Inflection points (algebraic) | AP Calculus AB | Khan Academy
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- čas přidán 25. 07. 2016
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Sal analyzes the points of inflection of g(x)=_x_-4x_+24x_ by looking for values where the second derivative g'' changes signs.
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Why would you have a video on how to find the inflection points, but solve a problem that doesn't have any inflection points?
Yeah, I'm kind of thinking the same thing. Still a good video though.
Exactly, this was the only question he picked and it was a bad one. The Organic Chemistry Tutor is so much better than Khan at teaching calculus and other math heavy problems.
I was going to comment something sarcastic along those lines. I'm getting click-bait from a math video, truly the darkest timeline.
the point of this video was to explain inflection points(Which he did very clearly )
lmao
so, is there a video of you actually solving to find inflection points... OR is there only one video on inflection points that doesnt actually show you how to find the inflection points...?
exactly what i needed.
Thank you so much sir....it helps me👌👌👌🙏
Another requirement of point of inlfection is that the f''(x) (2nd dervitive) has to equal zero along with changing signs (concave up to down or vice versa)
If signs are changing it must be zero at one point... So no need to check that if you find a point where sign changes
Thank you so much!
well explained
Very well explained!
What kind of graphic tablet do you guys use to create these video tutorials?
I want to create video tutorials in my own language, but I don't know what kind of graphic tablet is suitable. I need an affordable one.
very nice handwriting
Perfect video
First, confirm if there are any inflection points with the second derivative factored, solved for x-values of P.O.I, and using an analysis strip to determine the concavity regions.
Next, instead of saying switches signs you could just say when g''(x)=0 (second derivative of original equation factored), you solve for the x values of the inflection point. Then, you sub x-values into the f(x) (original equation) to solve for the y-values of the inflection point. Those two x and y values are your coordinates of the Point of inflection(s).
After watching this video, now I wonder why I attend all those super long online classes
So when you let the first derivative equal to 0 you get the max and min points, and when you let the second derivative equal to 0 you get the point of in inflection. Am I correct? Please correct me if I'm wrong
ninegames yeah I think you’re right
Exactly
No double derivative = 0 doesn't imply that it has inflection pt
But I think when you evaluate the values above 4 or below 4, you should use numbers that are very close to 4 , such as 3.999 or 4.0001
Doesnt matter because you know that in the interval the sign will stay the same.
'They are just for drama'
would you Ever solve for zero on the first derivative?
i put a like just to appreciate the drama😂
Why 0??
You should add more drama to your videos!
The Organic Chemistry Tutor can you please help Khan.
Guys, just go to The Organic Chemistry Tutor, he does a much better job explaining this and uses much better examples.
the one tine khan academy let me down
Any one else wondering what happened to the 16 when solving for zero with the second derivative
?
Makes video on how to determine inflection point but uses a function that doesn’t have an inflection point😢
Great video,I make videos too and will love it if you check it out 🤗
Makes a video about inflection points, solves a problem without inflection points. Still great information but kind of pointless to have this problem as a first exercise.
Maybe it's just me, but you sound like Tom Hanks. Seriously.
this is such a bad explanation. you made it harder when finding out the inflection point.. just use 3 and 5 to check the inflection point why need to use hard numbers for