I think an easier way to solve this question would be: If A quits 10 days before, that means, B works for 10 days which is 1/3rd of the work, and then we take 2/3rd of the work done by A+B to get to ans value 18.
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Hi sir, can't we do the below For 10 days both a and b work together = 10(1/20+1/30) =5/6th of work done. Remaining 1/6th of the work is done by B in 30*1/6 = 5 .total days is 10+5 =15 days. What am I doing wrong here ?
You have interpreted the question wrongly. It says, A quits before 10 days of work being completed, which means B alone has to complete the remaining work for the last 10 days.
Please help me what am i missing here Total works assumed - 600 units A rate - 30 units/day B rate - 20 units/day as per info A+B can do it in 12 days. but A left 10 day before which means that A+B have worked 2 days in which they have completed 100 units. remaining B has to do alone as per his rate it take him 25 days to complete. so total is 25+2 = 27 days. Can you please tell me what I am doing wrong here
Hey Nishant, A+B need not necessarily work for two days. If that is the case, then B alone must complete the remaining work (500 units) in 10 days, which is impossible ( 20*10 = 200 units). So, the best way is equating the amount of work that B has done alone i.e. 10 days. B can do 1/3 of the work (200 units) in 10 days. Therefore, there is 2/3 of the work (400 units) remaining to be done together in x days. Find the value of x. 50*x = 400 x = 400/50 x=8. B worked alone for 10 days + (A+B working together) = 10 + 8 = 18 days Regards, Wizako GMAT Prep.
@@Wizako Why do you have to make things complicated? What do you mean A+B not necessarily worked together? According to the question they have started working together!!!!!! What if they did? Is your answer correct? In which level of your study did you take that kind of doubt ? Nishant is bang on the point. I think he has got the right answer. The level of GMAT math of that nature will never take such kind of doubt. If it is just to boast your knowledge, go ahead but please don't confuse people.
@@blackwarrior7805 I made the same mistake initially and you can refer to 4:20, where you can see Baskar gave special attention to explain this point. I think we can be more appreciative of these tutors putting out their content for free when they don't really have to do so and are just trying to make a living. Cheers
A tough question ! I got it right on my own.
Great job!
I think an easier way to solve this question would be: If A quits 10 days before, that means, B works for 10 days which is 1/3rd of the work, and then we take 2/3rd of the work done by A+B to get to ans value 18.
That's another way to approach the same question. Spot on.
Sir , I have solved this using A+B both worked for (x-10)days together+ B worked for 10days alone which equals to 1.
Spot on Arpan!!
Cheers!
awesome video
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thank you sir
Best wishes for your GMAT prep
I just have one doubt. Why did we took 1 as total work done?
Hi sir, can't we do the below
For 10 days both a and b work together = 10(1/20+1/30) =5/6th of work done. Remaining 1/6th of the work is done by B in 30*1/6 = 5 .total days is 10+5 =15 days. What am I doing wrong here ?
You have interpreted the question wrongly.
It says, A quits before 10 days of work being completed, which means B alone has to complete the remaining work for the last 10 days.
Please help me what am i missing here
Total works assumed - 600 units
A rate - 30 units/day
B rate - 20 units/day
as per info A+B can do it in 12 days. but A left 10 day before which means that A+B have worked 2 days in which they have completed 100 units. remaining B has to do alone as per his rate it take him 25 days to complete.
so total is 25+2 = 27 days.
Can you please tell me what I am doing wrong here
Hey Nishant, A+B need not necessarily work for two days. If that is the case, then B alone must complete the remaining work (500 units) in 10 days, which is impossible ( 20*10 = 200 units). So, the best way is equating the amount of work that B has done alone i.e. 10 days. B can do 1/3 of the work (200 units) in 10 days. Therefore, there is 2/3 of the work (400 units) remaining to be done together in x days. Find the value of x.
50*x = 400
x = 400/50
x=8.
B worked alone for 10 days + (A+B working together) = 10 + 8 = 18 days
Regards,
Wizako GMAT Prep.
@@Wizako Why do you have to make things complicated? What do you mean A+B not necessarily worked together? According to the question they have started working together!!!!!! What if they did? Is your answer correct? In which level of your study did you take that kind of doubt ? Nishant is bang on the point. I think he has got the right answer. The level of GMAT math of that nature will never take such kind of doubt. If it is just to boast your knowledge, go ahead but please don't confuse people.
@@blackwarrior7805 I made the same mistake initially and you can refer to 4:20, where you can see Baskar gave special attention to explain this point. I think we can be more appreciative of these tutors putting out their content for free when they don't really have to do so and are just trying to make a living.
Cheers