He made a mistake for the calculation for the parallel circuit. It's actually 0.125 + 0.125 + 0.5 which eqauls 0.75. Then you do 1 / 0.75 which gives you 1.3
@@marclink0 He had the wrong chart up. The chart he showed was simply to show that when resistors of mixed values are connected in parallel, the total resistance will always be lower than the lowest component.
@@james77011 I thought the wires are ran in a series but each appliance has internal components that bypass the circuit allowing it to be turned off without interruption to circuit
@@jurnagin only in a parallel circuit can one appliance (the load) go out and still have a path for current to flow to the other appliances ( loads) If it was a series circuit and one load goes out, than all of them will go out
The information is valuable but the background music in this video is too loud and unnecessary. The video would have been better without background music at all.
ShavinMcCrotch, Don't know about him, but I'm a CZcams critic and he's right. No need for the stupid goddamn music. What fucking purpose does it serve other than annoyance?
He must have accidentally added 0.125 + 0.125 + 0.25 to get 1/0.5 = 2, I made that mistake in my head when breaking down 1/2 into 1/4 and 1/8, and recalculated my answer to figure out the same. Oops lol.
Thanks for this. I been an electrician for only 4 years, NEVER had to calculate this stuff, but now that I am about to take my J-man test, I HAVE to know this. You made it very easy to understand, thank you!
This is excellent...in physics 2 lab now and we haven't even been taught circuits at all (still on electric fields and force) in lecture...saved my life and grade!
im trying to work out if i connect leds in series parallel but with odd number of leds in series will be the same brightness im using cc drivers each ie 4 series /4 series /4 series /4 series /4 series /9 series /9 series /8 series then each connected in parallel to a 800ma driver for example so each section gets 100ma or do i need equal numbers of leds per series string
Can we get an example of a non-closed loop CCT? For example when R1 & R2 are in series w/ each other but they are also in parallel with R3. Would R1 and R3 be parallel? Or would it just be R1,2 in parallel w/ R3?
For the longest time I have had the hardest time understanding this for a speaker application, and no matter who explained it to me I just could never 100% understand (10-20 yrs) I couldn't figure out what 1 little piece of info I was missing. Looking at from a speaker point makes it hard to learn and what this video did was make me realize that parallel is the one I'm having a problem with. I have noticed under many of these video is that people leaving still still confused and I think I just figured out how to explain it, hopefully through writing. When you showed the 1 single yellow charge going through the parallel circuit 1 resistor at a time, It throws off what is happening. What I never understood was why in parallel does the resistance go down, that made no sense to me. It's not that the resistance goes down, but that the power output from each individual resistor get added together, making the current added together, seem like there was less resistance. 12v@8ohm + 12v@8ohms, both of those powers added together is like having 12v@4ohms + 12v@4ohm, add those powers together and it's like 12v@2ohm. The resistance does NOT go down, it's just that when you add the powers from each resistor together, you get enough power to make it seem like the resistance has gone down. People that do know all about this, does what I said make sense, did I finally figure it out?
As I keep rereading that, yes I guess you can say the resistance goes down, I see where that statement fits, but I think for the hard to understand people, explaining it in the way of the powers being added together, not that the resistance goes down, would help A 1/4" hose + 1/4" hose + 1/4" hose all taped together does not have les resistant, it's just that the gallons per minute added together makes it seems like you have less resistance, therefore; more flow per minute. I don't know if that makes sense but my math matches everyone eles math now, so I'm pretty happy.
Im so confused about this. The tweeter on one of my speakers blew for the 3rd time. I asked the shop where I buy these things what to do and they replied that I need to resistors for each tweeter. The first one is simple enough and makes sense, since it should be in series on the plus wire. But they said that the second resistor should be connected directly to the terminals plus and minus of the tweeter in parallel. Won't it just short-circuit the amplifier if plus and minus is directly connected via a resistor in parallel -- and what's the point? Wouldn't the first resistor in series be enough?
I choose voltage over current. Reducing the need for heavier gauge wires, reducing voltage drops and increased arc stability (for MOTs and custom arc welders; oil cooling recommended). Possibly increasing charge as well. Store bought welders can only be connected or wired in parallel which increases current. That will make you pay the power company more, drain more energy and make very noticeable voltage drops for your neighbors. At least you'll be able to cut metal with electrodes or get DC electrodes working on AC. Side effects of excess current may include a very erratic arc.
If the reciprocal of (1/8)+(1/8)+(1/2) = < 2 ohms, are you rounding 1.33 up to 2? 1/0.75 = 1.33, no? Or am I missing something. I'm taking General physics part 2. Just making sure I'm understanding. Thank you!
