What are the Cauchy-Riemann equations? - Complex Analysis

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  • čas přidán 21. 08. 2024
  • We start with the definition of the derivative in complex analysis, and by looking at the real and imaginary parts separately, we deduce the Cauchy-Riemann equations.

Komentáře • 38

  • @dantemlima
    @dantemlima Před 8 dny

    Your excitement with this beatiful piece of math is contagious! Thank you.

  • @dansantner
    @dansantner Před 2 lety +9

    Thanks for explaining this. I've been self studying Complex Analysis using Zill and Shanahan and tripped on this section. Your explanation makes it very simple to understand.

    • @kisonecat
      @kisonecat  Před 2 lety +2

      I'm glad you found the video helpful. Complex analysis is the Disneyland of mathematics, so it is great that you're studying it!

  • @stevengubkin7197
    @stevengubkin7197 Před 2 lety +4

    Hey Jim! I am teaching complex analysis this semester and I am using your phase plotter, so I linked them your video.
    I think you already know my perspective on this stuff, but I will comment here regardless.
    A function f: C --> C has a total derivative which is a real-linear function Df(p): C --> C. When I write that derivative as a matrix with respect to the basis {1,i} we get the regular Jacobian matrix. Saying that a function is complex differentiable is equivalent to saying that the map Df(p) is complex linear, not just real linear. This happens if and only if the Cauchy-Riemann equations hold. Also note that a complex linear map from C --> C is just multiplication by a fixed complex number. This justifies just writing f'(p) as a complex number instead of a linear map.
    Even cooler: the space Lin(C,C) of real-linear maps is a 4 dimensional real vector space (4 real entries in a 2x2 matrix) but it is also (naturally!) a 2 dimensional complex vector space (you can obviously scale a map C --> C by a complex scalar). A natural basis to choose is the identity map and the complex conjugation map (both are real linear). Expressing a real-linear map L:C --> C in this basis breaks it into a complex-linear and a complex-antilinear part. When you apply this decomposition to Df(p) you get (df/dz) dz + (df/zbar) dzbar. The Cauchy-Riemann equations are then equivalent to Df(p) being complex linear, which means the dzbar term vanishing.

  • @bungeruwu
    @bungeruwu Před 2 lety +1

    Thank you! this video helped me so much

    • @kisonecat
      @kisonecat  Před 2 lety

      You're so welcome! I'm glad you liked the animations.

  • @pauselab5569
    @pauselab5569 Před 7 měsíci

    this is amazing, need to learn complex analysis to understand a proof in my book using liouville's theorem.

  • @DissidentReport
    @DissidentReport Před rokem

    This was a wonderful explanation, thank you so much! I just started complex analysis and had a hard time understanding this from the textbook.

    • @kisonecat
      @kisonecat  Před rokem +1

      I'm glad you liked it! complex analysis is so fun.

  • @dmeech7
    @dmeech7 Před 2 lety

    beautiful explanation, gave me some extra clarify in my complex variables class

    • @kisonecat
      @kisonecat  Před 2 lety

      Thanks! I am glad it was helpful.

  • @baconsky1625
    @baconsky1625 Před rokem +1

    Brilliant!

  • @peiopascualhernando2236
    @peiopascualhernando2236 Před 3 lety +4

    dope video

  • @user-yg31415
    @user-yg31415 Před 2 lety

    This is a cool explanation 👍

  • @arielzhang3464
    @arielzhang3464 Před rokem

    very helpful video

    • @kisonecat
      @kisonecat  Před rokem

      thanks -- I'm glad you found it helpful

  • @AG-pm3tc
    @AG-pm3tc Před 2 lety

    thanks my dude, this is great!

  • @alejandrogillo1698
    @alejandrogillo1698 Před 3 lety

    Thank you for this information highly appreciated the effort of explaining the topic 💛

  • @Douglas.Kennedy
    @Douglas.Kennedy Před 3 lety +2

    Is there some intuitive reason for the negative sign in one equation, but not the other? Maybe I should try to think up a simple example to show myself it is true... Great video :)

    • @kisonecat
      @kisonecat  Před 3 lety +1

      Great question. Yes, there's some geometry to do which yields some intuition for this, which basically boils down to the real input and imaginary output being separated by 90 degrees (just like the imaginary input and real output!), but the "sense" is different: in one case, these are clockwise, and in the other, counterclockwise.

  • @amaanhussainbarbhuyan9628

    Awesome 👌

  • @black_jack_meghav
    @black_jack_meghav Před 3 lety +2

    Mark my attendance, Sir!

    • @kisonecat
      @kisonecat  Před 3 lety

      I like the idea of having a roll call in a CZcams video!

  • @hakeemnaa
    @hakeemnaa Před 2 lety

    the conclusion
    the change in i output when you wiggle i input
    = the change in real output when you wiggle real input
    //
    the change in i output when you wiggle real input
    = negative(-) the change in real output when you wiggle i input
    still we need more deep explanation
    better than other videos

  • @baarrijaama
    @baarrijaama Před 3 měsíci

    best lecture, thanks , where find a note book

  • @elizgunduz4515
    @elizgunduz4515 Před 2 lety

    You'ew awesome!

  • @UncoveredTruths
    @UncoveredTruths Před 3 lety

    thanks man!

  • @abinashmuduli7579
    @abinashmuduli7579 Před rokem

    What is the use of this lesson in the day to day life sir!

  • @sucateirodawasteland2228
    @sucateirodawasteland2228 Před 10 měsíci

    Murilo sent me this video.

  • @hakeemnaa
    @hakeemnaa Před 2 lety

    the conclustion

  • @can4757
    @can4757 Před 6 měsíci

    partial

  • @anjipati1680
    @anjipati1680 Před 2 lety

    Put a little English subtitles sir it will help us to understand easily
    its my humble request sir

  • @mohamedelaminenehar333

    We want complex calculus course 😢
    Help please