+Carlos Serrano well, when you convert back to decimal, you will always have to add that 1 because when you are converting FROM again FROM Decimal to IEEE 754 binary, you just remove 1.(you only care about fraction) and if you look at 2:20 , he got that number from pink highlight, that was considered a fraction because it is separated from other exponent and sign number... sorry for late response.
how would you go about converting to double precision (64 bits)? would you proceed the same way and just fill in the extra slots in the exponent and mantissa with 0's?
When the number is negative and it is in two's complement, do i have to calculate the absolute value of this number first, or is it ok to put only the 1 at the beginning of ieee754?
So I am assuming the spaces are part of the notation? otherwise 100000 or 1000001 and many other things can be the exponent? edit: nvm, I just realize the exponent have to occupy 8 bits even if its 0000 0000
This video is so simple some steps just doesn't make sense without explanation. Like how did he get 127 for bias? And why the p = 3 isn't brought into the next equations? SMH
You probably figured this out. But in case someone else was confused...consider what .1 means in base 10. It's in the 10^-1 position ( the 1/10th position). 1*(1/10)=1/10=.1 It works the same way in base 2. .1 in base 2 is 1*2^-1=1/2=.5. In base 2, the places to the right of the decimal place are 1/2, 1/4, 1/8, 1/16, ... and so on. .111 in base 2 is, in base 10, 1/2+1/4+1/8=(4+2+1)/8=7/8=.875. Just remember that for all bases, the places of the number are the powers of the base. In base 10, we have ... 10^3, 10^2, 10^1, 10^0, 10^-1, 10^-2, ... ( 1000, 100, 10, 1, 1/10, 1/100). In base 2, we have ...2^3, 2^2, 2^1, 2^0, 2^-1, 2^-2 ( 8, 4, 2, 1, .5, .25).
@@carlosserrano5194 In case you spent last 5 years trying to find answer, here it is. 1, (before the comma) is always there . ,001 (after the comma) is from fraction (bit 0-22)
Josh Oduyoye I think if you get a negative p that means you must shift your point leftwards. Imagine you ave, like in the example, 1.001... (adding that 1, as the uploader said), you would just shift the point to the left, and the result will be 0.1001... That in terms of computers is a non-normalized number, because its integer part is 0...
Whatever you get for the exponent part, you will always use that number to subtract 127 because in 8 bits the highest is 127 since it's from 0 to 127. In this case, if you have 1000|0010 = 128 + 2 = 130. Use 130 - 127 = 3. The idea of 127 is the same as adding a 1 in front of the fraction portion. It'll always be 1.###.... except in this case you will always subtract 127 because that's the highest it goes in 8 bits.
suppose no. given was : 010000000 11000000 0000 0000 0000 0000 then as per my calculations P=1 ..., so in 1.1100000..... i shifted one decimal which gives me 11.100000..... so deciaml representation of (11) is 3 but answer is given 3.5
I know it is too late for you but for new person ... The answer is, to the left of "." you will have 2^-1, 2^-2 ... so you have 11 (equals 3) + 2^-1 (equal 0.5). The final result is 3.5.
1000 0010 = 128 + 2 = 130. Remember that it's in base of 2. That's an 8 bit, so it goes from right to left 2^0, 2^1, 2^2, 2^3, 2^4, 2^5, 2^6, 2^7. Because the first four numbers are 1000, we know that is 2^7 (128). The second 4 numbers are 0010, which we know that is 2^1 (2). Remember that we ignore the 0. Therefore, 128 + 2 = 130
Thanks for explaining in just over 4 minutes what my comp science lecturer failed to do in several hours.
You explain to me in 4 minutes what my professor failed in an hour. Thank you!
Good explanation, but you really should've chosen a better example that has values behind the decimal rather than an integer 9.
+BiN4RY Good example but bad example? xD
+Tim Burkhardt imagine a bad example instead of BiN4RY :D
+Tim Burkhardt I meant to say "good explanation", my bad.
@@timburkhadt you mean good explanation?