1/8 + 1/8 + 1/2 => 1/8 + 1/8 + 4/8 = 6/8 or 0.75 1/(6/8) = 1.33 if you're typing fractions into the calculator you must use parentheses or the calculator will sabotage you
I'm late so I don't think I'll get an answer but it's bugging me how in your circuit diagram that one yellow charge flows from the negative terminal to the positive one, aren't we using conventional current because then that would be wrong.
in series circuit, voltage will be divided across the components of the circuit, and if the leds all have equal resistance then equal voltage will be divided by them.
I thought that the current (amps) never decreases in a circuit. It’s the voltage that decreases with each resister in a series. There is always zero volts at the return, if wired correctly, but the current flow remains the same. (Kirchhoff’s Law)
in this video the single charge is shown to leave the battery at the negative end and travel to the positive end through the series circuit....would that mean that the charge is negative? Following rules on how charges move through an E Field?
How do you get 2 ohms as the total resistance? You don’t really explain it well. I’m new and I’m trying to understand. The formula is 8+8+2.. so wouldn’t that equal 18 ohms? I’m just trying to figure out how this equation equals 2 ohms or how you work the problem out to equal 2 ohms for the parallel circuit example. Thank you
Adding more resistors in parallel is equivalent to providing more branches through which charge can flow. Even though the added branches offer resistance to the flow of charge, the overall resistance decreases due to the fact that there are additional pathways available for charge flow. The fraction of the total charge which encounters a single resistor is now less. The additional branches mean that the circuit can sustain a greater current.
I have a series circuit with 12 bulbs in series. Each bulb has 10.5 ohms resistance. Rt 126 total resistance. I am trying to select a power supply. I can do a 6v or 12v supply. There are multiple amperage options. If I do 6v makes total current 6.85 amp If I add 100ohm resistor before each bulb makes total amps 0.65.
It may but it will still go through the other resistors as well. The electricity is traveling near the speed of light so it does not matter which it goes through first in these examples.
I think you're right. His illustration of electricity flowing made no sense. The electricity would go through the lowest resistance first but also go through the higher resistance at a slower speed. The way he illustrated it made it seem like the electricity only goes through one resistor on each pass through the circuit.
When adding the resistance of a circuit in series, you simply add the resistances. When doing so in parallel you add them 1/R1 + 1/R2 ..etc. you simply put the resistor amount in the formula as stated above instead of adding them straight R1 + R2..etc.. after you put them in that formula, you take the inverse and solve for R(equivalence): 1/R(equivalence) = 1/R1 + 1/R2
@@josphellihsilak4588 thanx it's hard to find ppl who deal with energy, frequency, &vibration...I'm gonna send specs on my grc79 induction motor..(einstein Rosen bridges)...
He made a mistake for the calculation for the parallel circuit.
It's actually 0.125 + 0.125 + 0.5 which eqauls 0.75.
Then you do 1 / 0.75 which gives you 1.3
Lol I was wondering why I didn't understand the parallel circuit answer.
I was confused too. I know the numbers did not look correct.?
Isn't that why the answer he wrote was "
@@marclink0 He had the wrong chart up. The chart he showed was simply to show that when resistors of mixed values are connected in parallel, the total resistance will always be lower than the lowest component.
Thanks!
I found the music to be nice. It added to the mysteriousness since none of us know what we're doing and we're all investigating the solutions.
I found this song in milfy city game ..
Thank you! You taught me in six minutes what I 've had trouble understanding for weeks in my classroom. Keep up the great work!
That's the trouble with school, you get taught the same way regardless of what interests you have or what you want to do in later life.
i hope you forgot this unit
Hi! How are you 5 years later? :)
Thanks, I appreciate your simple to understand style and graphics, I was totally jamming out to this music too good stuff keep it up brother
I didnt mind the background music. I was too focused on how informational and well said it was. Good work
Yeah my college instructor isnt the best and he is so monotone so im just using shorter better explained youtube videos
adhd doesnt help
What I learned from the comments: no one likes background music.
nah I loved it
too loud and unrelated to the content
Reminds me of some game...
Music.. Why? and if you really 'do' need music.. turn it down below the volume of the narrator.. sorry i gave up on it. Wasted opportunity
yup, no background tunes
Thank you for a great introduction into series and parallel circuits.
Damn. That kitchen example really helped me understand. Thanks!
Now I know why my electric bill is so high. I need to rewire my whole kitchen in series !
