Prove the limit does not exist. Real Analysis Example (2.1)

In this video, we construct a function on domain (0,1) that has a limit at each point in (0,1) except at 1/2. We use the delta-epsilon definition of the limit to prove that the limit does not exist at 1/2.

[@anuj8855]

Thanks a lot sir you clear my very deep doubt 🙏🙏🙏🙏🙏🙏

[@ashenafidejene9512]

great work , it is simple and clear

[@garytiner508]

Thank you for your nice comment!

[@sadececansu9]

Thanks a lot for this clear explanation😇😇😁

[@360mathematics6]

Very nice explanation

[@soheil9255]

That was great . Thanks a lot .

[@TaharProd]

this is awesome

[@TaharProd]

thanks a lot

[@slandrix5240]

One question, how do you know what epsilon to pick? Is it just for convenience?

[@jacobguerreso675]

Same question. Everything else makes perfect sense. Trying understand why epsilon equals greater than |f(x1)-L| wouldn’t work

[@jacobbarats1493]

Pretend that you didn't know it was 1/2 at the beginning. We just need to make the formula work for some epsilon, so at the end when we see that |...| + |...| > 1 when know that one of those terms is greater than 1/2 which we then let be the epsilon

[@jesusdanielmiguelcova2360]

Same question everything else is perfect

[@namupalaaunenyanyukwenindeuten]

❤🔥🔥

[@metalliron8821]

If I have a more complex function, that F(x1) and F(x2)aren't numbers, like "lim x - > 2 of g(x) = { x^(2) if 0

[@adesina1]

Thanks sir

[@TaharProd]

what a goat