Those who facing doubt regarding remainders theoram u must first watch topic : Chinese remainder theoram from Remainder part 5 ... Available in Number system part
Also if u have doubt on ordered and unordered solution part then u must watch part 4 video of factors ... Available in Number system part ..All doubt will clear !
@@ShreyashPatil1811 if you have time then cover whole number system because there will be things like calculating total number of factor and other things related with it if you have time then definately go with it otherwise leave it if you are running out of time
in the last question zero should come twice because the equations are different as on the positive side we have 6 + 7k and for initial value we will put the value of k as 0. similarly for the negative side the equation is -1 -7k when we put 0 we will get -1. hence the ans is correct 57 solutions.
nope there are two different equations -1-7k and 6+7k so the variable is different.. confusion is only because we have used same variable "k" for both the equations.. for better understanding you can use k1 and k2...
In last question there are 58 solution because - 15+-7=-22, -22+-7=-29.. So there are 29+1=30 in the negative side and 27+1=28 in the positive side... 30+28=58 solutions
The 0 he counted is not the numbers from progression.. its k's value. I.e in the positive side there are 0 to 27 values of k thats satisfies hence altogether 28 values, when k is 0 there the actual value of 'a' is 6 (7k+6 where k is 0) and in the negetive side of the progression when k is 0 the value is -1
i am slightly confused that at 7:45 video sir has said coefficient of y as -7 but as we know linear eqn std format is ax+by+c=0 than y while determining the AP of x variable and y variable sir has done this way ? or is this always reqd. to put the lower coefficient variable at LHS nd other variable and constant to RHS and than determine coefficients values as sir has done and use those as new coeffifient values to determine AP of variables ?? if anyone got this pls help ..thank you.
Both K's are different K's dude. One for the positive side, one for the negative side. You can clearly see that there are 2 different equations of K. So No need to subtract 1.
I am slightly confused about the increase and decrease pattern of solution series of x and y. For example, If I express the equation as 7y = 115 - 3x , does it mean that the solution series of x would be an AP with CD of +7 ? Is sign of the equation a reliable method to decide this or should this be determined by observation (hit and trial)
we generally keep the small coeff variable in the LHS since that variable has c.d of the opp variable which is larger. But the value of both the variable increase and decrease by the C.D on both sides of the number lines just like in the last example, but for negative solutions we just consider the changes to get non negative solutions
Sir has split 'a' series as positive and negative part for making general soln, If u make general soln using '-1' , which is the smallest value of 'a' .....u are involving 0 twice
Sir has split 'a' series as positive and negative part for making general soln, If u make general soln using '-1' , which is the smallest value of 'a' .....u are involving 0 twice
@@shubhamgupta4858 why 4? I mean remainder of 13y will be 3 hence equation will become 3y/5 = 2(remainder of 1002/5) hence y=3 or -2(-ve one) not 4 will satisfy it. Can you explain your answer?
Ya 6 solutions only. Later I have corrected
Sir, when will you upload the rest of the videos?
Sir pls try to complete the progression series. That'll be big help👍
@@zoro3188 its already completed...🦍
@@sarthakagarwal8532 where ??
@@ShwetaDutta1k check algebra playlist
Those who facing doubt regarding remainders theoram u must first watch topic : Chinese remainder theoram from Remainder part 5 ... Available in Number system part
hey can you pls solve 5x+13y =1002 in chinese remainder theorem. Pls I'm not getting the answer
same, y comes 2/3 @@barshasaha1658
bro is it 5 solution or 6
Its 2@@barshasaha1658
@@deringlangthasa63626
Also if u have doubt on ordered and unordered solution part then u must watch part 4 video of factors ... Available in Number system part ..All doubt will clear !
So should i do the whole Number System Chapters first
@@ShreyashPatil1811 if you have time then cover whole number system because there will be things like calculating total number of factor and other things related with it if you have time then definately go with it otherwise leave it if you are running out of time
@@ANONYMOUS-lx6mp Ok Thank you
I think sir there should be 6 instead of 5 when u were talking about the value of x.
yeah it should be 6.
he corrected it laterr
I had the same doubt
Happy teacher's day sir ❤
important: rewatch again
What a beautiful concept sir..
in the last question zero should come twice because the equations are different as on the positive side we have 6 + 7k and for initial value we will put the value of k as 0. similarly for the negative side the equation is -1 -7k when we put 0 we will get -1. hence the ans is correct 57 solutions.
Values of x and y would be solutions and not the values of k. So the answer is 57 only.
how did we get 6k+7
Sir, at 28:20 - Are we double-counting zero? Should the final number of solutions by 28+28=56?
nope there are two different equations -1-7k and 6+7k so the variable is different.. confusion is only because we have used same variable "k" for both the equations.. for better understanding you can use k1 and k2...
Can we take k = -28 to +28 in last question... which gives 57 solutions... ??????
rodha sir always dimmag ke kappat khol dete he 😛
Awesome 👌
In last question there are 58 solution because - 15+-7=-22, -22+-7=-29.. So there are 29+1=30 in the negative side and 27+1=28 in the positive side... 30+28=58 solutions
wrong
57 value hi hoga
Sir in the last question there should be 56 terms becoz you have counted 0 in both the equation i.e both the positive side and negative side
but what about the values such as 1,2 ,3 , 4... and so on?