@@Hapax007 😨 no! Don't do that... If u do that and one element goes out, everything will go out
@@james77011 I thought the wires are ran in a series but each appliance has internal components that bypass the circuit allowing it to be turned off without interruption to circuit
@@jurnagin only in a parallel circuit can one appliance (the load) go out and still have a path for current to flow to the other appliances ( loads)
If it was a series circuit and one load goes out, than all of them will go out
@@Hapax007 1🤣🤣🤣🤣🤣
The information is valuable but the background music in this video is too loud and unnecessary. The video would have been better without background music at all.
Jose M. Pulido w
Who asked for your opinion? What are you, The CZcams Critic?
ShavinMcCrotch he is A CZcams critic
ShavinMcCrotch, Don't know about him, but I'm a CZcams critic and he's right. No need for the stupid goddamn music. What fucking purpose does it serve other than annoyance?
@@da324 Terrible language
I took 2 years of college physics and still couldn't understand this topic until now. Thanks!!
in your scientific calc- 1/(1/8+1/8+1/2)= 1.3^
He must have accidentally added 0.125 + 0.125 + 0.25 to get 1/0.5 = 2, I made that mistake in my head when breaking down 1/2 into 1/4 and 1/8, and recalculated my answer to figure out the same. Oops lol.
I knew it was wrong. I was like how the fuck did he get 2 there?
Ikr, i got so confused.
Seriously wtf when in doubt read the fucking comments
I was like WAIT!!!
1/8+1/8+4/8=6/8
And 8÷6 is not 2
I'm gonna just find another video 😂
Thanks for this. I been an electrician for only 4 years, NEVER had to calculate this stuff, but now that I am about to take my J-man test, I HAVE to know this. You made it very easy to understand, thank you!
jarry Dee that’s why union is superior
Hi
Hello Mr jarry
Boulder the World The Union is great for people that can’t think for themselves. Kind of like liberalism.
I studied for and passed the MECP first class test, and what was needed to pass that test I've literally never used.
This is excellent...in physics 2 lab now and we haven't even been taught circuits at all (still on electric fields and force) in lecture...saved my life and grade!
Best thing I have ever learn in so easy way
Best video to watch to get a basic knowledge on the characteristics and differences of series and parallel circuits.
Using this as last minute studying for an AP test
What grade are you in?
Sameee
Lol samee
@@Omar-wu3nb well I was a senior in high school when I made this comment. 2nd Year 1st Semester off college now.
@@piepienate what do you study?
Can we connect two 23 watt CFL circuits in series or parallel in order to get a 46 watt CFL circuit? If so, then how?
Thank you for clearing up my confusion !!
im trying to work out if i connect leds in series parallel but with odd number of leds in series will be the same brightness im using cc drivers each ie 4 series /4 series /4 series /4 series /4 series /9 series /9 series /8 series then each connected in parallel to a 800ma driver for example so each section gets 100ma or do i need equal numbers of leds per series string
Wasn’t focused on the music because this explanation was seriously so awesome! Thanks, dude!
This video helped a lot thank you for making it!
Love this video it clears all my confusion. Thumps up dude!!!!!!!!
Can we get an example of a non-closed loop CCT? For example when R1 & R2 are in series w/ each other but they are also in parallel with R3. Would R1 and R3 be parallel? Or would it just be R1,2 in parallel w/ R3?
Nice explanation, especially with those visuals.
For the longest time I have had the hardest time understanding this for a speaker application, and no matter who explained it to me I just could never 100% understand (10-20 yrs) I couldn't figure out what 1 little piece of info I was missing. Looking at from a speaker point makes it hard to learn and what this video did was make me realize that parallel is the one I'm having a problem with. I have noticed under many of these video is that people leaving still still confused and I think I just figured out how to explain it, hopefully through writing.
When you showed the 1 single yellow charge going through the parallel circuit 1 resistor at a time, It throws off what is happening. What I never understood was why in parallel does the resistance go down, that made no sense to me. It's not that the resistance goes down, but that the power output from each individual resistor get added together, making the current added together, seem like there was less resistance.
12v@8ohm + 12v@8ohms, both of those powers added together is like having 12v@4ohms + 12v@4ohm, add those powers together and it's like 12v@2ohm.
The resistance does NOT go down, it's just that when you add the powers from each resistor together, you get enough power to make it seem like the resistance has gone down.
People that do know all about this, does what I said make sense, did I finally figure it out?
