All About ESR/EPR Spectroscopy
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- čas přidán 20. 08. 2024
- In this video you will get a quick understanding of EPR/ESR Spectroscopy. Which kind of Questions are asked and How to approach them will be discussed in detail.
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I read many comments and got the confusion which you guys have, in that problem where we did for R3Ge radical why I didn't took Hydrogen attached to carbon and said it will not participate in splitting. Actually it should participate but here we have to neglect it for following reasons:
Firstly it's not mentioned that what R is, is it methyl, ethyl, isopropyl what exactly R is, depending on that you have to take number of H. Since it's not mentioned so you cannot take any number of H here.
Secondly in options you don't have any value more than 10 lines which is our answer after neglecting Hydrogens here, so you cannot have any other option to choose.
Now if it would've mentioned in the question about R, then obviously we will take those Hydrogens in splitting.
I hope it's clear now.
All 'Bout Chemistry OK sir it is now clear ..and also its a smart work to do in exam
All 'Bout Chemistry.. If (R3Ge)2 one option would 've been 20 lines. Could we have marked that coz of two radicles.
Do reply ...Thank you
thank you sir
Thank you
@@shayalone7893 i think both are similar type hence we need to consider one set only
Thank you uploading in English cuz South Indians like us don't know hindi. But most of Indian utubers do video only on hindi. Thank you again
I think you belong to some other planet, thanks a lot sir, Brilliant way of teaching, hats-off
I'll take that as a compliment 😂😂😂
Thanks brother
Thank you so much Sir. Your lectures are in a simple language, elaborative & crisp at the same time giving in depth concept, Very helpful & useful for MSc students like me, especially during this Pandemic time when I can't understand virtual college classes properly. Keep going.
Thank you so much, I'm glad that it helped you 💙
Thanks for the lecture sir. True respect from the bottom of my heart. I got some strength for preparing NET/GATE from this lecture.
Great, wish you all the very best for CSIR Exam
@@AllBoutChemistry Thanks☺️
Thank you so much sir.till now I never couldn't see this much of explanation about ESR Spectra. Once again thank you sir 💐.
You're most welcome 😊
Thankyu so much Sir..and missing you in CZcams..your vedios are osm..plz..keep uploading..😊🙏😊👌
Is Drago's rule applicable for coordination compound? Otherwise how hydrogen of Ammonia participate in splitting?
I am very much thankful to you Noorul Huda Sir and I really do hope that students will get benefit from your videos and it is beneficial for students like me who cannot afford coaching. Thanks for uploading your lectures and I personally request you please make more videos with more examples. Thanks a lot sir. Wish you all the best Sir.
Thank you and God bless you 😊
Thank you so much for the video! the best explanation i have come across
Excellent!!! No words to say how amazing this vedio was.
Thank you so much 😀
Your classes are the best among all sir..keep uploading vedios..really helpful
the video on ESR and MOSSBAUER helps me a lot......thank you very much
Thank you sir
Best explanation
And u clear all dout related to physical chem...
I follow your all videos
Excellent work
Thank you brother 😊
After a long gap back with an excellent video thanq so much sir
Thank you so much brother. I have waited a lot about ESR
why we count H in NH3 radical though N is magnetically active and in the later eg of complex we dont count H?
please read q. carefully
Sir this lecture made my concept very clear bcoz of examples problm, thnku so much, u r the best😊👍👌
Very nyccc..... brilliantly explained 👍
Thank you so much sir for understanding the ESR topic in very easy and concise way. your teaching style is superb sir❤❤.
I have doubt regarding: you say that magnetically inactive means hydrogen participate in splitting ..but last question previous one u did not calculate h value R3 get pls explain
Ya there u didn't took it, and I said that it will not split but actually it will split and if there would be option of more than 10 and it was asked about Number of Hyperfine lines then it will split and Answer would be the one including those hydrogens.
One more reason is that in Organic radicals the splitting caused by Beta Hydrogens is very week, and since Ge is large in size so it makes the Beta Hydrogen move away from it and hence it doesn't causes in splitting.
Thanks. I have posted the same question. I got the answer.
In anthracene 3 different hydrogens are present so overall 75 lines .
And in phenanthrene 5 different hydrogens are present so overall 243 lines 🤗☺️☺️sir thank you much for the explanation 🤗it really helps me a lot . Respect and regards 🙏🙏🙏
You are so good at explaining this. Thank you so much!
In case if Ti(H2O)4(NH3)2 why didn't you take the 2 unpaired electron of Ti in the formula of 2nI+1 itself?
no doubt sir your videos are very helpful i secure JRF 87 in 2018
in which your videos play an important role now i prepare for UPSC geoscientist exam please help us with PYQ of geo scientist chemistry
Have been looking for dis for a long time....👍
Thank you sir. Really ur explanation is in a very simple way. I can understand it easily. Thank you so much
Thank you so much Sir. You made more easy to understand this topic.
