figured it out. When using the formula 'torque= r x F', we substitute the values 'torque= 5.5m x Fw' but if we choose to use the formula 'torque= r x F x sin θ', we substitute the values r= length of ladder, F=Fw , sin θ= sine of angle between the horizontal Fw and ladder or alternatively, sin θ= opposite/hypotenuse= 5.5m/length of ladder, all these into 'torque= r xF x sin θ' and the torques would be the same. Hope this helps!
Thank You!
+Raphael Banoub You are welcome!
You can see a listing of all my videos at my website,www.stepbystepscience.com
Great! They are awesome! Very helpful!
I damn sure appreciate cha!
I love this but I still dont get that Xl and Xp, did u get those Xl and Xp from the question or did u just count them ? Thank you 😭
This is about 2 years too late, but those are given in the question
I love you
BEST
Shouldn't the Ff be (-247N)? It's in the opposite direction.
This dude talks faster than anyone I've ever heard but still is easier to understand than my professor.
Glad it was clear and understandable!
thnk you
You are very welcome, thanks for commenting!
Why aren't the weight forces broken down into components? Aren't they both at angles instead of being perpendicular to the ladder?
because they are acting in the y direction, not between the x and y directions.
Are we assuming that friction between ladder and wall = zero for this example?
Yes, You can see a listing of all my videos at my website, www.stepbystepscience.com
wouldn't there be another up force at the another end of the ladder?
Yeah, if there was only one force then the ladder would be moving to the right.
At 3:39 when you said, “if these forces were to act by themselves, the would cause the ladder to rotate in the counter-clockwise direction” did you mean clockwise?
Those downward forces are clockwise, aren’t they?
Well, i guess that just depends which normal force you get rid of to allow rotation. its only counterclockwise if you get rid of the wall. If yiu getvrid if the ground, it goes clockwise
Its because axis of rotation is at base of ladder
Why FW is directly horizontal ?
The ladder pushes into the wall and the wall pushes back. Newton's 3rd Law. Seems a bit odd but yes the forces are horizontal.
Step-by-Step Science Thanks
❤
Appreciated the video. Btw you sound like a congested Tom Hanks :D
Mmmm i get it now.thks amte
You are very welcome.
very good video but can you talk a bit slower next time
I am always trying to find a balance between too fast and too slow...thanks for watching and commenting.
Excuse me sir! how did you get 1.1m and 1.6m? Is there any formula on how to get them?
THANK U SHAHSJWDJOWJDWJDJW IM SCREAMING
I think that is good, You can see a complete listing of my videos at www.stepbystepscience.com
Ur so fast when teaching but good also
Sorry for that, but thanks for the comment.
Why do u talk so fast I really don't get it especially with how fast u speak
Sorry, but you can try using the pause and replay features.
oops. solved for friction coeffiecient. It's .27
How did you get that?
I reincarnated into this?!?
Awesome.
Thank you sir
My pleasure, thanks for watching