As I keep rereading that, yes I guess you can say the resistance goes down, I see where that statement fits, but I think for the hard to understand people, explaining it in the way of the powers being added together, not that the resistance goes down, would help
A 1/4" hose + 1/4" hose + 1/4" hose all taped together does not have les resistant, it's just that the gallons per minute added together makes it seems like you have less resistance, therefore; more flow per minute.
I don't know if that makes sense but my math matches everyone eles math now, so I'm pretty happy.
Im so confused about this. The tweeter on one of my speakers blew for the 3rd time. I asked the shop where I buy these things what to do and they replied that I need to resistors for each tweeter. The first one is simple enough and makes sense, since it should be in series on the plus wire. But they said that the second resistor should be connected directly to the terminals plus and minus of the tweeter in parallel. Won't it just short-circuit the amplifier if plus and minus is directly connected via a resistor in parallel -- and what's the point? Wouldn't the first resistor in series be enough?
thx some much man thank god you exist
help i have a taramp 800x4 and 4 size 10" manaces 500 watts 250rms whats better parallel or series
You should have been my high school teacher. I might have understood it more easily back then. Great explanation, very clear. Thanks!
Good video. On a 4 channel motorcycle amp, Can I do 2 4ohms speakers in one channel and 4 speakers on the other?
Thank you! Nice and simply put~ easy to understand
Glad you think so!
My final is due tomorrow and this video helped me out on a question haha thank you so much
Awesome simplified content!
thank you, your video was the one I was looking for. now i know what to do with my lights :)
What about battries connected in series or .. i guess what are the different ways to connect batteries together to change their voltage or a amperage.
I had a great 5 minutes, I understood everything and I jammed on the music
Yay!
short and parallel circuit is similar? A short will usually cause a blow fuse?
Excellent series and parallel cct information
On a dual 1 ohm subwoofer is better to series then parallel or parallel then series to get a final load of 1 ohm?
How did you get 2 ohms as the total for parallel? I used the formula but only got 1.33
THANKS FOR THE VIDEO music kept me from getting bored and it was fantastic
thank you, really helped me understand :)
"I'm uncertain about Jenks' calculation-abilities"
Thanks! Gonna use this example for my reporting in class
If two 60 watts lamps are connected in series and another two 60 watts in parallel then what will be the total watts generated in each circuit?
Are you going explain the "unexpected behaviors," like why adding more resisters decreases the resistance?
Can you make a video in finding the missing voltage and missing resistance 1 of a parallel circuit?
Thank you nice short and straight to the point !!!!!!!
Thanks for the video, it has helped a lot.
that was very good. now it is make since to me . THANK YOU.
I choose voltage over current.
Reducing the need for heavier gauge wires, reducing voltage drops and increased arc stability (for MOTs and custom arc welders; oil cooling recommended). Possibly increasing charge as well.
Store bought welders can only be connected or wired in parallel which increases current. That will make you pay the power company more, drain more energy and make very noticeable voltage drops for your neighbors. At least you'll be able to cut metal with electrodes or get DC electrodes working on AC.
Side effects of excess current may include a very erratic arc.
Thanks for the video, very helpful :)
How do you connect a series and a parallel to each other and attach it to one battery???HELP
Thank you so much tommorow is my science Exam
very very good explanation!
Please tell, why some using series if it is increasing Volts?
If the reciprocal of (1/8)+(1/8)+(1/2) = < 2 ohms, are you rounding 1.33 up to 2? 1/0.75 = 1.33, no? Or am I missing something. I'm taking General physics part 2. Just making sure I'm understanding. Thank you!
+DJ Redmond, I got the same answer as you, did I miss something :/
+Kathryn Emery , curios if you had figure out the >2ohms, I got 1.33 ?
he just said less than 2 (
Can you help me please, 1/8 + 1/8 + 1/2 = 0.5703 how do you get 1.33? Thanks John.... :)
1/8 + 1/8 + 1/2 => 1/8 + 1/8 + 4/8 = 6/8 or 0.75
1/(6/8) = 1.33
if you're typing fractions into the calculator you must use parentheses or the calculator will sabotage you
I'm late so I don't think I'll get an answer but it's bugging me how in your circuit diagram that one yellow charge flows from the negative terminal to the positive one, aren't we using conventional current because then that would be wrong.
Very clear and understandable.
Thanks that cleared my all concepts❤
So what was the answer of the parallel circuit in Ohm's?
That shirt is ironically appropriate. Excellent video!
Thanks!
Thanks a lot dude.
Loved it :)
Groovy tunes man!