You're welcome 😊
Thanku so much sir waiting for more such videos on youtube.keep uploading sir........
Ya sure 👍
I am also waiting sir
Wonderful explanation. Very simple and easy way.
Sir firstly you taught about the concept of magnetically in active whose H will take part in splitting but you applied reverse in (R3Ge)4 complex
Hello.......!!!
Hope these youtube creators create all free content fully availbale for and specific for net chemistry
In the second last ques one confussion is there that why the hydrogens attached to carban is not taken in splitting that in GeR3 EXAMPLE ???????
Pls explain this sir.
I've answered it, plz read my comment.
Very2 ❤❤Thanks to you Sir understand easily Alhamdulillah
Sir if carbon is magnetically inactive than the spliting of hydrogen was nt considered but in next example nitrogen is manetically active stil spliting was nt considered!!! Sir a big confusion plzzz...technically the answer is okay..sir
Yes,i also have doubt on the last question of Ge.....with carbon atomic mass divisible by 4,so why is not H+ not participate in the splitting
Sir in CH2OH radical the hyperfine lines are 3 only why not 6 ? Why a H of OH doesn't split and not shows any line ? Pls kindly elaborate.
Sapna Barad, there are two things hyperfine and superhyperfine lines. Although I don't mentioned about superhyperfine lines coz they're not asked that much in exams. But they will arise when you have more than one magnetically active atoms at alpha and beta positions to the central atom.
Alpha one will give you hyperfine and beta will give super hyperfine lines.
Here H of OH will give superhyperfine lines
Sir I think what you told, will happen if two magnetically inactive nucleas is in alpha and beta position
An awesome way to revise the topic in last minutes thankyou 💛
Yes, finally!! 🙌 Thank you sir.
Brilliant way of teaching.Thank you sir
Egarly waiting for this video :-)
sir kindly make a dedicated video on Mossbauer spectroscopy ...
And actually u deserve more than thanks.... for what u do for us 👍👍👍 (Aastha)
Thank you dear.
nice explanation sir. i also have same doubt but Now Clear with comments. thank you so Much
Thank you so much sir... Your way of explanation is very nice...
Tq u sir nice explanation sir..
Explain the kinetics of octahedral substitution(June 2017 booklet:A, q.no:31) pls explain sir and related questions
❤ really sir you are the best।।।।।।।।।no word ।।।।।
For anthracene 75 esr lines how many esr lines for phenanthrene
243 lines
Very great sir u r doing a great job...we r thankful to u..
Sir your notes very good question also vry good
Good explanation. Thank u 💕 dear
After watching splitting of nh3 radical I tried to predict the spectra of cd2h radical which possess 10 lines but, I am unable to write splitting pattern. Can anyone help me? Thank u
In the last question of the video why the hydrogen present in copper complex attached to ring is not considered?
Sir in H2O you take hydrogen as magnetically active in splitting but in CH3 u do not take hydrogen as magnetically active? ... But in both case O and C are inactive .
BRIJESH KUMAR, I think you're talking about it with respect to that GeR3 question. Ya you're correct H should participate in hyperfine lines. But in option it was not given more than 10 lines, so we neglected the effect of those H
@@AllBoutChemistry ok sir 😊
Your way of teaching is just perfect sir
I had a query in question of germanium atom sould not we take two atoms of germanium although option of 19 is also not given but why is it so sir
Thank you sir for nice explanation.I request you to kindly make a video on how to solve questions for the H2 atom like molecules dissociation energy,ionisation energy related problem..Frequently asked in gate (2016/2018)
Thank you so much sir. Tnx for english.. Northeast😊
Just to understand we come to watch videos in CZcams
But some people take chemistry in their own native languages like Hindi or some other which is not useful
But u take in english and
Videos are pretty good
All the best for more videos
Excellent sir
Thats a huge helpful video thanks
For the example [Ti(H2O)4(NH3)2] there will be cis and trans and you have considered only trans but not cis to calculate the splitting .Why so?
Anthracene=75
Phenanthracene= 243
Thank you Friend very much
Hi from France 🇨🇵
This compound obeys 18 electron rule. How ?This compound is [(Hapticity 5 metal (co) 3] 2. Identify the metal.? Plz reply.
Subhasni Verma is it Mn metal ?
It should be Cr I think, bcoz we have to make M-M bond also. For 1 metal metal bond and rest of the ligands we can have Cr as one of the choice to make it 18e species
Is drago's rule valid for complexes only?
I have a doubt sir, in GeR3 the C is is inactive then the H should be taking part. Why u said that it shouldn't. Because in Ti (H2O)6 the H takes part where oxygen is inactive.
One thing more... Why in NH3 radical the effect of H is also included in hyperfine lines... But acc to drago's rule it shouldn't be included because N is active nuclei.