@@SumitProductions cool reply
The 0 he counted is not the numbers from progression.. its k's value. I.e in the positive side there are 0 to 27 values of k thats satisfies hence altogether 28 values, when k is 0 there the actual value of 'a' is 6 (7k+6 where k is 0) and in the negetive side of the progression when k is 0 the value is -1
Thank you Sir🙏
What will be the process of getting the solution using remainder theorem in Q2? Also, how did you get 7k+6 in last question?
6 is the first term and 7 is the common difference (larger coefficient of variable) hence 6+7k
❤❤❤love it sir
thankyu sir!!!!!!!!!!!!!!!!!!!!😇😇
don't you think there are 6 solutions in question 1?
i am slightly confused that at 7:45 video sir has said coefficient of y as -7 but as we know linear eqn std format is ax+by+c=0 than y while determining the AP of x variable and y variable sir has done this way ? or is this always reqd. to put the lower coefficient variable at LHS nd other variable and constant to RHS and than determine coefficients values as sir has done and use those as new coeffifient values to determine AP of variables ?? if anyone got this pls help ..thank you.
in the last ques k=0 is taken twice , once for positive and once for negative shouldnt we subtract it once then?
Pls answer any one I have same doubt regarding this
Both K's are different K's dude. One for the positive side, one for the negative side. You can clearly see that there are 2 different equations of K. So No need to subtract 1.
@@Rain_Over_Everything you don't even need to take 2 equations just take k positive and negative you'll get 57 including 0
How can we know about k's value that It is 28 or 27
Thanku sir
Thnku sir
I am slightly confused about the increase and decrease pattern of solution series of x and y. For example, If I express the equation as 7y = 115 - 3x , does it mean that the solution series of x would be an AP with CD of +7 ? Is sign of the equation a reliable method to decide this or should this be determined by observation (hit and trial)
Signs can be determined by simple observation.
we generally keep the small coeff variable in the LHS since that variable has c.d of the opp variable which is larger. But the value of both the variable increase and decrease by the C.D on both sides of the number lines just like in the last example, but for negative solutions we just consider the changes to get non negative solutions
i have a doubt , in the last question why didn't you use b =0 for a and directly used 1
same doubt
Because 0 is non negative integer , nd in this question non negative not mentioned
How one divided by 3 remainder is ... Remainder should be -2 right plzzz helpp
3-2 is also 1
watch remanider theorem
Sir how to find at what all cases we should apply remainder theorem and at where we should apply hit and trial method?
When both of the coeffs are bigger use remainder theorem
But for last question, if we solve for b, we get 99 solutions
Counted 0 twice.. 56 soln
ayush misra k=0 depicts 6 in the 1st series and
K=0 depicts -1in the 2nd series
So both k=0 have to be calculated
Sir has split 'a' series as positive and negative part for making general soln,
If u make general soln using '-1' , which is the smallest value of 'a' .....u are involving 0 twice
sir in first question it has 6 solutions and not 5.
last question with remainder method iam getting b=3 and hence a=-5
if he's taking remainder then why he's not cancelling denominator of LHS ?????
🛑🛑In 19:42…the value of x should be 192 instead of 190….as 5x will be equal to 960 instead of 950
can anyone pls solve 5x+13y =1002 in chinese remainder theorem?
Pls I'm not getting the answer
Same problem did you find the ans?
same problem can anyone help
@@Aryanshadev No yaar
5x + 13y / 5 ( lower coefficient)= 1002/ 5
Remainder will be 3y/5= 2/5
When we let y = 4 then we get 3×4/5 = 2 remainder
For better understanding watch remainder video of number system lecture 4&5
In the first question x has 6 solution not 5
What is integral solution idk can you explain
@@minnieplayzz9642 watch raman tiwari sir's algebra playlist on unacedmy CZcams channel it will clear all your doubts
sir whats the ans for real cat question which you changed for the last question
Thankyou sir
in last question ,0 is included twice sir,,,how can it be 57 solns sir,,its 56 solns sir...!!!
how is 0 included twice?
6:06 sir ye method smjh ni aya h
Sir i don't know how to thank you
in last question isn't it , 28 +30?
in the last question how did u get 6 and the equation to be 6K+7 please explain anyone
Bcz First positive value is 6 and rest positive values will be at gap of 7 so equation is 6+7k
@@AbhayBhadoriya2807 how did u know the first positive value is 6?
@@ManasviMehra-rp5ks 1st value we got is -1 and other values will be at 7 distance from it -1+7= 6 , then 6+7= 13 and so on till 200
How 1/3 gives remainder 1😢
1 itself a remainder when divide by any number
how it is 5 solution ? it clearly have 6 solution
Later sir corrected his mistake 15:21
Sir, in which video have you taught the remainder theorem?
Remainders
@@Rodha thanks sir 👍
LAST answer should be 56
yess , i m also getting 56
Sir in the last question you counted 0 twice
Sir has split 'a' series as positive and negative part for making general soln,
If u make general soln using '-1' , which is the smallest value of 'a' .....u are involving 0 twice
Algebra upar se ja raha he
can any one provide me the sol for 5x+13y/5=1002/5 by remainder method
13y/5|R = 2, from here also, at y=4 remainder will be 2, so y=4 satisfies the equation
@@shubhamgupta4858 why 4? I mean remainder of 13y will be 3 hence equation will become 3y/5 = 2(remainder of 1002/5) hence y=3 or -2(-ve one) not 4 will satisfy it. Can you explain your answer?
@@sneha6652 3y/5 = 2 remainder, that means 3×4/5 = 2 remainder