@@binexec ohh okay now it makes sense
I don't even know English, but I managed to understand it easily. Congratulations, your way of teaching is fantastic!
Simple, easy, direct, everything I wish my teacher´s classes were
i'm being deadass all of the comments saying you explained in four minutes what my professor tried to in multiple hours is 100% sure. thank you
Thank you! Very helpful. I had trouble understanding this, but your video cleared my mind from the confusion!
ShinyTHPS Helpful Video but I need to know, from where does it come the 1.0010..... ??? ThankYou
+Carlos Serrano well, when you convert back to decimal, you will always have to add that 1 because when you are converting FROM again FROM Decimal to IEEE 754 binary, you just remove 1.(you only care about fraction) and if you look at 2:20 , he got that number from pink highlight, that was considered a fraction because it is separated from other exponent and sign number... sorry for late response.
What could happen in the case of having floating points.. i mean... if the aswer is somthing like -9.35 or -35.25 ????
?? sos!
Excellent explanation. Thank you!! Have an exam in 3 hours :)
IK its been a 7 years but lool:)
did u succeed?
Forget it, I understood now... ThankYou Very helpful
thaaaaaaaaaaaank you so much I spent a lot time on CZcams to understand, finally i understannnd
Hello, please how did you come up with 127 and P as 3? would really appreciate the response. Thank you.
please give us an example using a number that isn't an integer!
Thank you so much. Short and to the point.
Thank you so much. You saved me.
how would you go about converting to double precision (64 bits)? would you proceed the same way and just fill in the extra slots in the exponent and mantissa with 0's?
When the number is negative and it is in two's complement, do i have to calculate the absolute value of this number first, or is it ok to put only the 1 at the beginning of ieee754?
Great video thanks for posting. I have a mid-term today, and its helping with my studies. :-D
Thank you so much, keep it up with the good work :)
damn, Quick and straight. Great tutorial
What does bias mean in this context? How do you know the bias is 127?
yeah I'm wondering the same. Poor explanation.
In 32 bit the bias is 127
Can someone explain to me why it's a 1 in 2:42? I thought it has to be 0 as it's a positive binary number.
What type of round did you use? I've read that IEEE 754 uses 4 types of round. Thanks :)
really nice example. cheers :)
i liked this example. i was confusing. thanks for help me.
Good explaination thanke your f❤
why is the sign positive ?
What if the exponent is 00000000 Would that mean that
exponent = bias + p => 0 = 127 + p => p = -127 ??
What if there are 1s in the significand? We wouldn't just ignore them like we do if the rest were zeros right?
I thought 0 = positive and 1 is negative?
So I am assuming the spaces are part of the notation? otherwise 100000 or 1000001 and many other things can be the exponent? edit: nvm, I just realize the exponent have to occupy 8 bits even if its 0000 0000
Also do you have any video that deal with negative exponent in converting from decimal to IEEE745?
great explanation
Helpful Video but I need to know, from where does it come the 1.0010..... ??? ThankYou
this one is known as a hidden 1 because we hide it when converting from decimal to binary
i got a question the value of the exp. is always 8 no matter what????
thank you very much
This video is so simple some steps just doesn't make sense without explanation. Like how did he get 127 for bias? And why the p = 3 isn't brought into the next equations? SMH
Thank you so munch my brother ♥
what do you do if there are still values after the decimal after moving it??
You probably figured this out. But in case someone else was confused...consider what .1 means in base 10. It's in the 10^-1 position ( the 1/10th position). 1*(1/10)=1/10=.1 It works the same way in base 2. .1 in base 2 is 1*2^-1=1/2=.5. In base 2, the places to the right of the decimal place are 1/2, 1/4, 1/8, 1/16, ... and so on. .111 in base 2 is, in base 10, 1/2+1/4+1/8=(4+2+1)/8=7/8=.875. Just remember that for all bases, the places of the number are the powers of the base. In base 10, we have ... 10^3, 10^2, 10^1, 10^0, 10^-1, 10^-2, ... ( 1000, 100, 10, 1, 1/10, 1/100). In base 2, we have ...2^3, 2^2, 2^1, 2^0, 2^-1, 2^-2 ( 8, 4, 2, 1, .5, .25).
fucking legend. thank you ;)
thank you good explanation awesome
Thank you..very well explained :)
Michael Knox Helpful Video but I need to know, from where does it come the 1.0010..... ??? ThankYou
@@carlosserrano5194
In case you spent last 5 years trying to find answer, here it is.