THANKS FOR THE PRESENTATION
if i want to connect leds (3.3v) to 220v in series how many leds i need and which resistor i need ??? ( i have 100 leds)
in series circuit, voltage will be divided across the components of the circuit, and if the leds all have equal resistance then equal voltage will be divided by them.
Very good explanation!
very well explained - thanks
makes so much more sense now. going to help my exam a lot
I thought that the current (amps) never decreases in a circuit. It’s the voltage that decreases with each resister in a series. There is always zero volts at the return, if wired correctly, but the current flow remains the same. (Kirchhoff’s Law)
Thanks for the great video
Can anyone help me?
I’m struggling to work out the 1 over 8, 1 over 8, 1 over 2 I type it on the calculator and get 0.75??
If u add more light bulbs to a series circuit will the voltage decrease like the current
Thanks for your help sir.
Thanks man Helped me out
in this video the single charge is shown to leave the battery at the negative end and travel to the positive end through the series circuit....would that mean that the charge is negative? Following rules on how charges move through an E Field?
The charge is an electron - a negative particle.
1:13 why is the charge flowing from negative to positive??? shouldnt it be from positive to negative?
very clear explain thanks mr.London
How do you get 2 ohms as the total resistance? You don’t really explain it well. I’m new and I’m trying to understand. The formula is 8+8+2.. so wouldn’t that equal 18 ohms? I’m just trying to figure out how this equation equals 2 ohms or how you work the problem out to equal 2 ohms for the parallel circuit example.
Thank you
why does the total resistance decrease as we increase the number of resistence in a parallel circuit?
Adding more resistors in parallel is equivalent to providing more branches through which charge can flow. Even though the added branches offer resistance to the flow of charge, the overall resistance decreases due to the fact that there are additional pathways available for charge flow. The fraction of the total charge which encounters a single resistor is now less. The additional branches mean that the circuit can sustain a greater current.
your "kitchen" analogy was very helpful in explaining it! ...now if I could find a Christmas Light set that TRULY stayed lit when one bulb goes out!
They're everywhere. They are LED's connected in parallel. Go to Home Depot.
U literally saved my life, useful and understandable 100% spectacular wish u are my science teacher. Basmalah Adil, 13 years, sudan. My greetings 🌸
Literally saved your life? Miracle cure perhaps?
Great video
What happens to voltage in parallel vs series
remove the music next time. thanks
Thanks. I wanted to know why my L.E.D's lit up with 13.5 volts when connected in series.
probably because it is too much voltage for it... I THINK
I have a series circuit with 12 bulbs in series. Each bulb has 10.5 ohms resistance. Rt 126 total resistance.
I am trying to select a power supply. I can do a 6v or 12v supply. There are multiple amperage options.
If I do 6v makes total current 6.85 amp
If I add 100ohm resistor before each bulb makes total amps 0.65.
Question.. current takes path of least resistance?? So wouldn’t your parallel example go through 2 ohm resistor first?
It may but it will still go through the other resistors as well. The electricity is traveling near the speed of light so it does not matter which it goes through first in these examples.
I think you're right. His illustration of electricity flowing made no sense. The electricity would go through the lowest resistance first but also go through the higher resistance at a slower speed. The way he illustrated it made it seem like the electricity only goes through one resistor on each pass through the circuit.
But doesn't the electron pass through all of the resistors in a wave function according to the rules of quantum mechanics?
What if you ground out some how in a series
In seriers, why wouldn't a lightbulb explode if in line with a refrigerator? Wouldn't all the power of the fridge need to pass through the bulb?
Very helpful and straight to the point but the alien soundtrack was not necessary
i dont get the explanation for the calculating the total resistance in a parallel circuit
When adding the resistance of a circuit in series, you simply add the resistances. When doing so in parallel you add them 1/R1 + 1/R2 ..etc. you simply put the resistor amount in the formula as stated above instead of adding them straight R1 + R2..etc.. after you put them in that formula, you take the inverse and solve for R(equivalence):
1/R(equivalence) = 1/R1 + 1/R2
@@josphellihsilak4588 ok will you help me with my time transducing capacitor w/ built in temporal displacement???ty so much..🤫🕢🚀
@@bernardoprovenzanno9487 yea sure, send me your work and I'll help you out.
@@josphellihsilak4588 thanx it's hard to find ppl who deal with energy, frequency, &vibration...I'm gonna send specs on my grc79 induction motor..(einstein Rosen bridges)...
Thank you sir Chavez
Thank you!!
How much diode, resistor and capacitor are used.. send me a small circuit borad
Thank you so much
Very Helpful Video Thancks
learning even more from these comments lol
Great video wow nice