Sir, is there another way to solve this question? Your method, though brilliant, is somewhat idiosyncratic. What I’m implying is that it might take more than two minutes for someone like me to draw such a sophisticated ratio relationship. I tried to solve this question by assigning D=RT equations to A and B individually, and then a D= RT equation to the shrinking gap between A and B. I couldn’t solve it this way, but do you think it was possible to do this question my way?
Sa = 1,25 Sb ( Sa = speed of A and Sb = Speed of B) We assume for D the distance of the race and t the time when both finished the race For A : in t time A travel distance = D For B : in t time B travel distance = D - 7 Time = Distance / speed so we can have the following equation : t = (D-7)/ Sb = D/ Sa = D/ 1,25 Sb , solving this equation we obtain D = 35 m.
Thanks Baskar. I was able to solve the question myself, but was unsure about my answer being correct, because of the wordings of the question.
How many hours is 700 gmat
Hello Chanchal
Approximately 300 hours of prep should get an average test taker 700 plus in the GMAT
Sir, is there another way to solve this question? Your method, though brilliant, is somewhat idiosyncratic. What I’m implying is that it might take more than two minutes for someone like me to draw such a sophisticated ratio relationship. I tried to solve this question by assigning D=RT equations to A and B individually, and then a D= RT equation to the shrinking gap between A and B. I couldn’t solve it this way, but do you think it was possible to do this question my way?
You are right. There must be some other way. This method, though efficient, is a little difficult to think of when looking at the question.
Sa = 1,25 Sb ( Sa = speed of A and Sb = Speed of B)
We assume for D the distance of the race and t the time when both finished the race
For A : in t time A travel distance = D
For B : in t time B travel distance = D - 7
Time = Distance / speed so we can have the following equation :
t = (D-7)/ Sb = D/ Sa = D/ 1,25 Sb , solving this equation we obtain D = 35 m.