1, (before the comma) is always there
.
,001 (after the comma) is from fraction (bit 0-22)
thanks a lot, great video
how does 127 + power came?
Where did you get 1.0010.... ?
can you teach my teacher how to teach?
Thank you
I watched the vid a few times and still don't know whats he doing :(
What if the p was a negative number? Like -1 ... How do you solve it then?
Josh Oduyoye I think if you get a negative p that means you must shift your point leftwards. Imagine you ave, like in the example, 1.001... (adding that 1, as the uploader said), you would just shift the point to the left, and the result will be 0.1001... That in terms of computers is a non-normalized number, because its integer part is 0...
+GuitarFrom71 covers! i have hexadecimal i,e 3F 99 99 9A and p is -16 now what?????
how did you get bias = 127?
Whatever you get for the exponent part, you will always use that number to subtract 127 because in 8 bits the highest is 127 since it's from 0 to 127. In this case, if you have 1000|0010 = 128 + 2 = 130. Use 130 - 127 = 3. The idea of 127 is the same as adding a 1 in front of the fraction portion. It'll always be 1.###.... except in this case you will always subtract 127 because that's the highest it goes in 8 bits.
thanks you
Thank you so much
nice work
good job!
thank you sir
suppose no. given was : 010000000 11000000 0000 0000 0000 0000
then as per my calculations P=1 ...,
so in 1.1100000..... i shifted one decimal which gives me
11.100000..... so deciaml representation of (11) is 3
but answer is given 3.5
I know it is too late for you but for new person ... The answer is, to the left of "." you will have 2^-1, 2^-2 ... so you have 11 (equals 3) + 2^-1 (equal 0.5). The final result is 3.5.
why are u adding powers in minus ? and why you add 2^-1 in 3? whats the logic behind it please elaborate
good bless you 😭😭😭😭❤
is this single precision numbers?
yes, which is 32 bits.
if p
+tran khanh then the point goes to the opposite side (left)
tks you =))
how does the exponent go from 128 to 130?
+Debbie Zepeda 1000000 = 2^7 = 128, but the exp is 1000010 which is 128 + 2 (because 10 in binary is equal to 2)
+theorangeiscool1 10000000 = 2^7 = 128
1000 0010 = 128 + 2 = 130.
Remember that it's in base of 2.
That's an 8 bit, so it goes from right to left 2^0, 2^1, 2^2, 2^3, 2^4, 2^5, 2^6, 2^7.
Because the first four numbers are 1000, we know that is 2^7 (128). The second 4 numbers are 0010, which we know that is 2^1 (2). Remember that we ignore the 0.
Therefore, 128 + 2 = 130
how do u convert 1000000000000000011111111111111
thank you
Great explanation
thx man!
Merci ......trés bien
bro come on, wtf is 9.0??????? or cant u calculate 9.057 ? huh
affter doing every thing i got 1010.01 thats 10. ????
10.25
(C1F70000)IEEE754−32bit=(?)10
i dont know how to solve some sample like this yet :(:(
How the hell is "P" = 3?
130-127
@@dotexpress9689 how did you considered the bias as 127 ???
good explanation, but the value you chose is way too easy. in the end i find my self still lost
BIG OLE CHUNK OF CRAP. kudos lol
+Chris G lol, the channel name should be EducationAboutStufforwhatever.
je suis pour votre exlicaction
you sound like ryan reynolds.
White Lisa Harris Charles Lee Helen
wow you are very slow, you sure you understand it ?
Thank you