The Step Response | Control Systems in Practice
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- čas přidán 6. 06. 2024
- Check out the other videos in this series: • Control Systems in Pra...
This video covers a few interesting things about the step response. We’ll look at what a step response is and some of the ways it can be used to specify design requirements for closed loop control systems.
We will also look at why design requirements like rise time, overshoot, settling time, and steady state error are popular and how they are related to natural frequency and damping ratio for a second order system with no finite zeros.
Check out these other references:
A good overview of the unit step response: bit.ly/3eGbKTG
A mathematical description of the step design requirements: bit.ly/3ezcaev
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How is Brian able to explain these concepts so succintly? Thank you, Sir.
Brian is always here to help. Thank you once again, you are saving many lives.
Brian you did an excellent job explaining the step response. Also thank you for the two links in the description.
a hidden gem, thank you mathworks, and Brian!
❤So helpful! Really brings the concepts around step response together and gives some practical intuition for the math. Thank you!
I was searching the practical connection of system response so long. Really glad to see this amazing video. Thank you very much for connecting theoretical concept with practical example..!!
I see Brian, I click!!
Thanks!
Same. Saw notification on phone, opened PC right away.
@@BiancaDianaT are you an engineer?
@@hunainaghai3342 no, we use Step Response of the system in our Ceramic Art classes
@@BiancaDianaT wow. I didn't know that it's used in ceramic art classes. Do you study mathematics?
Really well explained. Thank you!
Great Brian, there is no one explains control as you do. I wonder what circumstances produced such a product !
Really well explained! Kudos
Thanks Brian. For a second order system, you can find in one of your references (Lecture 21) that you'll introduce overshoot by choosing zeta < 1, which corresponds to having two complex conjugate poles. For zero overshoot, the poles must both be real, with the smallest rise time achieved when they are coinciding (zeta = 1, the critically damped case). What would you derive for the pole locations of a higher order system if zero overshoot (or ultimately, critical damping) was a requirement?
Terrific series, Brian. A criticism on this video--you could have mentioned overdamped conditions if zeta gets too large. Good vs worn out shock absorber analogies work well conveying the idea.
Thank you Uncle Brian. You are the bes.
Another awesome video
bless this man it all makes sense
Brilliant! Huge thank you
This is awesome
Thank you!
great video............hats off Sir...God bless
Wao. Thank you very much!
Thank You
Do you have the same video about frequency requirement?
Amazing as usual, keep talking :))
is it possible to have a improper function as the system ?
Can anybody solve my querry.....stepinfo command give different info and same values from bilevel measurment given diff value of overshoot settling time....why...which should we consider
Sir, how do you plot this one? 13:48
Hello, maybe I’m mistaken. But I think you have the high pass and low pass filters flipped?
I don't see where I did. Could you provide a time stamp and I'll check it out? Thanks!
I mean there could be no one who can dislike this video
doesn't matter nowdays does it
I am a fan! Go eagles!
plot the step response to a 10° ???????? Pls 😢😢😢
I want to explain pid controller