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1. prefix[a+b*(c-d) ] => +a*b-cd2. prefix[a+b*c/d+e] => ++a/*bcdeThanks for making all this awesome series. Keep doing bhaiya 🔥Bhaiya but maine online prefix calculator se check kiya tha toa alag aa raha tha like Prefix[a+b*c/d+e] : +a+*b/cde ??
Great 👍
same
Prefix [a+b*(c+d)] = *+ab+cdPrefix [a+b*c/d+e] = ++a/*bcdeThank you much bhaiya for such amazing tutorial
Bhut achi tarh se samjha rhe ho bro
Thank u sir for explaining this , I think that it is quite taught but now it is easy for me to understand it ♡
Glad to hear thatPlease, share this channel in your college, groups, or LinkedIn bcoz it's cost nothing to you 😀
1)prefix[a+b*(c-d) ]== +a*b-cd2)prefix[a+b*c/d+e] == ++a/*bcde
Ekdum mast Bhai
Wow you made it simple for me thanks
Thanks buddy 😊Bass share kar dete to ...aacha lagta mujhe v
Same to same answer , very nice Prince bhai
❤❤❤❤❤, I solved but watching in phone
you are the best...........masum.
Thanks a lot please share my channel with your friends
great video!
Thanks!
Thanks bro for making stacks and queue playlist
It's my pleasure
great sir. I appreciate.
Please, share this channel in your college, groups, or LinkedIn bcoz it's cost nothing to you 😀
Done bro ,thank you
Thanks to you brother
thank you sir
bhaiya aapki current ki company kaun si h jisme aap abhi work kr rahe ho
Browserstack
awesooome sir
a+b*c/d+e==>++a/*bcde
Nice 👍
Amazing
nice
Thanks
prefix[a+b*(c-d) ] => +a*b-cd prefix[a+b*c/d+e] => ++a/*bcde
Awesome
Nice video..
Thanks for the visit
prefix of a+b*(c-d)=+a*b-cd
♥️♥️♥️♥️
😍😍
Bhai aaj smjh aya ye ache se college vale haar gye smjha smjha ke hme🤣
HahahPlease, share this channel in your college, groups, or LinkedIn bcoz it's cost nothing to you 😀
Are wahh nice
prefix[a+b*(c-d) ]== +a*b-cdprefix[a+b*c/d+e] == ++a/*bcde
nice work
1. prefix[a+b*(c-d) ] => +a*b-cd
2. prefix[a+b*c/d+e] => ++a/*bcde
Thanks for making all this awesome series. Keep doing bhaiya 🔥
Bhaiya but maine online prefix calculator se check kiya tha toa alag aa raha tha like Prefix[a+b*c/d+e] : +a+*b/cde ??
Great 👍
same
Prefix [a+b*(c+d)] = *+ab+cd
Prefix [a+b*c/d+e] = ++a/*bcde
Thank you much bhaiya for such amazing tutorial
Bhut achi tarh se samjha rhe ho bro
Thank u sir for explaining this , I think that it is quite taught but now it is easy for me to understand it ♡
Glad to hear that
Please, share this channel in your college, groups, or LinkedIn bcoz it's cost nothing to you 😀
1)prefix[a+b*(c-d) ]== +a*b-cd
2)prefix[a+b*c/d+e] == ++a/*bcde
Ekdum mast Bhai
Wow you made it simple for me thanks
Thanks buddy 😊
Bass share kar dete to ...aacha lagta mujhe v
Same to same answer , very nice Prince bhai
❤❤❤❤❤, I solved but watching in phone
you are the best...........masum.
Thanks a lot please share my channel with your friends
great video!
Thanks!
Thanks bro for making stacks and queue playlist
It's my pleasure
great sir. I appreciate.
Please, share this channel in your college, groups, or LinkedIn bcoz it's cost nothing to you 😀
Done bro ,thank you
Thanks to you brother
thank you sir
bhaiya aapki current ki company kaun si h jisme aap abhi work kr rahe ho
Browserstack
awesooome sir
a+b*c/d+e==>++a/*bcde
Nice 👍
Amazing
nice
Thanks
prefix[a+b*(c-d) ] => +a*b-cd
prefix[a+b*c/d+e] => ++a/*bcde
Awesome
Thanks
Nice video..
Thanks for the visit
prefix of a+b*(c-d)=+a*b-cd
nice
♥️♥️♥️♥️
😍😍
Bhai aaj smjh aya ye ache se college vale haar gye smjha smjha ke hme🤣
Hahah
Please, share this channel in your college, groups, or LinkedIn bcoz it's cost nothing to you 😀
❤❤❤❤❤, I solved but watching in phone
Are wahh nice
prefix[a+b*(c-d) ]== +a*b-cd
prefix[a+b*c/d+e] == ++a/*bcde
nice work