David Griffiths Electrodynamics | Problem 2.22 Solution

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[@gustavonoe7185]

I like the way you solve the problem. You need a little time to think and it looks very natural. A Hello from Brazil!

[@brandonberisford]

Thank you! I will try to keep this style for my videos. Glad you enjoyed.

[@01agnikmandal36]

❤❤❤❤❤❤❤ from India

[@Xhassan.1]

Love from Pakistan sir. You help us alot to solve these problems.❤️
Thanks 💚

[@Thepeaceout166]

In 2.13 you got E= lambda / (2 pi s epsilon) , why did you multiply it by 2/2?
also, why did you take the limit at a instead of infinity?
Thanks!

[@brandonberisford]

Hey Halle! I honestly can't even remember why I wrote the solution to 2.13 in the different form here haha. Probably just too make the bottom have (4*pi*epsilon) to match coulombs constant. Also the reason the limit is set to "a" and not infinity is because setting the limit to infinity would mean that we'd have the ln(0) for one of our bounds, which is undefined. Therefore I just make the limit "a" which is a very large number, that's not infinity. It's just a dummy limit basically, so that we don't get the undefined in our answer.