Wrong answer, the son's age should be 14. We know now the father's age plus the son's age is 60 so F+S=60. We also know that 6 years ago the father's age was 5 times the son's age. So for 6 years ago F-6+S-6=60 which gives F+S-12=60 so F+S=48. With the father's age being 5 times the son's age F=5S, that gives 5S+S=48 so 6S=48 which means S=48/6=8. That means that now the son is 8+6=14 years old and the father is 5x8+6=46 years old. Check in F+S=60 to see if this is correct: 46+14=60. We can also calculate the age of the father when his son was born: 46-14=32 years old. With that we can calculate when the father will be twice the son's age. When the father is twice his son's age F=2S. The father is 32 years older than his son so F=S+32. Put the two together to get S+32=2S and simplify to 32=S. The son will be 32 years old in 32-14=18 years and in 18 years the father will be 46+18=64 years old. We can check with F=2S to see if this is correct: 64=2x32. Using the same method we can calculate when the father will be 3 times as old as his son. F=3S and F=S+32 so 3S=S+32 which gives 2S=32 and S=32/2=16. So in 16-14=2 years the father will be 46+2=48 which is 3 times the age of his son.
It's the right answer. NOW, the son's age is 14, but in 6 years the son will be 20 years old. You should read correctly. She explained in detail the present age, the age six years ago and the age in 6 years.
When you watch the video completely, you will see she calculated the age correctly. It's said that the present age is 14 and the age in 6 years will be 20.
The best and precise solution. Thanks for this
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Wrong answer, the son's age should be 14.
We know now the father's age plus the son's age is 60 so F+S=60. We also know that 6 years ago the father's age was 5 times the son's age. So for 6 years ago F-6+S-6=60 which gives F+S-12=60 so F+S=48. With the father's age being 5 times the son's age F=5S, that gives 5S+S=48 so 6S=48 which means S=48/6=8. That means that now the son is 8+6=14 years old and the father is 5x8+6=46 years old. Check in F+S=60 to see if this is correct: 46+14=60.
We can also calculate the age of the father when his son was born: 46-14=32 years old. With that we can calculate when the father will be twice the son's age. When the father is twice his son's age F=2S. The father is 32 years older than his son so F=S+32. Put the two together to get S+32=2S and simplify to 32=S. The son will be 32 years old in 32-14=18 years and in 18 years the father will be 46+18=64 years old. We can check with F=2S to see if this is correct: 64=2x32.
Using the same method we can calculate when the father will be 3 times as old as his son. F=3S and F=S+32 so 3S=S+32 which gives 2S=32 and S=32/2=16. So in 16-14=2 years the father will be 46+2=48 which is 3 times the age of his son.
It's the right answer. NOW, the son's age is 14, but in 6 years the son will be 20 years old.
You should read correctly. She explained in detail the present age, the age six years ago and the age in 6 years.
What pen are you using? Just curious? And which notepad?
Good morning
Very good morning yasir😊
So your Lachers solo
The present age of son should be 14 not 20.
The question told you to find the age of the son after 6 years.
When you watch the video completely, you will see she calculated the age correctly. It's said that the present age is 14 and the age in 6 years will be 20.
Hii
( )+ ( )=14
( )- ( )=16