Tnq so much.,I understood clearly.. Please make more videos..tnq sir
A particular mossbauer nucleus has spin 3/2 and 5/2 in its ground state and excites state respectively. How many lines the gamma ray spectrum will split if the nucleus is under the influence of an external electric field gradient but no magnetic field is applied
Please provide the answer. Thank you.
Sir atomic mass of nitrogen is 14... it is indivisible by4 so it should magnetically active and not participate in splitting cu(nh3)4
U r great sir
In ESR, while analysing ·OH radical using DMPO, I got ·OH signal and extra peaks. What could be the reason for excess peaks other than ·OH spectra?
Anthracene 3 types of protons available no of lines 5*5*3=75 and in phenanthracene 5types of protons are there 3*3*3*3*3=243 lines.
38:01 , how will hydrogens not involve in splitting. According to dragos rule, it is attached to non magnetic nulcei, so it should participate right
Thanks a lot sir.
Sir please make a video on Mossbauer spectroscopy just as like this...as possible as earlier sir ..it's humble request sir....and nice explanation sir
hello sir u said that h connected to magnetically inactive atom like O,C are shows splitting then why u not consider h of alkyl group in the example of R3Ge question
Thank you sir.... Super explaination
Amazing sir tq u soo much i learned more from this vedio
Appreciable❤️
Hello sir,its really wow............Can you upload some concept and related net questions on Mossbauer spectro...?It will be very helpful...
I will do for sure
@@AllBoutChemistry thankyou very much sir...
How far is the effect of hyperfine splitting (upto how many bond distances ) ?
In CH2 (OCH3) you have shown hyperfine splitting upto 3rd bond distance i,e. Splitting by those H's which are not directly attached to oxygen but are attached to next carbon atom. I think this happens only if there is resonance.
Please explain
Also in NH3 example you made triplet of quartets (3 quartets) not quartet of triplets...
As per rule heavier 1st and lighter later ...it should be triplet of quartets as you have done. But
I think terminology is opposite all other things are right.
If i am wrong please correct me...
I appreciate your efforts...one more thing sir...
Then non pascalian triangle you made is not true for every I value other than 1/2 but that one is only applicable to atoms with I=1
For each I value there is different splitting ratio hence different pascalian triangle.
For I=3/2
1st 4 lines are 1:1:1:1 (n=1)
Next 7 lines are in the ratio 1:2:3:4:3:2:1 (n= 2)
For n= 3 there are 10 lines
1:3:6:10:12:12:10:6:3:1
{By adding maximum of four four digits at a time}
I agree with you... about hyperfine lines in CH2(OCH3)...
Nd yes u r ryt tht thr b a different splitting pattern fr different I value...
But fr NH3 the quartet of triplet should be thr...
That's where i have said ..
I have little confusion ..
I take 3 quartets as triplet of quartets ( 3 = triplet)
If it would have been quartet of triplets then it would be 4 triplets..
@@chemistry-basicstoadvanced714
No dear! Firstly the free electron will get coupled with its nearby atom that is N here, so it would split into triplet...then again for hyperfine lines these triplet gets splitted by 3 hydrogens ...i.e. (3+1)..each of the line gets splitted into quartet... Nd it is being called as quartet of triplet....
Thank you so much sir, wonderful one
Thanks a lot sir.....please upload video on inorganic NMR spectroscopy......
Superb sir
Best video
Thank you soooo much sir....
Superb👍👍 ♥️
Thanks a lot sir.now it's very clear.you are great sir.plz upload some problems on mossbaour.plz
Thank you sir.
Sir please make video on mossbaur spectroscopy
OK ill try to make it soon
Ohk
Thank you sir
total no. of fine and hyperfine EPR lines for Octahedral high spin Mn(II) complex. (I Mn = 5/2). Hyperfine lines are 30. how to measure fine lines?
Thank you
Informative videos
For one Ge radical it is 10 lines, since it is two Ge radicals the reaction is giving........ I'm kinda confused with the answer, Sir.
already said that in question on photolysis a radical...if the photolysis is not mentioned in question then your question was right but on photolysis it generates a radical...so we have to look for one radical
Superb
Very nice sir
Wow, thank you so much. Much appreciated
Thnq sr
Super sir...thank you very much sir...
Sir RGe radical in alkyl radical carbon is inactive so hydrogen must take part in splitting then why
A good video. But I am comfused whether H in NH3 radical take part in splitting? how many number of lines will be obtained? In the last problem you discussed, 25 lines came out as answer but somewhere it has given 60 lines as answer, please explain.
Thanks a lot
Tysm Sir!
you just said the exact opposite on the (GeR)2 question. earlier you said H atoms attached to magnetically inactive atoms count for splitting and you gave an example for it [Ti(H2O)6]3+ , it is confusing
Why you didnt take splitting of O in calculating htperfine lines in dragos rule in the Ti complex???please reply ASAP