Solving Modulus Equations and Inequalities
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- čas přidán 28. 11. 2022
- How to solve Modulus inequalities and equations. Also know as solving absolute value inequalities. Modulus inequalities revision questions / handout. Absolute Value Equations. Leaving Cert Maths and a levels.
Overall good explanation but u could've used (a+b)²= a²+b²+2ab
Thank you!!! Finding this every where, the drawing graph part totally answered my question ❤
I'm glad you found it helpful. Yes the sketching clarifies it easier.
It's great but lengthy process!
Thank you...
Im glad it helped
Thankyou sir.. 💌in part 12:17 how did you solve the eqn into (3x+ 7)(x+5) i mean which were the numbers that you considered?
it is factorising quadratics. Please check this video if you need support. Any queries, let me know. czcams.com/video/UekDsivwxYo/video.html
Thank you Sir
no problem - glad you found it helpful
Thank you sir love from Pakistan
Great Tulla Maths is reaching Pakistan
Explanation is good , TNX
I'm glad it helped !
Thank you ❤
you're welcome!
how do you solve inequalities when there is a - or + outside of the abs(x)? e.g abs(x-1)>4-abs(x+1)?
Thank you
you're welcome
thank u from kashmir
Glad to help !
Thxs broo nice explanation tq soo much
no problem at all - glad it helped
Him : Twenty-five
My ears: Turkey-five
Just question cus Im struggling with factoring. Where did you get the 15 (FIFTEEN) to add to (7+5) in the part 12:00 ?
Factorising can always be though. The fifteen is coming from multiplying the 3x by 5 = 15x. Then multiplying the x by 7= 7x. Add 15x and 7x makes the 22x. Perhaps watch this video and it could help better
czcams.com/video/UekDsivwxYo/video.html
Polynomial
that's great sir
very welcome
How do you solve |x-2| = |x| +1? Does anyone have any ideas?
How to draw modular graph in Y = 4 - |2x - 8|
Crispy
taught me faster than my teacher
great that it helped you
It's easy of course but I'm alitle bit confused here (x-2)² ....was it not supposed to be difference of two square?
difference of two squares is when squaring each part separately, such as (x)² -(2)² . Hope this clarifies.
@@tullamaths much appreciation...it's clear now
@@user-ib5fp6hh5r best of luck with your studies
How did get to conclusion of example 1 and 2. In example 1,6 is correct however when you minus 2 from -2 it doesn't give you 4. In example 2 is it not suppose to be -25😢😢. I'm already confused ain't planning to go further 💔
-2 -2 is = -4 modulus of -4 = 4 as per my video. Be careful with your rules of subtraction. Example 2 the answer is x=2 as per video (not -25 as you state).
Your method is too lengthy+complicated... infact the first math you have done is way too lengthy and on the other hand I completed it within 2 lines only.
Please try to make it easy
There are many methods to solving mathematical problems. My tutorial video aims to explain just one of these methods.
I have found out a way
If inequality is in form :
1) |a|≤/≥|b| then square both side snd find the domain.
2) |a|±|b|≥/≤(any constant)
Then use identiy
|Z1|+|Z2|≥|Z1 + Z2|
|Z1|-|Z2|≤|Z1-Z2|
You can't square both sides in inequalities 🤦 because x is a variable it can be a negative value too
You have murdered all the laws in mathematics
sguares are always positive. aise karega iit?
@@atharvsoni5308
-4 < 3✅
Squaring both sides
(-4)² < (3)²
16
In this case you can because both sides are positive, plus |x| = sqrt(Re(x)^2 + Im(x)^2) which is sqrt(x^2) for all real numbers.
Both sides can be squared when both sides of the modulus inequality are absolute values, because -4 < 3, but |-4|>|3|, so both equations can be squared
misleading, make easy to complicate!
Agreed,this isnt hard but overcomplicated for no reason
It's not that hard if u understand polynomial 😌
@@Carrymejane doesn't matter there are easier ways
@@Uchiha...Itachi how? can u suggest?
its three not tree
If you know better maths then y tf u watching this 🤭🤓
If you know better maths then why tf u watching this video ? 🤓
🤓 @@adw8s941
13 minutes of absolute no use
Thank you
You're very welcome